Replace forEach with map.

 items.stream()
      .filter(s-> s.contains("B"))
      .map(s-> {s.setState("ok");return s;})
      .collect(Collectors.toList());

forEach and collect are both terminal operations - Streams must have just one. Anything that returns a Stream<T> is a intermediate operation, anything other is a terminal operation.

While Lino's answer is certainly correct. I would argue that if a given person object in jrList can only ever have one corresponding match in seniorList maximum, in other words, if it's a 1-1 relationship then you can improve upon the solution given by Lino by finding the first match as follows:

List<PersonWrapper> resultSet = jrList.stream()
                .map(p -> seniorList.stream()
                        .filter(sr -> p.getName().equals(sr.getName()))
                        .findFirst()
                        .map(q -> new PersonWrapper(p, q))
                        .get())
                .collect(Collectors.toList());

or if there is no guarantee that each person in jrList will have a corresponding match in seniorList then change the above query to:

List<PersonWrapper> resultSet = jrList.stream()
                .map(p -> seniorList.stream()
                        .filter(sr -> p.getName().equals(sr.getName()))
                        .findFirst()
                        .map(q -> new PersonWrapper(p, q))
                        .orElse(null))
                .filter(Objects::nonNull)
                .collect(Collectors.toList());

The difference is that now instead of calling get() on the result of findFirst() we provide a default with orElse in case findFirst cannot find the corresponding value and then we filter the null values out in the subsequent intermediate operation as they are not needed.