You are trying to map clubs to two separate arrays (each containing a single object), rather than a single array with two objects.

json_clubs = {
    "clubs": [
        {
            "Oak Club": {
                    "members": [
                        "Charles",
                        "Nora",
                        "Tom",
                        "Paul"
                        ]
                    }
        },
        {
            "Bravo Club": {
                "members": [
                    "Nathaniel",
                    "Roselyn",
                    "Ash"
                    ]
                }
        }
    ]
}
Answer from chepner on Stack Overflow
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JSONLint
jsonlint.com › json-syntax-error
JSON Syntax Error: How to Find and Fix It | JSONLint
Unlike some formats that are forgiving, JSON requires exact syntax—a single misplaced character will cause the entire document to fail parsing. This guide will help you quickly identify what's wrong and fix it. The fastest way to find a syntax error is to paste your JSON into the JSON Validator.
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Bubble
forum.bubble.io › need help
JSON Syntax Error - Need help - Bubble Forum
February 23, 2024 - Hello, I’m trying to create a JSON and send it via an API to XANO, but keep receiving the error message: “Error parsing JSON: Syntax error”} After trying a lot of different things, I found a way to “fix” the problem. I added the JSON to a Custom State, which populates an Input.
Discussions

php - json_decode syntax error from valid json - Stack Overflow
When I pass it to json_decode($json, true), the result is NULL and json_last_error() give me 4 (JSON_ERROR_SYNTAX) More on stackoverflow.com
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SyntaxError: JSON.parse: unexpected character at line 1 column 1 of the JSON data
For the benefit of searchers looking to solve a similar problem, you can get a similar error if your input is an empty string. ... In chrome it resulted in 'Uncaught SyntaxError: Unexpected end of input', but Firebug showed it as 'JSON.parse: unexpected end of data at line 1 column 1 of the ... More on stackoverflow.com
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php - json_decode returns JSON_ERROR_SYNTAX but online formatter says the JSON is OK - Stack Overflow
I have the same problem, receiving JSON_ERROR_CTRL_CHAR and JSON_ERROR_SYNTAX. More on stackoverflow.com
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Help! JSON Syntax Error in PHP Code
The error being related to JSON.parse smacks of this being a JavaScript error not a PHP one. So I would do a console.log(...) on whatever data you are passing to JSON.parse; that's where the error is coming from. If you can't identify what is wrong with that data, post it here and I'm sure someone wil pitch in and help you identify your issue. More on reddit.com
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November 20, 2024
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SyntaxError · JSON.parse() parses a string as JSON. This string has to be valid JSON and will throw this error if incorrect syntax was encountered. Both lines will throw a SyntaxError: js · JSON.parse("[1, 2, 3, 4,]"); JSON.parse('{"foo": 1,}'); // SyntaxError JSON.parse: unexpected character // at line 1 column 14 of the JSON data ·
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January 24, 2025 - Learn how to identify and fix the most common JSON parsing errors including trailing commas, missing quotes, and invalid escape sequences.
Top answer
1 of 16
62

For the benefit of searchers looking to solve a similar problem, you can get a similar error if your input is an empty string.

e.g.

var d = "";
var json = JSON.parse(d);

or if you are using AngularJS

var d = "";
var json = angular.fromJson(d);

In chrome it resulted in 'Uncaught SyntaxError: Unexpected end of input', but Firebug showed it as 'JSON.parse: unexpected end of data at line 1 column 1 of the JSON data'.

Sure most people won't be caught out by this, but I hadn't protected the method and it resulted in this error.

2 of 16
28

The fact the character is a < make me think you have a PHP error, have you tried echoing all errors.

Since I don't have your database, I'm going through your code trying to find errors, so far, I've updated your JS file

$("#register-form").submit(function (event) {

    var entrance = $(this).find('input[name="IsValid"]').val();
    var password = $(this).find('input[name="objPassword"]').val();
    var namesurname = $(this).find('input[name="objNameSurname"]').val();
    var email = $(this).find('input[name="objEmail"]').val();
    var gsm = $(this).find('input[name="objGsm"]').val();
    var adres = $(this).find('input[name="objAddress"]').val();
    var termsOk = $(this).find('input[name="objAcceptTerms"]').val();

    var formURL = $(this).attr("action");


    if (request) {
        request.abort(); // cancel if any process on pending
    }

    var postData = {
        "objAskGrant": entrance,
        "objPass": password,
        "objNameSurname": namesurname,
        "objEmail": email,
        "objGsm": parseInt(gsm),
        "objAdres": adres,
        "objTerms": termsOk
    };

    $.post(formURL,postData,function(data,status){
        console.log("Data: " + data + "\nStatus: " + status);
    });

    event.preventDefault();
});

PHP Edit:

 if (isset($_POST)) {

    $fValid = clear($_POST['objAskGrant']);
    $fTerms = clear($_POST['objTerms']);

    if ($fValid) {
        $fPass = clear($_POST['objPass']);
        $fNameSurname = clear($_POST['objNameSurname']);
        $fMail = clear($_POST['objEmail']);
        $fGsm = clear(int($_POST['objGsm']));
        $fAddress = clear($_POST['objAdres']);
        $UserIpAddress = "hidden";
        $UserCityLocation = "hidden";
        $UserCountry = "hidden";

