You haven't created three different empty lists. You've created one empty list, and then created a new list with three references to that same empty list. To fix the problem use this code instead:
listy = [[] for i in range(3)]
Running your example code now gives the result you probably expected:
>>> listy = [[] for i in range(3)]
>>> listy[1] = [1,2]
>>> listy
[[], [1, 2], []]
>>> listy[1].append(3)
>>> listy
[[], [1, 2, 3], []]
>>> listy[2].append(1)
>>> listy
[[], [1, 2, 3], [1]]
Answer from Mark Byers on Stack OverflowYou haven't created three different empty lists. You've created one empty list, and then created a new list with three references to that same empty list. To fix the problem use this code instead:
listy = [[] for i in range(3)]
Running your example code now gives the result you probably expected:
>>> listy = [[] for i in range(3)]
>>> listy[1] = [1,2]
>>> listy
[[], [1, 2], []]
>>> listy[1].append(3)
>>> listy
[[], [1, 2, 3], []]
>>> listy[2].append(1)
>>> listy
[[], [1, 2, 3], [1]]
[[]]*3 is not the same as [[], [], []].
It's as if you'd said
a = []
listy = [a, a, a]
In other words, all three list references refer to the same list instance.
do you guys know how to add append an array in a 2d array?
Two dimensional array in python - Stack Overflow
Python: Appending numerous 2D list to one 2D list - Stack Overflow
python 2D list appends the element to every list in it - Stack Overflow
say i have array [[1,2,3,4,5]], how can i duplicate it 5 times to [[1,2,3,4,5],[1,2,3,4,5],[1,2,3,4,5],[1,2,3,4,5],[1,2,3,4,5]] ?
You do not "declare" arrays or anything else in python. You simply assign to a (new) variable. If you want a multidimensional array, simply add a new array as an array element.
arr = []
arr.append([])
arr[0].append('aa1')
arr[0].append('aa2')
or
arr = []
arr.append(['aa1', 'aa2'])
There aren't multidimensional arrays as such in Python, what you have is a list containing other lists.
>>> arr = [[]]
>>> len(arr)
1
What you have done is declare a list containing a single list. So arr[0] contains a list but arr[1] is not defined.
You can define a list containing two lists as follows:
arr = [[],[]]
Or to define a longer list you could use:
>>> arr = [[] for _ in range(5)]
>>> arr
[[], [], [], [], []]
What you shouldn't do is this:
arr = [[]] * 3
As this puts the same list in all three places in the container list:
>>> arr[0].append('test')
>>> arr
[['test'], ['test'], ['test']]
You can iterate through the items of the lists and then add them to your masterlist:
a = [[1,2,3],
[1,2,3]]
b = [[4,5,6],
[4,5,6]]
masterlist = []
for aa,bb in zip(a,b): # loop over lists
for itema, itemb in zip(aa,bb): # loop over items in list
masterlist = masterlist + [[itema, itemb]]
output:
[[1, 4], [2, 5], [3, 6], [1, 4], [2, 5], [3, 6]]
If you use numpy,this is really easy
import numpy as np
a = np.array([[1,2,3],
[1,2,3]])
b = np.array([[4,5,6],
[4,5,6]])
fl = np.vstack(np.dstack((a,b)))
output
array([[1, 4],
[2, 5],
[3, 6],
[1, 4],
[2, 5],
[3, 6]])
def main():
how_many = int(raw_input("How many to enter? "))
counter = 0
list = []
while counter < how_many:
name = raw_input("Enter the Name ")
first_val = int(raw_input("Enter first_val "))
first_val2 = int(raw_input("Enter first_val2 "))
sec_val = int(raw_input("Enter sec_val "))
sec_val2 = int(raw_input("Enter sec_val2 "))
list.append([[name], [first_val, first_val2], [sec_val, sec_val2]])
counter = counter + 1
Assume we are reading the values from stdin (as in the question body)
you can use lists:
list = []
....
list.append([[name], [first_val, first_val2], [sec_val, sec_val2]])
but a tuple seems to be a better fit here:
t = (name, (first_val, first_val2), (sec_val, sec_val2))
list.append(t)
Since the values are not likely to change, a tuple feels like the better choice.
Think about how a field would be accessed in each case:
list:
name = list[i][0][0]
tuple:
name = list[i][0]
Again...it just seem more natural...