My problem was actually a problem of bad planning with the JSON object rather than an actual logic issue. What I ended up doing was organize the object as follows, per a suggestion from user2736012.

{
"dialog":
{
    "trunks":[
    {
        "trunk_id" : "1",
        "message": "This is just a JSON Test"
    },
    {
        "trunk_id" : "2",
        "message": "This is a test of a bit longer text. Hopefully this will at the very least create 3 lines and trigger us to go on to another box. So we can test multi-box functionality, too."
    }
    ]
}
}

At that point, I was able to do a fairly simple for loop based on the total number of objects.

var totalMessages = Object.keys(messages.dialog.trunks).length;

    for ( var i = 0; i < totalMessages; i++)
    {
        console.log("ID: " + messages.dialog.trunks[i].trunk_id + " Message " + messages.dialog.trunks[i].message);
    }

My method for getting totalMessages is not supported in all browsers, though. For my project, it actually doesn't matter, but beware of that if you choose to use something similar to this.

for my case i found iterating the names() works well

for(int i = 0; i<jobject.names().length(); i++){
    Log.v(TAG, "key = " + jobject.names().getString(i) + " value = " + jobject.get(jobject.names().getString(i)));
}

Taken from jQuery docs:

var arr = [ "one", "two", "three", "four", "five" ];
var obj = { one:1, two:2, three:3, four:4, five:5 };

jQuery.each(arr, function() {
  $("#" + this).text("My id is " + this + ".");
  return (this != "four"); // will stop running to skip "five"
});

jQuery.each(obj, function(i, val) {
  $("#" + i).append(document.createTextNode(" - " + val));
});

Hi @Paul

My thoughts are:

1. Declare classes and lists.
2. Assign a value to the data.
3. Generate JSON variables.
4. Print it out

For demonstration purposes, I printed the JSON data as string data.

In order to keep the same format as JSON, I set an option.

var options = new JsonSerializerOptions { WriteIndented = true };

string jsonString = System.Text.Json.JsonSerializer.Serialize(outputdata, options);

Of course, you can also print it directly.

You can refer to the following code:

public class TASK_O
{
    public List TASK_O_ITEM { get; set; }
}
public class Outputdata
{
    public TASK_O TASK_O { get; set; }
    public string ERROR_O { get; set; }
}
public class Example
{
    public Outputdata Outputdata { get; set; }
}
public class TASK_O_ITEM
{
    public string CODE { get; set; }
    public string NAME { get; set; }
}
internal class Program
{
    static void Main(string[] args)
    {
        var task_o_item = new List {
            new TASK_O_ITEM
            {
                CODE = "123",
                NAME = "ABC"
            },
            new TASK_O_ITEM
            {
                CODE = "456",
                NAME = "DEF"
            },
            new TASK_O_ITEM
            {
                CODE = "789",
                NAME = "GHI"
            },
        };
        var task_O = new TASK_O
        {
            TASK_O_ITEM = task_o_item
        };
        var outputdata = new Outputdata
        {
            TASK_O = task_O,
            ERROR_O = null
        };
        var example = new Example
        {
           Outputdata=outputdata
        };
        var options = new JsonSerializerOptions { WriteIndented = true };
        string jsonString = JsonSerializer.Serialize(example, options);
        Console.WriteLine(jsonString);
        Console.Read();
    }
}

Result:

Best Regards

Qi You

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