You can do it specifying the characters you want to remove:

string = string.replace(/[&\/\\#,+()$~%.'":*?<>{}]/g, '');

Alternatively, to change all characters except numbers and letters, try:

string = string.replace(/[^a-zA-Z0-9]/g, '');

Note that if you still want to exclude a set, including things like slashes and special characters you can do the following:

var outString = sourceString.replace(/[`~!@#$%^&*()_|+\-=?;:'",.<>\{\}\[\]\\\/]/gi, '');

take special note that in order to also include the "minus" character, you need to escape it with a backslash like the latter group. if you don't it will also select 0-9 which is probably undesired.

To remove the special characters, try

var name = name.replace(/[!@#$%^&*]/g, "");

Use this regex:

const regex = /\('([^']+)',\)/g

const output = input.replace(regex, '$1');

//   explain:  /  \(  '  (   [^']+  )  ',\)  /  g

//             1   2  3  4    5     6   7    8  9

• 1: start regex
• 2: match character ( (character / to escape)
• 3: match character '
• 4: start group in regex
• 5: match character not '
• 6: close group in regex
• 7: match ',)
• 8: end regex
• 9: make this regex match global (don't need if you want replace one time)
• $1 in code is first group match regex (start with 4 and end with 6)

const input = `('FCA',)
('JP NIC',)
('JP CHI',)
('2022-03-04T07:18:36.468Z',)`;

const output = input.replace(/\('([^']+)',\)/g, '$1');

console.log(input)
console.log('// =>')
console.log(output)

var str = "ABC/D A.b.c.;Qwerty";
var result = str.replace(/[^A-Za-z;]/g, "");​​ // 21ABCDAbc;Qwerty

Live DEMO

Honestly I think this probably the most concise and least confusing, but maybe that is just me:

str = "F0123456";
str.replace("f0", "");

Dont even go the regular expression route and simply do a straight replace.