Is this what you want?

echo json_encode($artists)

PHP: json_encode

Try

json_decode(stripslashes($_COOKIE['data']));

First off, it's worth pointing out that PHP is not "messing up" anything. It's escaping characters, which may look weird, but it is perfectly valid and when you json_decode it later it will be just the same as it was originally. See here: https://3v4l.org/Smj2F

If you don't like the escaping though, you can use the JSON_UNESCAPED_UNICODE flag:

https://www.php.net/function.json-encode

This flag will "encode multibyte Unicode characters literally" according to https://www.php.net/manual/en/json.constants.php.

So you can do:

json_encode($array, JSON_UNESCAPED_UNICODE);

And it will give you the following output:

["M-am întîlnit ieri cu","fosta mea profă de matematică"]

Working example: https://3v4l.org/daETG

When you save some data using JSON.stringify() and then need to read that in php. The following code worked for me.

json_decode( html_entity_decode( stripslashes ($jsonString ) ) );

Thanks to @Thisguyhastwothumbs

If you are not using dataType : 'json', you might need to do stripslashes

$.post(window.data.baseUrl, {posts : JSON.stringify(posts)});

And in php:

$posts = json_decode(stripslashes($_POST['posts']));

First make sure that $locationinfo is exactly a json string. I suspect it is a php associative array.

Try echo $locationinfo['id'];. If value appears u don't want to decode it. Use $locationinfo directly withot json decode.

If it is a json, Try using like this,

$arr = json_decode($locationinfo, true);