If usage of python standard library is not prohibited by the rules of your contest I would go with
from statistics import median
median(l)
Answer from gants_kuhelgarten on Stack OverflowI’ve looked it up and saw a lot of different formulas, so if someone could tell me which one you need to know for the SAT, that would be much appreciated?
(n+1)/2 is for odd numbers, but what about for even numbers?
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How to find the median of odd numbers?
Can the median value be a non-integer when dealing with even numbers of data points?
What are the steps to find the median in statistics for even data sets?
I don't have Excel, so I can't try it, but I think you should be able to accomplish this with a combination of the LARGE function the COUNT function, and the TRUNC function. For example, if the numbers you are working with are in cells A1 through A8, you should be able to find the answer you want, though technically it's not the median, with the formula
=LARGE(A1:A8,TRUNC(COUNT(A1:A8)/2))
Edit
=LARGE(A1:A8,TRUNC((1+COUNT(A1:A8))/2))
If you know you will always be working with an even number of entries, the call to TRUNC could be omitted.
With data in column A:
=IF(ISODD(COUNT(A:A)),MEDIAN(A:A),ROUNDUP(MEDIAN(A:A),0))
EDIT#1:
Consider the array formula:
=IF(ISODD(COUNT(A:A)),MEDIAN(A:A),MIN(IF(A:A>MEDIAN(A:A),A:A)))
If the number of values is odd, return the median.
If the number of value is even, return the smallest value greater than the median.
Array formulas must be entered with Ctrl + Shift + Enter rather than just the Enter key.
This approach does not require the data to be sorted.
EDIT#2:
This array formula appears to handle Ron's case:
=IF(ISODD(COUNT(A:A)),MEDIAN(A:A),MIN(IF(A:A>=MEDIAN(A:A),A:A)))
It returns the smallest value greater than or equal to the median (for the even case)
But I don't know if this is what the Poster wants.