Take a look at this tutorial. Also you can parse above json like :

JSONArray arr = new JSONArray(yourJSONresponse);
List<String> list = new ArrayList<String>();
for(int i = 0; i < arr.length(); i++){
    list.add(arr.getJSONObject(i).getString("name"));
}

Use gson. It's got a much friendlier API than org.json.

Collections Examples (from the User Guide):

Gson gson = new Gson();
Collection<Integer> ints = Lists.immutableList(1,2,3,4,5);

//(Serialization)
String json = gson.toJson(ints); ==> json is [1,2,3,4,5]

//(Deserialization)
Type collectionType = new TypeToken<Collection<Integer>>(){}.getType();
Collection<Integer> ints2 = gson.fromJson(json, collectionType);
//ints2 is same as ints

Here you get JSONObject so change this line:

JSONArray jsonArray = new JSONArray(readlocationFeed); 

with following:

JSONObject jsnobject = new JSONObject(readlocationFeed);

and after

JSONArray jsonArray = jsnobject.getJSONArray("locations");
for (int i = 0; i < jsonArray.length(); i++) {
    JSONObject explrObject = jsonArray.getJSONObject(i);
}

The problem is not the JSONArray.toString(), as @Selvin mentioned.

From JSONArray source:

/**
 * Encodes this array as a compact JSON string, such as:
 * <pre>[94043,90210]</pre>
 */
@Override public String toString() {
    try {
        JSONStringer stringer = new JSONStringer();
        writeTo(stringer);
        return stringer.toString();
    } catch (JSONException e) {
        return null;
    }
}

/**
 * Encodes this array as a human readable JSON string for debugging, such
 * as:
 * <pre>
 * [
 *     94043,
 *     90210
 * ]</pre>
 *
 * @param indentSpaces the number of spaces to indent for each level of
 *     nesting.
 */
public String toString(int indentSpaces) throws JSONException {
    JSONStringer stringer = new JSONStringer(indentSpaces);
    writeTo(stringer);
    return stringer.toString();
}

The problem is that you need to convert your ChecklistAnswer to JSON object first for your JSONArray to work properly.

Again from Javadoc:

/**
 * A dense indexed sequence of values. Values may be any mix of
 * {@link JSONObject JSONObjects}, other {@link JSONArray JSONArrays}, Strings,
 * Booleans, Integers, Longs, Doubles, {@code null} or {@link JSONObject#NULL}.
 * Values may not be {@link Double#isNaN() NaNs}, {@link Double#isInfinite()
 * infinities}, or of any type not listed here.

...

Look like you want to store name and location in an array, if yes then

for(int i=0; i < jLocation.length(); i++){
    arr[0] = jLocation.getJSONObject(i).getString("name");
    arr[1] = jLocation.getJSONObject(i).getString("location");
} 

Note - This code assume that you only have one name and location. However I sugegst you to do something like below:

Create a Location class, e.g. below

public class Location {
    private String name;
    private String location;

    public Location(String name, String location) {
        this.name = name;
        this.location = location;
    }

    public String getName() {
        return name;
    }

    public String getLocation() {
        return location;
    }
}

Then use it like below:

public static void main(String[] args) {
        List<Location> locations = new ArrayList<Location>();

        for(int i=0; i < jLocation.length(); i++){
            String name = jLocation.getJSONObject(i).getString("name");
            String location = jLocation.getJSONObject(i).getString("location");

            locations.add(new Location(name, location));
        } 
    }

Issue is here:

JSONArray myjsonarray = myjson.toJSONArray(temparray); 

Solution:

JSONArray myjsonarray = new JSONArray(myJSON);   
// myJSON is String

Now here you are having JSONArray, iterate over it and prepare ArrayList of whatever types of you want.

Something like this:

ArrayList<String> jsonStringToArray(String jsonString) throws JSONException {

    ArrayList<String> stringArray = new ArrayList<String>();

    JSONArray jsonArray = new JSONArray(jsonString);

    for (int i = 0; i < jsonArray.length(); i++) {
        stringArray.add(jsonArray.getString(i));
    }

    return stringArray;
}

For anyone else who might need this:

String jsonString = "[\"string1\",\"string2\",\"string3\"]";
ObjectMapper mapper = new ObjectMapper();
List<String> strings = mapper.readValue(jsonString, List.class);

To have a string value inside your JSON array, you must remember to backslash escape your double-quotes in your Java program. See the declaration of s below.

String s = "[[\"110917       \", 3.0099999999999998, -0.72999999999999998, 2.8500000000000001, 2.96, 685.0, 38603.0], [\"110917    \", 2.71, 0.20999999999999999, 2.8199999999999998, 2.8999999999999999, 2987.0, 33762.0]]";

Your code in the main() method works fine. Below is just a minor modification of your code in the main() method.

System.out.println("String to Json Array Stmt");
JsonParser parser = new JsonParser();
JsonElement tradeElement = parser.parse(s);
JsonArray trade = tradeElement.getAsJsonArray();
System.out.println(trade);

Lastly, remember to prefix your statement "com.google.gson.*" with the keyword "import", as shown below.

import com.google.gson.*;

Using a stream you could convert it like so:

String s = "[\"A\",\"B\",\"C\",\"D\",\"E\"]";
String[] arr = Arrays.stream(s.substring(1, s.length()-1).split(","))
                .map(e -> e.replaceAll("\"", ""))
                .toArray(String[]::new);

You could also use a JSON library (which might be the prefered way). For example using Jackson:

String s = "[\"A\",\"B\",\"C\",\"D\",\"E\"]";
ObjectMapper mapper = new ObjectMapper();
String[] arr = mapper.readValue(s, String[].class);