re.sub python - Brave Search

Python Regular Expression: re.sub to replace matches

stackoverflow.com › questions › 74613853 › python-regular-expression-re-sub-to-replace-matches

The first argument to re.sub is treated as a regular expression, so the square brackets get a special meaning and don't match literally.

You don't need a regular expression for this replacement at all though (and you also don't need the loop counter i):

for name_line in name_lines:
    text = text.replace(name_line, '')

Answer from Thomas on Stack Overflow

Python documentation

docs.python.org › 3 › library › re.html

re — Regular expression operations

4 days ago - However, Unicode strings and 8-bit ... for a substitution, the replacement string must be of the same type as both the pattern and the search string. Regular expressions use the backslash character ('\') to indicate special forms or to allow special characters to be used without invoking their special meaning. This collides with Python’s usage ...

geeksforgeeks.org › python › re-sub-python-regex

re.sub() - Python RegEx - GeeksforGeeks

July 23, 2025 - re.sub() method in Python parts of a string that match a given regular expression pattern with a new substring.

Discussions

Regular Expressions re.sub

There is, by making the pattern lazy rather than greedy: new_text = re.sub(r"(?:\<.*?\>)*", "", old_text) However, you should not use regex to parse HTML, as Tony the Pony will tell you . More on reddit.com

r/learnpython

10

9

August 29, 2023

Replacement argument in re.sub()

Hello, I have the following strings that I would like to match and replace. I am able to match the strings but struggling to carry out a replacement - the output either doesn’t change or it completely erases sections of the input string. i have included an example of one of many options I ... More on discuss.python.org

discuss.python.org

0

November 10, 2022

Regex re.sub("^\s*(.-)\s*$", "%1", s).replace("\\n", "\n") explained

re.sub replaces matches with something else. ^\s*(.-)\s*$ ^ means start of string $ means end of string \s* means match 0 or more empty space characters () means this is a group we want, this will be group 1 for replace .- means match any 1 character and a dash after it. \s* again means 0 or more empty spaces basically it takes a " a- " and replaces it with "a-". >>> re.findall("^\s*(.-)\s*$"," s- ") ['s-'] >>> re.findall("^\s*(.-)\s*$"," xx- ") [] More on reddit.com

r/learnpython

6

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June 4, 2020

Module re: add possibility to return matches during substitution

Problem I would like to have access to the matches from a substitution. This would allow to reconstruct the original string (or parts of it) from the replaced string. An example use case is to (efficiently) parse a long … More on discuss.python.org

discuss.python.org

0

April 12, 2024

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Python standard library: Replacing text with regexps using re.sub ...

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Regular Expressions 2018 | #8 re.sub() replace characters | Python ...

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stackoverflow.com › questions › 74613853 › python-regular-expression-re-sub-to-replace-matches

regex - Python Regular Expression: re.sub to replace matches - Stack Overflow

The first argument to re.sub is treated as a regular expression, so the square brackets get a special meaning and don't match literally.

You don't need a regular expression for this replacement at all though (and you also don't need the loop counter i):

for name_line in name_lines:
    text = text.replace(name_line, '')

Try to use re.sub to replace the match:

import re

text = """\
Questions and Answers
Operator [1]

Shannon Siemsen Cross, Cross Research LLC - Co-Founder, Principal & Analyst [2]
I hope everyone is well. Tim, you talked about seeing some improvement in the second half of April. So I was wondering if you could just talk maybe a bit more on the segment and geographic basis what you're seeing in the various regions that you're selling in and what you're hearing from your customers. And then I have a follow-up.
Timothy D. Cook, Apple Inc. - CEO & Director [3]"""

text = re.sub(r".*\d]", "", text)
print(text)

Prints:

Questions and Answers



I hope everyone is well. Tim, you talked about seeing some improvement in the second half of April. So I was wondering if you could just talk maybe a bit more on the segment and geographic basis what you're seeing in the various regions that you're selling in and what you're hearing from your customers. And then I have a follow-up.

w3schools.com › python › python_regex.asp

W3Schools offers free online tutorials, references and exercises in all the major languages of the web. Covering popular subjects like HTML, CSS, JavaScript, Python, SQL, Java, and many, many more.

reddit.com › r/learnpython › regular expressions re.sub

r/learnpython on Reddit: Regular Expressions re.sub

August 29, 2023 -

Hi. I am currently building my very first python project. I need to get rid of all the Characts inside and including the <>. In the following example, the text "like the side of a house" should be left over.

