How to break out of while loop in Python? - Stack Overflow
how to stop the while loop
Ending While True Loop
python - How can I stop a While loop? - Stack Overflow
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A couple of changes mean that only an R or r will roll. Any other character will quit
import random
while True:
print('Your score so far is {}.'.format(myScore))
print("Would you like to roll or quit?")
ans = input("Roll...")
if ans.lower() == 'r':
R = np.random.randint(1, 8)
print("You rolled a {}.".format(R))
myScore = R + myScore
else:
print("Now I'll see if I can break your score...")
break
I would run the loop until ans is 'Q' like this:
ans = 'R'
while not ans == 'Q':
print('Your score is so far ' + str(myScore) + '.')
print("Would you like to roll or quit?")
ans = input("Roll...")
if ans == 'R':
R = random.randint(1, 8)
print("You rolled a " + str(R) + ".")
myScore = R + myScore
I'm doing a CS50p project on making a grocery list. The only issue I'm having is once the list prints, I need the program to end. No matter where I break, it either doesn't stop the program or does stop it but bugs something else.
This is what I have:
def main():
list = []
while True:
try:
item = input()
list.insert(0, item)
continue
except EOFError:
list.sort()
while list != None:
for word in list:
x = list.count(word)
if x != 0:
print(str(x) + " " + str.upper(word), sep=" ")
list = [i for i in list if i!=word]
else:
break
breakmain()
just indent your code correctly:
def determine_period(universe_array):
period=0
tmp=universe_array
while True:
tmp=apply_rules(tmp)#aplly_rules is a another function
period+=1
if numpy.array_equal(tmp,universe_array) is True:
return period
if period>12: #i wrote this line to stop it..but seems its doesnt work....help..
return 0
else:
return period
You need to understand that the break statement in your example will exit the infinite loop you've created with while True. So when the break condition is True, the program will quit the infinite loop and continue to the next indented block. Since there is no following block in your code, the function ends and don't return anything. So I've fixed your code by replacing the break statement by a return statement.
Following your idea to use an infinite loop, this is the best way to write it:
def determine_period(universe_array):
period=0
tmp=universe_array
while True:
tmp=apply_rules(tmp)#aplly_rules is a another function
period+=1
if numpy.array_equal(tmp,universe_array) is True:
break
if period>12: #i wrote this line to stop it..but seems its doesnt work....help..
period = 0
break
return period
def determine_period(universe_array):
period=0
tmp=universe_array
while period<12:
tmp=apply_rules(tmp)#aplly_rules is a another function
if numpy.array_equal(tmp,universe_array) is True:
break
period+=1
return period
I have a long while loop, it has a lot of code in it and a lot of delays.
I want to break out of the loop when a condition is met but I need to break out of it instantly. The only thing I can think of, is to print if statements constantly through the loop, checking if the condition is true, but this seems a little silly because it would have literally 100s of break statements.
Is there any better way to do this without typing break statements after every single line of code, that seems impractical because there's 100s of lines of code in the while loop, it takes around 10 minutes to finish and I need it to break instantly
You could always use a function and return from it:
import logging
def func():
for i, x in enumerate(x):
logging.info("Processing `x` n.%s...", i)
y = do_something(x)
if y == A:
logging.info("Doing something else...")
do_something_else(x)
elif y == B:
logging.info("Done.")
return # Exit the function and stop the loop in the process.
func()
Although using break is more elegant in my opinion because it makes your intent clearer.
You could use a boolean value to check if you are done. It will still iterate the rest of the loop but not execute the code. When it is done it will continue on its way without a break. Example Pseudo code below.
doneLogging = False
for i, x in enumerate(x):
if not doneLogging:
logging.info("Processing `x` n.%s...", i)
y = do_something(x)
if y == A:
logging.info("Doing something else...")
do_something_else(x)
elif y == B:
logging.info("Done.")
doneLogging = True