Assuming you meant to find the phrase "The rain falls in Spain" within a larger string:

import re

t = "Hello G'day. The rain falls in Spain. Testing 123."
x = re.search("The.*Spain", t)

if x:
  print("There's a match!")
  print(f'The match is: {x.group(0)!r}')
  print('The span is:', x.span(0))
else:
  print("There's no match")

print(x)

Output:

There's a match!
The match is: 'The rain falls in Spain'
The span is: (13, 36)
<re.Match object; span=(13, 36), match='The rain falls in Spain'>

What did I change:

• I removed ^$ from the regex, because we don't want to check for the start and end of a string explicitly. The desired match can also be somewhere within the string as well.
• Access a captured group number n using the syntax x.group(n). In the above example, you can also use x.group() as a shortcut to get the first captured group (i.e. the first match)
• Access the start/end indices within the input string, of a captured group n (i.e. a match), using the syntax x.span(n). Similarly as above, you can use x.span() as a shortcut to get the span of the first match.

You should use re.MatchObject.group(0). Like

imtag = re.match(r'<img.*?>', line).group(0)

Edit:

You also might be better off doing something like

imgtag  = re.match(r'<img.*?>',line)
if imtag:
    print("yo it's a {}".format(imgtag.group(0)))

to eliminate all the Nones.