Just split into two parts with '.' and format them individually.

function commafy( num ) {
    var str = num.toString().split('.');
    if (str[0].length >= 5) {
        str[0] = str[0].replace(/(\d)(?=(\d{3})+1,');
    }
    if (str[1] && str[1].length >= 5) {
        str[1] = str[1].replace(/(\d{3})/g, '$1 ');
    }
    return str.join('.');
}

@Paul Creasey had the simplest solution as the regex, but here it is as a simple jQuery plugin:

$.fn.digits = function(){ 
    return this.each(function(){ 
        $(this).text( $(this).text().replace(/(\d)(?=(\d\d\d)+(?!\d))/g, "$1,") ); 
    })
}

You could then use it like this:

$("span.numbers").digits();

In your current pattern (\d{3}) you add a comma after matching 3 digits and also when there is already a comma following the 3 digits.

What you might do is match 3 digits using a negative lookahead (?!,) to assert what follows is not a comma:

(\d{3}(?!,))

$("#annual_sales").on('keyup', function() {
  $(this).val($(this).val().replace(/(\d{3}(?!,))/g, "$1,"));
});

<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<input id="annual_sales" type="text" />

If you don't want the comma at the end of the line you could use an alternation in the negative lookahead that asserts what follows is neither a comma or the end of the line (\d{3}(?!,|$))

$("#annual_sales").on('keyup', function() {
  $(this).val($(this).val().replace(/(\d{3}(?!,|1,"));
});

<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<input id="annual_sales" type="text" />

The correct JavaScript code to add a comma after every three digits in the Monthly Payments input value for an onclick event would be:

<script
           language="JavaScript"><!--
function CarLoanCalculator()
{
    form = document.myform
    LoanAmount= form.LoanAmount.value
    LoanAmount = LoanAmount.replace(/,/g, "");
    parseInt(LoanAmount);   
    DownPayment= "0"
    AnnualInterestRate = form.InterestRate.value/100
    Years= form.NumberOfYears.value
        MonthRate=AnnualInterestRate/12
    NumPayments=Years*12
    Prin=LoanAmount-DownPayment

    function ReplaceNumberWithCommas(yourNumber) {
    MonthPayment=Math.floor((Prin*MonthRate)/(1-Math.pow((1+MonthRate),(-1*NumPayments)))*100)/100
    yourNumber = MonthPayment
    //Seperates the components of the number
    var components = yourNumber.toString().split(".");
    //Comma-fies the first part
    components [0] = components [0].replace(/\B(?=(\d{3})+(?!\d))/g, ",");
    //Combines the two sections
    return components.join(".");
    }
      //Seperates the components of the number
        form.NumberOfPayments.value=NumPayments
    form.MonthlyPayment.value=ReplaceNumberWithCommas()
    //Seperates the components of the number
}
        // --></script>

Note: the code is a bit out of order in terms of neatness and perhaps the comments, but the JavaScript syntax is correct.

I used the idea from Kerry's answer, but I simplified it since I was just looking for something simple for my specific purpose. Here is what I have:

function numberWithCommas(x) {
    return x.toString().replace(/\B(?=(\d{3})+(?!\d))/g, ",");
}

function numberWithCommas(x) {
    return x.toString().replace(/\B(?<!\.\d*)(?=(\d{3})+(?!\d))/g, ",");
}

function test(x, expect) {
    const result = numberWithCommas(x);
    const pass = result === expect;
    console.log(`${pass ? "✓" : "ERROR ====>"} ${x} => ${result}`);
    return pass;
}

let failures = 0;
failures += !test(0,        "0");
failures += !test(100,      "100");
failures += !test(1000,     "1,000");
failures += !test(10000,    "10,000");
failures += !test(100000,   "100,000");
failures += !test(1000000,  "1,000,000");
failures += !test(10000000, "10,000,000");
if (failures) {
    console.log(`${failures} test(s) failed`);
} else {
    console.log("All tests passed");
}

.as-console-wrapper {
    max-height: 100% !important;
}

The regex uses two lookahead assertions:

• a positive one to look for any point in the string that has a multiple of 3 digits in a row after it,
• a negative assertion to make sure that point only has exactly a multiple of 3 digits. The replacement expression puts a comma there.

