As ZdaR's post illustrates, to create a json, you need to build the corresponding Python data structure (lists for json arrays, dictionaries for json objects) and serialize it at the end. So the question is almost the same as how to create a list in a loop, because after creating the list, what remains is serialization which is as simple as json.loads(data).

The task in the OP can be done in two loops:

data = [{'Title': line.getText(strip=True)} for line in games_html.findAll('a')]

for i, line in enumerate(games_html.findAll('div', class_="product_score")):
    data[i]['Score'] = line.getText(strip=True)

# serialize to json array
j = json.dumps(data)

# or write to a file
with open('data.json', 'w') as f:
    json.dump(data, f)

Your JSON file is incorrect. Normally you must have a structure as:

{
    "key1": [
        {
            "id": "blabla",
            "name": "Toto"
        },
        {
            "id": "blibli",
            "name": "Tata"
        }
    ],
    "key2": {
        "id": "value"
    },
    "key3": "value"
}

So I think you have to change your JSON array for example as following:

{
    [
        {
            "id": 0,
            "organizer": "Some Name",
            "eventStart": "09:30 AM",
            "eventEnd": "10:00 AM",
            "subject": "rental procedure",
            "attendees": "Some Name<br />Person 2<br />Person 3"
        },
        {
            "id": 1,
            "organizer": "Some Name",
            "eventStart": "09:30 AM",
            "eventEnd": "10:00 AM",
            "subject": "rental procedure",
            "attendees": "Some Name<br />Person 2<br />Person 3"
        },
        {
            "id": 2,
            "organizer": "Some Name",
            "eventStart": "09:30 AM",
            "eventEnd": "10:00 AM",
            "subject": "rental procedure",
            "attendees": "Some Name<br />Person 2<br />Person 3"
        }
    ]
}

You can decide also to have not a list of dictionary as I proposed above but to use the ID value as key for each dictionary; in that case you have:

{
    "id0":{       
            "organizer": "Some Name",
            "eventStart": "09:30 AM",
            "eventEnd": "10:00 AM",
            "subject": "rental procedure",
            "attendees": "Some Name<br />Person 2<br />Person 3"
    },
    "id1":{       
            "organizer": "Some Name",
            "eventStart": "09:30 AM",
            "eventEnd": "10:00 AM",
            "subject": "rental procedure",
            "attendees": "Some Name<br />Person 2<br />Person 3"
    },
    "id2":{       
            "organizer": "Some Name",
            "eventStart": "09:30 AM",
            "eventEnd": "10:00 AM",
            "subject": "rental procedure",
            "attendees": "Some Name<br />Person 2<br />Person 3"
    }
}

Another simple solution, using enumerate:

import json

arr_of_id_by_user = [1, 2, 3]
arr_of_wallet_amount = [100,3400,200]

jsonfile=[]

for index, value in enumerate(arr_of_id_by_user):
    jsonfile.append({
        "user": value,
        "waller_amount": arr_of_wallet_amount[index]
    }) 

print (json.dumps(jsonfile, indent=4))

As explained by others (in answers) you should create a new dictionary for each item on the list elsewhere you reference always the same dictionary

import json
part_nums = ['ECA-1EHG102','CL05B103KB5NNNC','CC0402KRX5R8BB104']

def json_list(list):
    lst = []
    for pn in list:
        d = {}
        d['mpn']=pn
        lst.append(d)
    return json.dumps(lst)

print json_list(part_nums)

print

[{"mpn": "ECA-1EHG102"}, {"mpn": "CL05B103KB5NNNC"}, {"mpn": "CC0402KRX5R8BB104"}]

Try to Google this kind of stuff first. :)

import json

array = [1, 2, 3]
jsonArray = json.dumps(array)

By the way, the result you asked for can not be achieved with the list you provided.

You need to use python dictionaries to get json objects. The conversion is like below

Python -> JSON
list -> array
dictionary -> object

And here is the link to the docs https://docs.python.org/3/library/json.html

To solve this, you need to split the input list into chunks, by 7 in your case. For this, let's use this approach. Then, use a list comprehension producing a list of dictionaries:

>>> from pprint import pprint
>>> l = [['String 1'],['String 2'],['String 3'],['String 4'],['String 5'],
... ['String 6'],['String 7'],['String 8'],['String 9'],['String 10'],
... ['String 11']]
>>> def chunks(l, n):
...     """Yield successive n-sized chunks from l."""
...     for i in range(0, len(l), n):
...         yield l[i:i+n]
... 
>>>
>>> result = [{"title%d" % (i+1): chunk[i][0] for i in range(len(chunk))} 
              for chunk in chunks(l, 7)]
>>> pprint(result)
[{'title1': 'String 1',
  'title2': 'String 2',
  'title3': 'String 3',
  'title4': 'String 4',
  'title5': 'String 5',
  'title6': 'String 6',
  'title7': 'String 7'},
 {'title1': 'String 8',
  'title2': 'String 9',
  'title3': 'String 10',
  'title4': 'String 11'}]