Simplest Answer
array.sort(function(a,b){
// Turn your strings into dates, and then subtract them
// to get a value that is either negative, positive, or zero.
return new Date(b.date) - new Date(a.date);
});
More Generic Answer
array.sort(function(o1,o2){
if (sort_o1_before_o2) return -1;
else if(sort_o1_after_o2) return 1;
else return 0;
});
Or more tersely:
array.sort(function(o1,o2){
return sort_o1_before_o2 ? -1 : sort_o1_after_o2 ? 1 : 0;
});
Generic, Powerful Answer
Define a custom non-enumerable sortBy function using a Schwartzian transform on all arrays :
(function(){
if (typeof Object.defineProperty === 'function'){
try{Object.defineProperty(Array.prototype,'sortBy',{value:sb}); }catch(e){}
}
if (!Array.prototype.sortBy) Array.prototype.sortBy = sb;
function sb(f){
for (var i=this.length;i;){
var o = this[--i];
this[i] = [].concat(f.call(o,o,i),o);
}
this.sort(function(a,b){
for (var i=0,len=a.length;i<len;++i){
if (a[i]!=b[i]) return a[i]<b[i]?-1:1;
}
return 0;
});
for (var i=this.length;i;){
this[--i]=this[i][this[i].length-1];
}
return this;
}
})();
Use it like so:
array.sortBy(function(o){ return o.date });
If your date is not directly comparable, make a comparable date out of it, e.g.
array.sortBy(function(o){ return new Date( o.date ) });
You can also use this to sort by multiple criteria if you return an array of values:
// Sort by date, then score (reversed), then name
array.sortBy(function(o){ return [ o.date, -o.score, o.name ] };
See http://phrogz.net/JS/Array.prototype.sortBy.js for more details.
Answer from Phrogz on Stack OverflowSimplest Answer
array.sort(function(a,b){
// Turn your strings into dates, and then subtract them
// to get a value that is either negative, positive, or zero.
return new Date(b.date) - new Date(a.date);
});
More Generic Answer
array.sort(function(o1,o2){
if (sort_o1_before_o2) return -1;
else if(sort_o1_after_o2) return 1;
else return 0;
});
Or more tersely:
array.sort(function(o1,o2){
return sort_o1_before_o2 ? -1 : sort_o1_after_o2 ? 1 : 0;
});
Generic, Powerful Answer
Define a custom non-enumerable sortBy function using a Schwartzian transform on all arrays :
(function(){
if (typeof Object.defineProperty === 'function'){
try{Object.defineProperty(Array.prototype,'sortBy',{value:sb}); }catch(e){}
}
if (!Array.prototype.sortBy) Array.prototype.sortBy = sb;
function sb(f){
for (var i=this.length;i;){
var o = this[--i];
this[i] = [].concat(f.call(o,o,i),o);
}
this.sort(function(a,b){
for (var i=0,len=a.length;i<len;++i){
if (a[i]!=b[i]) return a[i]<b[i]?-1:1;
}
return 0;
});
for (var i=this.length;i;){
this[--i]=this[i][this[i].length-1];
}
return this;
}
})();
Use it like so:
array.sortBy(function(o){ return o.date });
If your date is not directly comparable, make a comparable date out of it, e.g.
array.sortBy(function(o){ return new Date( o.date ) });
You can also use this to sort by multiple criteria if you return an array of values:
// Sort by date, then score (reversed), then name
array.sortBy(function(o){ return [ o.date, -o.score, o.name ] };
See http://phrogz.net/JS/Array.prototype.sortBy.js for more details.
@Phrogz answers are both great, but here is a great, more concise answer:
array.sort(function(a,b) { return a.getTime() - b.getTime() });
Using the arrow function way
array.sort((a,b) => a.getTime() - b.getTime());
found here: Sort date in Javascript
How can I sort an array of object with date (created_at) from the latest to the oldest .Here is an example bellow of an array I want to sort
Sort array of arrays by date in the array?
You don't really need lodash. You can use JavaScript's Array.prototype.sort method.
You'll need to create Date objects from your date strings before you can compare them.
var myArray = [{
name: "Joe Blow",
date: "Mon Oct 31 2016 00:00:00 GMT-0700 (PDT)"
}, {
name: "Sam Snead",
date: "Sun Oct 30 2016 00:00:00 GMT-0700 (PDT)"
}, {
name: "John Smith",
date: "Sat Oct 29 2016 00:00:00 GMT-0700 (PDT)"
}];
myArray.sort(function compare(a, b) {
var dateA = new Date(a.date);
var dateB = new Date(b.date);
return dateA - dateB;
});
console.log(myArray);
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Here's a solution using standard Javascript by converting both values to date object and comparing their value.
myArray.sort((d1, d2) => new Date(d1.date).getTime() - new Date(d2.date).getTime());
A complete snippet:
var myArray = [
{
name: "Joe Blow",
date: "Mon Oct 31 2016 00:00:00 GMT-0700 (PDT)"
},
{
name: "Sam Snead",
date: "Sun Oct 30 2016 00:00:00 GMT-0700 (PDT)"
},
{
name: "John Smith",
date: "Sat Oct 29 2016 00:00:00 GMT-0700 (PDT)"
}
];
myArray.sort((d1, d2) => new Date(d1.date).getTime() - new Date(d2.date).getTime());
console.log(myArray);
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