<span class="idiom_proverb">like the side of a <strong class="tilde">house

</strong> </span>

I want to use re.sub with regular expressions on this one and my current code looks like this:

new_text = re.sub(r"(?:\<.*\>)*", "", old_text)

The problem is, when using re.sub this way, I am essentially deleting everything between the first < and the very last >, loosing all the information in between. Is there a way to make sure that my regular expressions refer to the very next > once a < is found?

This way it would only replace <spand class="idiom\_proverb">, <strong class="tilde">, </strong> and </span>?

I would really appreciate any help. Thank you!

There is, by making the pattern lazy rather than greedy: new_text = re.sub(r"(?:\<.*?\>)*", "", old_text) However, you should not use regex to parse HTML, as Tony the Pony will tell you .

You nearly have it, but .* is greedy and will look for the largest search pattern it can match instead of matching each < with the closing >. You can include a ? after the * to indicate lazy instead. This should give the proper result. new_text = re.sub(r"(?:\<.*?\>)*", "", old_text)

Python Tutorial

pythontutorial.net › home › python regex › python regex sub()

Python Regex sub() Function

December 10, 2021 - re.sub(pattern, repl, string, count=0, flags=0)Code language: Python (python)

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educative.io › answers › what-is-the-resub-function-in-python

What is the re.sub() function in Python?

Python uses the re.sub() function to replace text that matches a regular expression pattern with a new value in a string.

zetcode.com › python › regex-sub-function

Python re.sub - Mastering Regular Expression Substitution

April 20, 2025 - The basic syntax of re.sub has three required parameters: ... Optional count limits replacements. flags modify matching behavior. The function returns the modified string. Let's start with a simple example replacing colors in a sentence. ... #!/usr/bin/python import re text = "The sky is blue and the grass is green" result = re.sub(r'blue', 'gray', text) print(result)

builtin.com › articles › python-re-match

Python re.match() and re.sub() Explained | Built In

Python re.sub() is a function that’s used for substituting occurrences of a pattern in a string.

codecademy.com › docs › python › regular expressions › re.sub()

Python | Regular Expressions | re.sub() | Codecademy

October 14, 2024 - The re.sub() function replaces matching substrings with a new string for all occurrences, or a specified number. ... Looking for an introduction to the theory behind programming? Master Python while learning data structures, algorithms, and more!

Python documentation

docs.python.org › 3 › howto › regex.html

Regular Expression HOWTO — Python 3.14.3 documentation

Backreferences like this aren’t often useful for just searching through a string — there are few text formats which repeat data in this way — but you’ll soon find out that they’re very useful when performing string substitutions.

software.codidact.com › posts › 294905

Python re.sub() how to include and slice the match in the substitution? - Software Development

November 1, 2025 - I recently started learning regular expressions and I'm trying to use Python's re module, specifically the re.sub() function, to convert a subset of Markdown syntax to HTML whenever it appears in a string.

discuss.python.org › python help

Replacement argument in re.sub() - Python Help - Discussions on Python.org

November 10, 2022 - Hello, I have the following strings that I would like to match and replace. I am able to match the strings but struggling to carry out a replacement - the output either doesn’t change or it completely erases sections of the input string. i have included an example of one of many options I have tried. scenario 1: input string: (BXXADDB)(BXXXCAC1)(CXX2A)CANEVER desired output string: (BXXADDB)(BXXXCAC1)(CXX2A)*CANEVER pattern = r"^\([A-Za-z0-9]+\)\([A-Za-z0-9]+\)\([^)]*\)[a-zA-Z]+$" replaceme...

youtube.com › pymoondra

Python Regular Expressions -part #12 - Re.sub - YouTube

In this video series, we will be tackling Python Regular Expressions from beginners to advanced.This video goes over:1) re.sub -- vanilla subs, as well as us...