For example, if you pass it 123456789.01, the positive assertion will match every spot to the left of the 7 (since 789 is a multiple of 3 digits, 678 is a multiple of 3 digits, 567, etc.).

The negative assertion checks that the multiple of 3 digits does not have any digits after it. 789 has a period after it so it is exactly a multiple of 3 digits, so a comma goes there. 678 is a multiple of 3 digits, but it has a 9 after it, so those 3 digits are part of a group of 4, and a comma does not go there. Similarly for 567.

456789 is 6 digits, which is a multiple of 3, so a comma goes before that. 345678 is a multiple of 3, but it has a 9 after it, so no comma goes there. And so on. The \B keeps the regex from putting a comma at the beginning of the string.

neu-rah mentioned that this function adds commas in undesirable places if there are more than 3 digits after the decimal point. If this is a problem, you can use this function:

function numberWithCommas(x) {
    var parts = x.toString().split(".");
    parts[0] = parts[0].replace(/\B(?=(\d{3})+(?!\d))/g, ",");
    return parts.join(".");
}

function numberWithCommas(x) {
    var parts = x.toString().split(".");
    parts[0] = parts[0].replace(/\B(?=(\d{3})+(?!\d))/g, ",");
    return parts.join(".");
}

function test(x, expect) {
    const result = numberWithCommas(x);
    const pass = result === expect;
    console.log(`${pass ? "✓" : "ERROR ====>"} ${x} => ${result}`);
    return pass;
}

let failures = 0;
failures += !test(0              , "0");
failures += !test(0.123456       , "0.123456");
failures += !test(100            , "100");
failures += !test(100.123456     , "100.123456");
failures += !test(1000           , "1,000");
failures += !test(1000.123456    , "1,000.123456");
failures += !test(10000          , "10,000");
failures += !test(10000.123456   , "10,000.123456");
failures += !test(100000         , "100,000");
failures += !test(100000.123456  , "100,000.123456");
failures += !test(1000000        , "1,000,000");
failures += !test(1000000.123456 , "1,000,000.123456");
failures += !test(10000000       , "10,000,000");
failures += !test(10000000.123456, "10,000,000.123456");
if (failures) {
    console.log(`${failures} test(s) failed`);
} else {
    console.log("All tests passed");
}

.as-console-wrapper {
    max-height: 100% !important;
}

T.J. Crowder pointed out that now that JavaScript has lookbehind (support info), it can be solved in the regular expression itself:

function numberWithCommas(x) {
    return x.toString().replace(/\B(?<!\.\d*)(?=(\d{3})+(?!\d))/g, ",");
}

function numberWithCommas(x) {
    return x.toString().replace(/\B(?<!\.\d*)(?=(\d{3})+(?!\d))/g, ",");
}

function test(x, expect) {
    const result = numberWithCommas(x);
    const pass = result === expect;
    console.log(`${pass ? "✓" : "ERROR ====>"} ${x} => ${result}`);
    return pass;
}

let failures = 0;
failures += !test(0,               "0");
failures += !test(0.123456,        "0.123456");
failures += !test(100,             "100");
failures += !test(100.123456,      "100.123456");
failures += !test(1000,            "1,000");
failures += !test(1000.123456,     "1,000.123456");
failures += !test(10000,           "10,000");
failures += !test(10000.123456,    "10,000.123456");
failures += !test(100000,          "100,000");
failures += !test(100000.123456,   "100,000.123456");
failures += !test(1000000,         "1,000,000");
failures += !test(1000000.123456,  "1,000,000.123456");
failures += !test(10000000,        "10,000,000");
failures += !test(10000000.123456, "10,000,000.123456");
if (failures) {
    console.log(`${failures} test(s) failed`);
} else {
    console.log("All tests passed");
}

.as-console-wrapper {
    max-height: 100% !important;
}

(?<!\.\d*) is a negative lookbehind that says the match can't be preceded by a . followed by zero or more digits. The negative lookbehind is faster than the split and join solution (comparison), at least in V8.