You could filter it and search just for one occurence of the search string.

Methods used:

• Array#filter, just for filtering an array with conditions,

• Object.keys for getting all property names of the object,

• Array#some for iterating the keys and exit loop if found,

• String#toLowerCase for getting comparable values,

• String#includes for checking two string, if one contains the other.

function filterByValue(array, string) {
    return array.filter(o =>
        Object.keys(o).some(k => o[k].toLowerCase().includes(string.toLowerCase())));
}

const arrayOfObject = [{ name: 'Paul', country: 'Canada', }, { name: 'Lea', country: 'Italy', }, { name: 'John', country: 'Italy' }];

console.log(filterByValue(arrayOfObject, 'lea')); // [{name: 'Lea', country: 'Italy'}]
console.log(filterByValue(arrayOfObject, 'ita')); // [{name: 'Lea', country: 'Italy'}, {name: 'John', country: 'Italy'}]

.as-console-wrapper { max-height: 100% !important; top: 0; }

The question is a little ambiguous, but my understanding (correct me if I'm wrong), is that you want to remove all items from a list emp that have the same QID as any item in another list data?

If that's the case, try:

this.employees = emp.filter(item => !this.data.some(d => d.QID === item.QID))

some is an array method that returns true if it's callback is true for any of the arrays elements. So in this case, some(d => d.QID === item.QID) would be true if ANY of the elements of the list data have the same QID as item.

filter() -> uses a callback function the return value of which decides what will be returned in the filtered array. If return value is true, the item is included in the resultant array.

includes() -> searches for something in an array of items using == equality

const books = [{
     id: "1",
     title: "Book title",
     areas: ["horror", "mystery"]
   }, {
     id: "2",
     title: "Book title 2",
     areas: ["friendship", "love", "history"]
   },
   {
     id: "3",
     title: "Book title 3",
     areas: ["friendship", "scifi"]
   }
];

const filterValue = "horror";
const filteredBooks = books.filter(val => val.areas.includes(filterValue));
console.log(filteredBooks);

You can use the Array.prototype.filter method:

var newArray = homes.filter(function (el) {
  return el.price <= 1000 &&
         el.sqft >= 500 &&
         el.num_of_beds >=2 &&
         el.num_of_baths >= 2.5;
});

Live Example:

var obj = {
    'homes': [{
            "home_id": "1",
            "price": "925",
            "sqft": "1100",
            "num_of_beds": "2",
            "num_of_baths": "2.0",
        }, {
            "home_id": "2",
            "price": "1425",
            "sqft": "1900",
            "num_of_beds": "4",
            "num_of_baths": "2.5",
        },
        // ... (more homes) ...     
    ]
};
// (Note that because `price` and such are given as strings in your object,
// the below relies on the fact that <= and >= with a string and number
// will coerce the string to a number before comparing.)
var newArray = obj.homes.filter(function (el) {
  return el.price <= 1000 &&
         el.sqft >= 500 &&
         el.num_of_beds >= 2 &&
         el.num_of_baths >= 1.5; // Changed this so a home would match
});
console.log(newArray);

This method is part of the new ECMAScript 5th Edition standard, and can be found on almost all modern browsers.

For IE, you can include the following method for compatibility:

if (!Array.prototype.filter) {
  Array.prototype.filter = function(fun /*, thisp*/) {
    var len = this.length >>> 0;
    if (typeof fun != "function")
      throw new TypeError();

    var res = [];
    var thisp = arguments[1];
    for (var i = 0; i < len; i++) {
      if (i in this) {
        var val = this[i];
        if (fun.call(thisp, val, i, this))
          res.push(val);
      }
    }
    return res;
  };
}