You haven't specified a scale for the result. Please try this
2019 Edit: Updated answer for JDK 13. Cause hopefully you've migrated off of JDK 1.5 by now.
import java.math.BigDecimal;
import java.math.RoundingMode;
public class Main {
public static void main(String[] args) {
BigDecimal a = new BigDecimal("1");
BigDecimal b = new BigDecimal("3");
BigDecimal c = a.divide(b, 2, RoundingMode.HALF_UP);
System.out.println(a + "/" + b + " = " + c);
}
}
Please read JDK 13 documentation.
Old answer for JDK 1.5 :
import java.math.*;
public class x
{
public static void main(String[] args)
{
BigDecimal a = new BigDecimal("1");
BigDecimal b = new BigDecimal("3");
BigDecimal c = a.divide(b,2, BigDecimal.ROUND_HALF_UP);
System.out.println(a+"/"+b+" = "+c);
}
}
this will give the result as 0.33. Please read the API
Answer from Rohan Grover on Stack OverflowBigDecimal division
Bigdecimal division problem
Dividing BigDecimal field by String field - Products - Jaspersoft Community
java - BigDecimal divide method either returns 0 or ArithmeticException? - Stack Overflow
You haven't specified a scale for the result. Please try this
2019 Edit: Updated answer for JDK 13. Cause hopefully you've migrated off of JDK 1.5 by now.
import java.math.BigDecimal;
import java.math.RoundingMode;
public class Main {
public static void main(String[] args) {
BigDecimal a = new BigDecimal("1");
BigDecimal b = new BigDecimal("3");
BigDecimal c = a.divide(b, 2, RoundingMode.HALF_UP);
System.out.println(a + "/" + b + " = " + c);
}
}
Please read JDK 13 documentation.
Old answer for JDK 1.5 :
import java.math.*;
public class x
{
public static void main(String[] args)
{
BigDecimal a = new BigDecimal("1");
BigDecimal b = new BigDecimal("3");
BigDecimal c = a.divide(b,2, BigDecimal.ROUND_HALF_UP);
System.out.println(a+"/"+b+" = "+c);
}
}
this will give the result as 0.33. Please read the API
import java.math.*;
class Main{
public static void main(String[] args) {
// create 3 BigDecimal objects
BigDecimal bg1, bg2, bg3;
MathContext mc=new MathContext(10,RoundingMode.DOWN);
bg1 = new BigDecimal("2.4",mc);
bg2 = new BigDecimal("32301",mc);
bg3 = bg1.divide(bg2,mc); // divide bg1 with bg2
String str = "Division result is " +bg3;
// print bg3 value
System.out.println( str );
}
}
giving wrong answer
For the class BigDemical, the calculation "divide" continue until the decimal terminates. This does not always happen, and with my program, it almost never does. However, I cannot find a way to specify the precision I want, that being 2^x for 0<x<35 bits of precision. I have read https://docs.oracle.com/javase/8/docs/api/java/math/BigDecimal.html, and it seems that it is possible to have arbitrary precision, but I cannot figure out how to specific any precision. I thought it might be divide(BigDecimal divisor, MathContext mc) , but this does not appear to be accurate enough. It caps out at 128, not 2^35. Does anyone know how I can specific the precision within 2N and N/2 digits for any N? Thanks and sorry if this has an obvious answer.