What about using:

min(a, b) < x < max(a, b)

Use random.uniform(a, b):

>>> import random
>>> random.uniform(1.5, 1.9)
1.8733202628557872

You can use the method linspace():

import numpy as np

l = np.linspace(1.2,2.9,100)

print(len(l))

print(l)

Output:

100
[1.2        1.21717172 1.23434343 1.25151515 1.26868687 1.28585859
 1.3030303  1.32020202 1.33737374 1.35454545 1.37171717 1.38888889
 1.40606061 1.42323232 1.44040404 1.45757576 1.47474747 1.49191919
 1.50909091 1.52626263 1.54343434 1.56060606 1.57777778 1.59494949
 1.61212121 1.62929293 1.64646465 1.66363636 1.68080808 1.6979798
 1.71515152 1.73232323 1.74949495 1.76666667 1.78383838 1.8010101
 1.81818182 1.83535354 1.85252525 1.86969697 1.88686869 1.9040404
 1.92121212 1.93838384 1.95555556 1.97272727 1.98989899 2.00707071
 2.02424242 2.04141414 2.05858586 2.07575758 2.09292929 2.11010101
 2.12727273 2.14444444 2.16161616 2.17878788 2.1959596  2.21313131
 2.23030303 2.24747475 2.26464646 2.28181818 2.2989899  2.31616162
 2.33333333 2.35050505 2.36767677 2.38484848 2.4020202  2.41919192
 2.43636364 2.45353535 2.47070707 2.48787879 2.50505051 2.52222222
 2.53939394 2.55656566 2.57373737 2.59090909 2.60808081 2.62525253
 2.64242424 2.65959596 2.67676768 2.69393939 2.71111111 2.72828283
 2.74545455 2.76262626 2.77979798 2.7969697  2.81414141 2.83131313
 2.84848485 2.86565657 2.88282828 2.9       ]

Try this:

import math
list(range(math.ceil(num1), math.floor(num2) + 1))

Is that you are looking for?

def check(value):
    if 0.50 <= value <= 150 and round(value,2)==value:
        return True
    return False

Given your comment:

i input 15.22366 it is going to return true; that is why i specified the range; it should accept 15.22

Simply said, floating point values are imprecise. Many values don't have a precise representation. Say for example 1.40. It might be displayed "as it":

>>> f = 1.40
>>> print f
1.4

But this is an illusion. Python has rounded that value in order to nicely display it. The real value as referenced by the variable f is quite different:

>>> from decimal import Decimal
>>> Decimal(f)
Decimal('1.399999999999999911182158029987476766109466552734375')

According to your rule of having only 2 decimals, should f reference a valid value or not?

The easiest way to fix that issue is probably to use round(...,2) as I suggested in the code above. But this in only an heuristic -- only able to reject "largely wrong" values. See my point here:

>>> for v in [ 1.40,
...            1.405,
...            1.399999999999999911182158029987476766109466552734375,
...            1.39999999999999991118,
...            1.3999999999999991118]:
...     print check(v), v
...
True 1.4
False 1.405
True 1.4
True 1.4
False 1.4

Notice how the last few results might seems surprising at first. I hope my above explanations put some light on this.

As a final advice, for your needs as I guess them from your question, you should definitively consider using "decimal arithmetic". Python provides the decimal module for that purpose.