For starters instead of this call of printf

printf("Hello, World!\n");

you could use a call of puts like

puts( "Hello, World!" );

The string literal "Hello, World!\n" internally is represented as a character array like

char string_literal[] = 
{ 
    'H', 'e', 'l', 'l', 'o', ',', ' ', 'W', 'o', 'r', 'l', 'd', '!', '\n', '\0' 
};

Arrays used in expressions are implicitly converted (with rare exceptions) to pointers to their first elements.

So in this call

printf("Hello, World!\n");

the character array used as an argument of the function call is converted to pointer of the type char * to its first element 'H'. You can imagine that the following way

printf( &"Hello, World!\n"[0] );

Thus the function deals with a pointer of the type char *. You could do the same by introducing an intermediate variable

char *s = "Hello, World!\n";
printf( s );

or

char *s = "Hello, World!\n";
printf( "%s", s );

or

char *s = "Hello, World!";
printf( "%s\n", s );

or

char *s = "Hello, World!";
puts( s );