Use a generator together with any, which short-circuits on the first True:
if any(ext in url_string for ext in extensionsToCheck):
print(url_string)
EDIT: I see this answer has been accepted by OP. Though my solution may be "good enough" solution to his particular problem, and is a good general way to check if any strings in a list are found in another string, keep in mind that this is all that this solution does. It does not care WHERE the string is found e.g. in the ending of the string. If this is important, as is often the case with urls, you should look to the answer of @Wladimir Palant, or you risk getting false positives.
Answer from Lauritz V. Thaulow on Stack OverflowUse a generator together with any, which short-circuits on the first True:
if any(ext in url_string for ext in extensionsToCheck):
print(url_string)
EDIT: I see this answer has been accepted by OP. Though my solution may be "good enough" solution to his particular problem, and is a good general way to check if any strings in a list are found in another string, keep in mind that this is all that this solution does. It does not care WHERE the string is found e.g. in the ending of the string. If this is important, as is often the case with urls, you should look to the answer of @Wladimir Palant, or you risk getting false positives.
extensionsToCheck = ('.pdf', '.doc', '.xls')
'test.doc'.endswith(extensionsToCheck) # returns True
'test.jpg'.endswith(extensionsToCheck) # returns False
Say I have a list of strings like: ["Hey dude", "Hey bro", "Sup dude", "Hey bud"]
How do I check if *any* of those strings in the list contain the word "Sup"?Alternatively, in my case, I could also check if *all* of the strings contain "Hey" , which I also don't know how to do.
(Sorry, I'm new to Python)
Edit: Thank you so much for all the help, guys <3
python - How to check if a string is a substring of items in a list of strings - Stack Overflow
How do I check if string contains all substrings in list?
You could try
if all([val in string for val in list]):
Which checks the truth of each check and returns True only if all are True. Otherwise you're looking at a loop (or if your lists get really big a generator).
Help!: Check if a Python list item contains a string inside another string but with conditions
Check contain string, and move the rest element to new list
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To check for the presence of 'abc' in any string in the list:
xs = ['abc-123', 'def-456', 'ghi-789', 'abc-456']
if any("abc" in s for s in xs):
...
To get all the items containing 'abc':
matching = [s for s in xs if "abc" in s]
Just throwing this out there: if you happen to need to match against more than one string, for example abc and def, you can combine two comprehensions as follows:
matchers = ['abc','def']
matching = [s for s in my_list if any(xs in s for xs in matchers)]
Output:
['abc-123', 'def-456', 'abc-456']
I have a list, that takes inputs from the user, this means it can change size; for example: list = ["test", "do"] or list = ["a", "b", "c"]
I want to check if variable string, contains all the substrings in list.
I thought if I used:
if list in string: that would work, but it didn't, TypeError: 'in <string>' requires string as left operand, not list
Is there another function/method for this? Or am I going to have to loop len(list) times (I really don't want to do that, because I check hundreds of changing strings)?
You could try
if all([val in string for val in list]):
Which checks the truth of each check and returns True only if all are True. Otherwise you're looking at a loop (or if your lists get really big a generator).
I don't really understand your question, but the easiest to understand solution is probably
if len(set(sub) - set(super)) > 0:Another one, straightforward, but more complex, is
if all(el in sub for el in super):I have two days learning python but I really need to do that code. I also posted this question in StackOverflow but it got downvoted the first second.
I want to make a function to print all the words that contain a specific consonant (only one) and any amount of vowels, but I don't know how to introduce the conditions here.
I made a list with 4 elements via the input method (I know I use a different way), and a method that prints all the words that include the letter "f", but as I said, it needs to be more specific (only one consonant, "f" in this case, and any amount of vowels):
list = []
for x in range (4):
words = str(input("Type a word "))
list.append(words)
#This method kinda works, but it needs to be more specific.
matching = [s for s in list if "f" in s]
print(matching) In my code, if I have words with the letter "f", I'll get a list with all the words containing any amount of "f" letters and any other consonant, but I just want one consonant "f" and vowels, not the other consonants.
My desired result is like
list = [fox, alfa, fa, real, fou]
#['fa', 'fou']