Using Math.round() will round the float to the nearest integer.

Answer from tw39124 on Stack Overflow
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Using Math.round() will round the float to the nearest integer.

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Actually, there are different ways to downcast float to int, depending on the result you want to achieve: (for int i, float f)

  • round (the closest integer to given float)

    i = Math.round(f);
      f =  2.0 -> i =  2 ; f =  2.22 -> i =  2 ; f =  2.68 -> i =  3
      f = -2.0 -> i = -2 ; f = -2.22 -> i = -2 ; f = -2.68 -> i = -3
    

    note: this is, by contract, equal to (int) Math.floor(f + 0.5f)

  • truncate (i.e. drop everything after the decimal dot)

    i = (int) f;
      f =  2.0 -> i =  2 ; f =  2.22 -> i =  2 ; f =  2.68 -> i =  2
      f = -2.0 -> i = -2 ; f = -2.22 -> i = -2 ; f = -2.68 -> i = -2
    
  • ceil/floor (an integer always bigger/smaller than a given value if it has any fractional part)

    i = (int) Math.ceil(f);
      f =  2.0 -> i =  2 ; f =  2.22 -> i =  3 ; f =  2.68 -> i =  3
      f = -2.0 -> i = -2 ; f = -2.22 -> i = -2 ; f = -2.68 -> i = -2
    
    i = (int) Math.floor(f);
      f =  2.0 -> i =  2 ; f =  2.22 -> i =  2 ; f =  2.68 -> i =  2
      f = -2.0 -> i = -2 ; f = -2.22 -> i = -3 ; f = -2.68 -> i = -3
    

For rounding positive values, you can also just use (int)(f + 0.5), which works exactly as Math.Round in those cases (as per doc).

You can also use Math.rint(f) to do the rounding to the nearest even integer; it's arguably useful if you expect to deal with a lot of floats with fractional part strictly equal to .5 (note the possible IEEE rounding issues), and want to keep the average of the set in place; you'll introduce another bias, where even numbers will be more common than odd, though.

See

http://mindprod.com/jgloss/round.html

http://docs.oracle.com/javase/6/docs/api/java/lang/Math.html

for more information and some examples.

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