With includes(), no, but you can achieve the same thing with REGEX via test():

var value = /hello|hi|howdy/.test(str);

Or, if the words are coming from a dynamic source:

var words = ['hello', 'hi', 'howdy'];
var value = new RegExp(words.join('|')).test(str);

The REGEX approach is a better idea because it allows you to match the words as actual words, not substrings of other words. You just need the word boundary marker \b, so:

var str = 'hilly';
var value = str.includes('hi'); //true, even though the word 'hi' isn't found
var value = /\bhi\b/.test(str); //false - 'hi' appears but not as its own word

This can be done cleanly using the reduce method of arrays. Here's how to do it with your example:

var arr = ["TL", "TM", "TR"];
var fails = ["TL"] // This will return false
var succeeds = ["TL", "TM", "TR"] // This will return true
var includesAll = (array_to_check) => arr.reduce(
    (accumulator, current) => accumulator && array_to_check.includes(current),
    true
)

if (includesAll(succeeds)){
    console.log("yes");
} else {
    console.log("nope");
}

You can use regex instead of includes() with a loop to solve it.

Demo:

var fruit = "green dpear";

if (/\b(apple|pear|orange)\b/.test(fruit)) {
  console.log('match');
} else {
  console.log('not_match');
}

This achieves dynamically and elegantly what you are trying to do

const terms = ["term1", "term2", "term3"]
const str = "very large string to check for term1, tern2, etc ..."

// check if the string has some of the terms
const result1 = terms.some(term => str.includes(term))

// check if the string has all the terms
const result2 = terms.every(term => str.includes(term))

This also makes it easy to filter an array of strings for an array of substrings

const terms = ["term1", "term2", "term3"]
const strings = ["very large string text ....", "another large string text"] 

// filter the strings of the array that contain some of the substrings we're looking for
const result1 = strings.filter(str => terms.some(term => str.includes(term)))

// filter the strings of the array that contain all the substrings we're looking for
const result2 = strings.filter(str => terms.every(term => str.includes(term)))