Published August 25, 2017

Views 18K

developers.google.com › google for education › python › python regular expressions

Python Regular Expressions | Python Education | Google for Developers

The re.sub(pat, replacement, str) function searches for all the instances of pattern in the given string, and replaces them.

reddit.com › r/learnpython › regex re.sub("^\s*(.-)\s*$", "%1", s).replace("\\n", "\n") explained

r/learnpython on Reddit: Regex re.sub("^\s*(.-)\s*$", "%1", s).replace("\\n", "\n") explained

June 4, 2020 -

I am working on a code I found on Github and I am not familiar with regex. Can someone please explain the meaning of this re.sub("^\s*(.-)\s*$", "%1", s).replace("\\n", "\n")

s is the variable containing the string of interest.

re.sub replaces matches with something else. ^\s*(.-)\s*$ ^ means start of string $ means end of string \s* means match 0 or more empty space characters () means this is a group we want, this will be group 1 for replace .- means match any 1 character and a dash after it. \s* again means 0 or more empty spaces basically it takes a " a- " and replaces it with "a-". >>> re.findall("^\s*(.-)\s*$"," s- ") ['s-'] >>> re.findall("^\s*(.-)\s*$"," xx- ") []

I would thoroughly recommend trying out an online regex checker (just search for one) they are super handy for writing, testing and understanding regexs I've used https://regex101.com/

geeksforgeeks.org › python › python-substituting-patterns-in-text-using-regex

Python - Substituting patterns in text using regex - GeeksforGeeks

July 12, 2025 - To perform this type of substitution the re.sub() method has an argument count. By providing a numeric value to this argument, the number of characters on which substitution will occur can be controlled. Below is the implementation. ... # Python implementation to perform substitution # up to a certain number of characters # importing regex module import re # Function to perform # operations on the strings def substitutor(): # a string variable sentence = "Follow your Passion."

discuss.python.org › python help

Module re: add possibility to return matches during substitution - Python Help - Discussions on Python.org

April 12, 2024 - Problem I would like to have access to the matches from a substitution. This would allow to reconstruct the original string (or parts of it) from the replaced string. An example use case is to (efficiently) parse a long string and then parse it again, e.g., s1 = re.sub(' and ', '', 'a and b and c and d') # 3 matches, s1 = 'abac' re.finditer('ab|cd', s1) # two matches span 'ab', 'ac' Now, I would like to reconstruct the original string partially to obtain ab and ac.

xahlee.info › python › python_re.sub.html

Python: Regex re.sub

# example of using re.sub(pattern, rep, str ) where rep is a function import re def ff(xx): if xx.group(0) == "ea": return "æ" elif xx.group(0) == "oo": return "u" else: return xx.group(0) print(re.sub(r"[aeiou]+", ff, "encyclopeadia")) # encyclopædia print(re.sub(r"[aeiou]+", ff, "book")) # buk print(re.sub(r"[aeiou]+", ff, "geek")) # geek

stackoverflow.com › questions › 56213054 › how-to-use-re-sub-in-python

regex - How to use re.sub in Python? - Stack Overflow

You can use re.sub:

>>> import re
>>> text = "<a> text </a> <c> code </c>"
>>> new_text = re.sub(r'<c>.*?</c>', '', text)
>>> new_text
<a> text </a>

 import re
 text = "<a> text </a> <c> code </c>"
 rg = r"<c>.*<\/c>"
 for match in re.findall(rg, text):
     text = text.replace(match, "")