The hex() function converts a specified integer number into a hexadecimal string representation.

Use int(x, base) with 16 as base to convert the string x to an integer. Call hex(number) with the integer as number to convert it to hexadecimal.

hex_string = "0xAA"

"0x" also required

an_integer = int(hex_string, 16)

hex_value = hex(an_integer)

print(hex_value)

Output

0xaa

We can try this:

frame = "AAA555AAA555AAA555AAA555AAA555AAA555AAA555AAA555AAA555AAA555AAA"
[int(character, 16) for character in frame]
# [10, 10, 10, 5, 5, 5, 10, 10, 10, 5, ... ]

As @Reti43 notes in a comment, hexadecimal values like 0xA correspond to numbers like 10, so that's why the resulting list has integers.

If the OP desires hexadecimal, string representation can be used as below. This string can then be passed to int to get the corresponding integer.

frame = "AAA555AAA555AAA555AAA555AAA555AAA555AAA555AAA555AAA555AAA555AAA"
[f"0x{character}" for character in frame]
# ['0xA', '0xA', '0xA', '0x5', '0x5', '0x5', '0xA', '0xA', '0xA', '0x5', ...]

You could range(..) over substrings of length 2:

c = '8db6796fee32785e366f710df10cc' 
c2=[int(c[i:i+2],16) for i in range(0,len(c),2)]

So i iterates of the string with steps of 2 and you take a substring of length 2 from i to i+2 (exclusive) with c[i:i+2]. These you convert by taking int(..,16).

For your sample input it generates:

>>> c='8db6796fee32785e366f710df10cc'
>>> [int(c[i:i+2],16) for i in range(0,len(c),2)]
[141, 182, 121, 111, 238, 50, 120, 94, 54, 111, 113, 13, 241, 12, 12]

The last element is 12 because the length of your string is odd, so it takes c as the last element to parse.

If you're using Python 3.5+ you can use the bytes.fromhex method to convert hex string to bytes, and use the list constructor to convert bytes into a list of integers:

>>> list(bytes.fromhex('7f33117cf266a525'))
[127, 51, 17, 124, 242, 102, 165, 37]

And you can use the bytes constructor to convert a list of integers to bytes, and use the bytes.hex method to convert bytes to hex string:

>>> bytes([127, 51, 17, 124, 242, 102, 165, 37]).hex()
'7f33117cf266a525'

Suppose your hex string is something like

>>> hex_string = "deadbeef"

Convert it to a bytearray (Python 3 and 2.7):

>>> bytearray.fromhex(hex_string)
bytearray(b'\xde\xad\xbe\xef')

Convert it to a bytes object (Python 3):

>>> bytes.fromhex(hex_string)
b'\xde\xad\xbe\xef'

Note that bytes is an immutable version of bytearray.

Convert it to a string (Python ≤ 2.7):

>>> hex_data = hex_string.decode("hex")
>>> hex_data
"\xde\xad\xbe\xef"