slices to the rescue :)
def left(s, amount):
return s[:amount]
def right(s, amount):
return s[-amount:]
def mid(s, offset, amount):
return s[offset:offset+amount]
Answer from Andy W on Stack Overflowslices to the rescue :)
def left(s, amount):
return s[:amount]
def right(s, amount):
return s[-amount:]
def mid(s, offset, amount):
return s[offset:offset+amount]
If I remember my QBasic, right, left and mid do something like this:
>>> s = '123456789'
>>> s[-2:]
'89'
>>> s[:2]
'12'
>>> s[4:6]
'56'
http://www.angelfire.com/scifi/nightcode/prglang/qbasic/function/strings/left_right.html
context. Given a string, return a new string where the first and last chars have been exchanged.
their answer
def front_back(str):
if len(str) <= 1:
return str
mid = str[1:len(str)-1] # can be written as str[1:-1]
# last + mid + first
return str[len(str)-1] + mid + str[0]
» pip install python-mid
Here's an example of how I would approach it:
def mid(string):
if len(string) % 2 == 0:
return ""
else:
offset = int(len(string) / 2)
return string[offset: offset + 1]
mid("abc")
mid("asaba")
Your code fails on edge cases, specifically when given the empty string, but I found during my tests that it works for strings like "asaba", "aaaa", and "abc" but throws the error when given "". The reason for this is because lastnum = enum[-1][0] + 1 will give an index that does not exist for the empty string. The way to fix this would be to add a condition at the beginning of your function that checks if it's an empty string, so like this:
if len(string) == 0:
return ""