        $DateTime = new DateTime();
        $result = $date->format('d-m-Y-H:i:s');
        $krr = explode('-', $result);
        $resultDateTime = implode("", $krr);

        $data = array('error' => 'Yükleme Sırasında Hata Oluştu');

        $kayit = "INSERT INTO tbl_Records(UserNameSurname, UserMail, UserGsm, UserAddress, DateAdded, UserIp, UserCityLocation, UserCountry, IsChecked, GivenPasscode) VALUES ('$fNameSurname', '$fMail', '$fGsm', '$fAddress', '$resultDateTime', '$UserIpAddress', '$UserCityLocation', '$UserCountry', '$fTerms', '$fPass')";
        $retval = mysql_query( $kayit, $conn ); // Update with you connection details
            if ($retval) {
                $data = array('success' => 'Register Completed', 'postData' => $_POST);
            }

        } // valid ends
    }echo json_encode($data);
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Bobby Hadz
bobbyhadz.com › blog › javascript-syntaxerror-json-parse-unexpected-character
SyntaxError: JSON.parse unexpected character in JavaScript | bobbyhadz
The "SyntaxError JSON.parse unexpected character at line" error occurs when we try to `JSON.parse` a value that is not a valid JSON string.
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LambdaTest
lambdatest.com › blog › syntaxerror-json-parse-bad-parsing
SyntaxError: JSON.parse: bad parsing | LambdaTest
November 30, 2023 - In most web applications, nearly all data transferred from web server is transmitted in a string format. To convert that string into JSON, we use JSON.parse() function, and this the main function that throws errors. Nearly all JSON.parse errors are a subset of SyntaxError error type.
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Quora
quora.com › How-do-I-fix-the-JSON-parse-error
How to fix the JSON parse error - Quora
JSON.parse() is a built-in method in JavaScript which is used to parse a JSON string and convert it into a JavaScript object. If the JSON string is invalid, it will throw a SyntaxError. ... The most common way to handle JSON parse error is using ...
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Reddit
reddit.com › r/phphelp › help! json syntax error in php code
r/PHPhelp on Reddit: Help! JSON Syntax Error in PHP Code
November 20, 2024 -

Hi everyone,

I'm a beginner in php and now i am currently facing an issue with a JSON syntax error in my PHP code. I've tried debugging it myself but can't seem to figure out what I'm doing wrong. Here's the part of the code where the error is coming , while this is the only code which makes the issue remaining code is correctly returning the json and my js is able to access it while in this function

function getPremiumItem($conn, $item_code)
{
    $sql = "SELECT item_name, credits FROM premium_items WHERE item_code = ?";
    $stmt = $conn->prepare($sql);
    $stmt->bind_param("s", $item_code);
    $stmt->execute();
    $item_name = '';
    $credits = 0;
    $stmt->bind_result($item_name, $credits);

    if ($stmt->fetch()) {
        echo json_encode(['item_name' => $item_name, 'credits' => $credits]);
    } else {
        echo json_encode(['error' => 'Item not found']);
    }
}

if ($_SERVER['REQUEST_METHOD'] === 'GET') {
    if (isset($_GET['action'])) {
        if ($_SERVER['action'] === 'getPremiumItem' && isset($_GET['item_code'])) {
            $item_code = $_GET['item_code'];
            getPremiumItem($conn, $item_code);
        }
    }
}

error is coming SyntaxError: JSON.parse: unexpected character at line 3 column 1 of the JSON data

can anyone pls help me fix the issue

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jsonlint.com
JSONLint - The JSON Validator
It's an excellent way to correct errors without wasting hours finding a missing coma somewhere inside your code. JSONLint is an online editor, validator, and formatting tool for JSON, which allows you to directly type your code, copy and paste it, or input a URL containing your code.
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Parabola
community.parabola.io › ask a question
JSON syntax error - Ask a question - Parabola support forum
February 13, 2023 - Keep getting this error. I’ve tried making changes as other people have had similar issues, but none have worked. Can anyone help please? Thank you for your help.
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Stack Overflow
stackoverflow.com › questions › 37982961 › json-syntax-and-errors
JSON Syntax and Errors
please make json comma (,) separate for valid syntax. example. { "name":"Udacity", "subjects":["HTML","CSS"], "nanodegrees":["Intro to Programming","Front-End Web Developer"] } Share · Improve this answer · Follow · edited Jun 23, 2016 at ...
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jsonlint.com › json-error-analyzer
JSON Error Analyzer - Understand & Fix JSON Errors | JSONLint | JSONLint
Check the line above — Often the real error is on the linebefore where it's reported (like a missing comma). Look for copy-paste issues — JSON from JavaScript code often has single quotes or trailing commas that need fixing. Validate incrementally — If you have a large JSON file, try validating smaller sections to isolate the problem. Use syntax highlighting — A good editor will show mismatched brackets and unclosed strings visually.