def tt(w): 
    if ' ' in w: 
       print 'space' 
    else: 
       print 'no space' 

>>   tt('b ')
>> space
>>  tt('b b')
>> space
>>  tt('bb')
>> no space

I am in train, sorry for not explaining.. cannot type much..

I don't think the str.isspace, str.isalpha and str.isdigit methods do what you expect them to do. To start with, they all test if all the characters in the string you enter are of the type that is described in their name. Your code seems to be expecting them to be return True if any of the characters match. That is, if there are any spaces, you want to remove them and show the two lengths, before and after.

There's no single string method that will do that test for you in Python. You could use regular expressions (which are more powerful, but much more complicated), or you could write some slightly more elaborate code to do the test. I'd suggest using the any function, and passing it a generator expression that calls the method you want on each character in the string.

if any(c.isspace() for c in user_str):
    ...

This may not be exactly what you want for all of your tests. The desired logic of your code is not entirely obvious, as there are a number of corner cases that your output doesn't specifically address. Is a string that contains both letters and numbers valid? How about one that has spaces in between numbers, but no letters at all? You may need to reorder the conditions of your if/elif/else statements so that they match what you intend.

I'd also note that the variable name you used for user input, new_length, is very misleading. It's not a length, its the string you want to measure the length of! It's a lot easier to make logic errors about variables that have misleading or unclear variable names, so taking time to go back and reconsider names you chose earlier is sometimes a good idea, as it can improve the clarity of your code a lot! Descriptive variable names are good, but it's a tradeoff between clarity and brevity, as long names are tedious to type (and prone to typos). They also can lead to line length issues, which can make it less convenient to see all your code on your editor screen at once.

You want non whitespace, so you should use not

def get_num_of_non_WS_characters(s):
    count = 0
    for char in s:
        if not char.isspace():
            count += 1
    return count

>>> get_num_of_non_WS_characters('hello')
5
>>> get_num_of_non_WS_characters('hello  ')
5

For completeness, this could be done more succinctly using a generator expression

def get_num_of_non_WS_characters(s):
    return sum(1 for char in s if not char.isspace())