Let me first highlight three different ways for similar purpose.
length -- arrays (int[], double[], String[]) -- to know the length of the arrays
length() -- String related Object (String, StringBuilder, etc) -- to know the length of the String
size() -- Collection Object (ArrayList, Set, etc) -- to know the size of the Collection
Now forget about length() consider just length and size().
length is not a method, so it completely makes sense that it will not work on objects. It only works on arrays.
size() its name describes it better and as it is a method, it will be used in the case of those objects who work with collection (collection frameworks) as I said up there.
Now come to length():
String is not a primitive array (so we can't use .length) and also not a Collection (so we cant use .size()) that's why we also need a different one which is length() (keep the differences and serve the purpose).
As answer to Why?
I find it useful, easy to remember and use and friendly.
Let me first highlight three different ways for similar purpose.
length -- arrays (int[], double[], String[]) -- to know the length of the arrays
length() -- String related Object (String, StringBuilder, etc) -- to know the length of the String
size() -- Collection Object (ArrayList, Set, etc) -- to know the size of the Collection
Now forget about length() consider just length and size().
length is not a method, so it completely makes sense that it will not work on objects. It only works on arrays.
size() its name describes it better and as it is a method, it will be used in the case of those objects who work with collection (collection frameworks) as I said up there.
Now come to length():
String is not a primitive array (so we can't use .length) and also not a Collection (so we cant use .size()) that's why we also need a different one which is length() (keep the differences and serve the purpose).
As answer to Why?
I find it useful, easy to remember and use and friendly.
A bit simplified you can think of it as arrays being a special case and not ordinary classes (a bit like primitives, but not). String and all the collections are classes, hence the methods to get size, length or similar things.
I guess the reason at the time of the design was performance. If they created it today they had probably come up with something like array-backed collection classes instead.
If anyone is interested, here is a small snippet of code to illustrate the difference between the two in generated code, first the source:
public class LengthTest {
public static void main(String[] args) {
int[] array = {12,1,4};
String string = "Hoo";
System.out.println(array.length);
System.out.println(string.length());
}
}
Cutting a way the not so important part of the byte code, running javap -c on the class results in the following for the two last lines:
20: getstatic #3; //Field java/lang/System.out:Ljava/io/PrintStream;
23: aload_1
24: arraylength
25: invokevirtual #4; //Method java/io/PrintStream.println:(I)V
28: getstatic #3; //Field java/lang/System.out:Ljava/io/PrintStream;
31: aload_2
32: invokevirtual #5; //Method java/lang/String.length:()I
35: invokevirtual #4; //Method java/io/PrintStream.println:(I)V
In the first case (20-25) the code just asks the JVM for the size of the array (in JNI this would have been a call to GetArrayLength()) whereas in the String case (28-35) it needs to do a method call to get the length.
In the mid 1990s, without good JITs and stuff, it would have killed performance totally to only have the java.util.Vector (or something similar) and not a language construct which didn't really behave like a class but was fast. They could of course have masked the property as a method call and handled it in the compiler but I think it would have been even more confusing to have a method on something that isn't a real class.
Variable length (Dynamic) Arrays in Java - Stack Overflow
java - Difference between size and length methods? - Stack Overflow
Getting the array length of a 2D array in Java - Stack Overflow
Was there a point of time when array.length is a O(N) operation in Java
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Yes: use ArrayList.
In Java, "normal" arrays are fixed-size. You have to give them a size and can't expand them or contract them. To change the size, you have to make a new array and copy the data you want - which is inefficient and a pain for you.
Fortunately, there are all kinds of built-in classes that implement common data structures, and other useful tools too. You'll want to check the Java 6 API for a full list of them.
One caveat: ArrayList can only hold objects (e.g. Integers), not primitives (e.g. ints). In MOST cases, autoboxing/autounboxing will take care of this for you silently, but you could get some weird behavior depending on what you're doing.
Arrays in Java are of fixed size. What you'd need is an ArrayList, one of a number of extremely valuable Collections available in Java.
Instead of
Integer[] ints = new Integer[x]
you use
List<Integer> ints = new ArrayList<Integer>();
Then to change the list you use ints.add(y) and ints.remove(z) amongst many other handy methods you can find in the appropriate Javadocs.
I strongly recommend studying the Collections classes available in Java as they are very powerful and give you a lot of builtin functionality that Java-newbies tend to try to rewrite themselves unnecessarily.
size() is a method specified in java.util.Collection, which is then inherited by every data structure in the standard library. length is a field on any array (arrays are objects, you just don't see the class normally), and length() is a method on java.lang.String, which is just a thin wrapper on a char[] anyway.
Perhaps by design, Strings are immutable, and all of the top-level Collection subclasses are mutable. So where you see "length" you know that's constant, and where you see "size" it isn't.
length is constant which is used to find out the array storing capacity not the number of elements in the array
Example:
int[] a = new int[5]
a.length always returns 5, which is called the capacity of an array. But
number of elements in the array is called size
Example:
int[] a = new int[5]
a[0] = 10
Here the size would be 1, but a.length is still 5. Mind that there is no actual property or method called size on an array so you can't just call a.size or a.size() to get the value 1.
The size() method is available for collections, length works with arrays in Java.
Consider
public static void main(String[] args) {
int[][] foo = new int[][] {
new int[] { 1, 2, 3 },
new int[] { 1, 2, 3, 4},
};
System.out.println(foo.length); //2
System.out.println(foo[0].length); //3
System.out.println(foo[1].length); //4
}
Column lengths differ per row. If you're backing some data by a fixed size 2D array, then provide getters to the fixed values in a wrapper class.
A 2D array is not a rectangular grid. Or maybe better, there is no such thing as a 2D array in Java.
import java.util.Arrays;
public class Main {
public static void main(String args[]) {
int[][] test;
test = new int[5][];//'2D array'
for (int i=0;i<test.length;i++)
test[i] = new int[i];
System.out.println(Arrays.deepToString(test));
Object[] test2;
test2 = new Object[5];//array of objects
for (int i=0;i<test2.length;i++)
test2[i] = new int[i];//array is a object too
System.out.println(Arrays.deepToString(test2));
}
}
Outputs
[[], [0], [0, 0], [0, 0, 0], [0, 0, 0, 0]]
[[], [0], [0, 0], [0, 0, 0], [0, 0, 0, 0]]
The arrays test and test2 are (more or less) the same.
So I remember my professor back in college tell me that in Java array.length is an O(N) operation, since the implementation would need to go through the array to count everything. That is why I should keep the array length in a variable so that I only call array.length once.
Recently this was brought up in a conversation, and I looked it up. Array.length is a O(1) operation since the length is just a property. My professor was old, so perhaps back in the day, it was a true statement?
Edit: there might be a chance that I misremembered, and it was arraylist. Though arraylist.length should still be O(1), unless it wasn't at some point?