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Python range of float numbers
April 13, 2021 - ... Import numpy module using the import numpy as np statement. ... Pass float numbers to its start, stop, and step argument. For example, np.arange(0.5, 6.5, 1.5) will return the sequence of floating-point numbers starting from 0.5 up to 6.5.
Finxter
blog.finxter.com › 5-best-ways-to-generate-list-of-floats-in-python
5 Best Ways to Generate List of Floats in Python – Be on the Right Side of Change
The call to list() then converts the generator expression’s output into a list. This method is highly efficient for large ranges as it doesn’t store the entire list in memory. itertools includes the functions islice() and count() which can be combined to efficiently generate sequences of ...
PyTutorial
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PyTutorial | Python Range Float: How to Generate Sequences
March 30, 2026 - For a deep dive into its exclusive stop behavior, see our guide on Is Python Range Inclusive? Stop Value Explained. This integer-only rule is non-negotiable. It is a core part of the function's contract. This ensures predictable and fast performance in loops. The simplest alternative is a list comprehension. You can use the integer range() to control iterations. Then, calculate the float value inside the loop. This gives you full control over the step size. # Generate a sequence from 0.0 to 2.0 in steps of 0.2 step = 0.2 num_steps = int((2.0 - 0.0) / step) + 1 # Calculate number of items float_sequence = [0.0 + i * step for i in range(num_steps)] print(float_sequence)
TutorialKart
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Python Range with Floating Point Numbers
January 17, 2021 - Also, there is a function in numpy() library, arange() function, that can generate a sequence of floating point numbers.
Iditect
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Python range() for floats
The built-in range() function in Python is designed for working with integers, and it doesn't support floating-point values directly. However, you can create your own generator function to generate a sequence of floating-point numbers within a specified range.
TechBeamers
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Generate Floating Point Range in Python - TechBeamers
November 30, 2025 - However, all arguments are of integer type. If you pass a float, it results in a TypeError. start = 1 stop = 6.7 step = 0.1 for value in range(start, stop, step): print (value) When you run the above code, it throws the following error: TypeError: 'float' object cannot be interpreted as an integer · The above example suggests that Python doesn’t give any built-in way to generate a floating point range.
AdamSmith.haus
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How to generate a range of Floats in Python - Adam Smith
Python answers, examples, and documentation
Learn By Example
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How to Generate a Range of Floating-point Numbers in Python - Learn By Example
April 18, 2024 - Generators are particularly useful for dealing with large datasets or potentially infinite sequences. Instead of computing and storing all values in memory at once, a generator produces them one at a time as needed. This ‘on-demand’ approach is extremely useful when handling large datasets or complex iterations, as it drastically reduces memory overhead. If you prefer a more concise approach and need to generate a list, you can use a list comprehension: def float_range(start, stop, step): return [round(start + i * step, 10) for i in range(int((stop - start) / step))] print(float_range(0.0, 1.0, 0.2)) # Output: [0.0, 0.2, 0.4, 0.6, 0.8]
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Its Linux FOSS
itslinuxfoss.com › home › python › python range of float numbers
Python Range of Float Numbers – Its Linux FOSS
February 19, 2023 - The “range()” function is used in Python to generate the sequence of numbers. But the simple “range()” function will return an error when the float value is passed to it, so we explained several other ...
Finxter
blog.finxter.com › 5-best-ways-to-create-a-set-of-floats-from-1-to-n-in-python
5 Best Ways to Create a Set of Floats from 1 to n in Python – Be on the Right Side of Change
February 25, 2024 - Using the itertools.chain function is a more advanced, yet concise, way to create a set of floats. This method can be particularly efficient when combining multiple iterators into a single sequence of floats before creating a set.
Top answer 1 of 3
2
In [1]: import numpy as np
In [2]: np.repeat(1 / 10**np.arange(1, 5), 2)[1:] * np.array([1., 5.]*4)[:-1]
Out[2]: array([0.1 , 0.05 , 0.01 , 0.005 , 0.001 , 0.0005, 0.0001])
Generalizing for any "pattern":
def rates(smallest_magnitude, pattern):
n = len(pattern)
pows = np.repeat(1 / 10**np.arange(1, smallest_magnitude), n)[(n-1):]
mults = np.array(pattern * (smallest_magnitude - 1))[:-(n-1)]
return np.round(pows * mults, smallest_magnitude)
Demo:
In [4]: print(*rates(5, [1, 5])) # Your original 'pattern'
0.1 0.05 0.01 0.005 0.001 0.0005 0.0001
In [5]: print(*rates(5, [2, 4, 8]))
0.2 0.04 0.08 0.02 0.004 0.008 0.002 0.0004 0.0008 0.0002
In [6]: print(*rates(5, [3, 5, 7, 9]))
0.3 0.05 0.07 0.09 0.03 0.005 0.007 0.009 0.003 0.0005 0.0007 0.0009 0.0003
2 of 3
2
This works, but I'm not sure it's any better than your method.
import numpy as np
# Create the powers of ten:
a = 0.1 ** np.arange(1,6)
# Interleave the halves in between:
a = np.concatenate((a,a/2))
# Sort and reverse:
a.sort()
a = a[-1::-1]
print(a)