It is an error (see my comment). You can graph
on Desmos.com by looking at the complement of
The Unshaded region below is the graph of your equation.
Alternatively, taking the complement of
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Inspired by the "absolute value of x without using absolute value" I thought I'd try to do the floor and ceiling function. Not an exact solution but it was fun!
It is an error (see my comment). You can graph
on Desmos.com by looking at the complement of
The Unshaded region below is the graph of your equation.
Alternatively, taking the complement of
It is not difficult to show that 
if and only if 
.
Try graphing in Desmos
Desmos does not show it accurately on the boundaries, however.
It is also the case that 
if and only if 
, but Desmos errs once again on the boundary.
i am looking to graph the integer-only line, but whenever i try to type [[]], it tells me that you cannot store a list of numbers in a list.
The graph is a little misleading. It only includes the "flat" parts, not the "diagonal" segments connecting them.
The complete graph is the union of the horizontal half-open segments
$$\left(\bigcup_{n\in\mathbb{N}}[n^2,n^2+n)\times\{n\}\right)\cup\left(\bigcup_{n\in\mathbb{N}}(n^2-n,n^2]\times\{-n\}\right)$$
The first union comprises segments above the x-axis, and the second comprises those below the x-axis. As you move to the right, each segment is one unit longer and one unit higher (lower, for segments below the x-axis) than the previous segment. There is a longer and longer gap between segments. Ignore the diagonal "connectors" in your graph and it is right.
floor(x/y) is the integer $n$ satisfying:
$$n \le \frac{x}{y} < n + 1$$
If $n = y$, then:
$$y \le \frac{x}{y} < y + 1$$
If $y > 0$, then:
$$y^2 \le x < y^2 + y$$ $$\frac{-1 + \sqrt{1+4x}}{2} < y \le \sqrt{x}$$
If $y < 0$, then:
$$y^2 \ge x > y^2 + y$$ $$y^2 + y < x \le y^2$$ $$-\sqrt{x} \le y < \frac{-1 - \sqrt{1+4x}}{2}$$
So, you get a graph that's similar to $y = \pm \sqrt{x}$ (with both positive and negative branches), except that $y$ takes on only nonzero integer values.