Assuming you have an array in a string format, you can use the following regex to match all the decimals and then use .map(Number)
const str = "['6.35', '2.72', '11.79', '183.25']",
array = str.match(/\d+(?:\.\d+)?/g).map(Number)
console.log(array)
Answer from adiga on Stack OverflowAssuming you have an array in a string format, you can use the following regex to match all the decimals and then use .map(Number)
const str = "['6.35', '2.72', '11.79', '183.25']",
array = str.match(/\d+(?:\.\d+)?/g).map(Number)
console.log(array)
\d matches only digits, it's the short for [0-9]. For example, in 6.35 \d+ matches 6 and then 35 separately and the dot is ignored. What you get in result is array containing those matches.
As suggested in other answers, use of match is redundant in your case and you can go with:
array.map(Number)
var intvalue = Math.floor( floatvalue );
var intvalue = Math.ceil( floatvalue );
var intvalue = Math.round( floatvalue );
// `Math.trunc` was added in ECMAScript 6
var intvalue = Math.trunc( floatvalue );
Math object reference
Examples
Positive// value=x // x=5 5<x<5.5 5.5<=x<6
Math.floor(value) // 5 5 5
Math.ceil(value) // 5 6 6
Math.round(value) // 5 5 6
Math.trunc(value) // 5 5 5
parseInt(value) // 5 5 5
~~value // 5 5 5
value | 0 // 5 5 5
value >> 0 // 5 5 5
value >>> 0 // 5 5 5
value - value % 1 // 5 5 5
Negative
// value=x // x=-5 -5>x>=-5.5 -5.5>x>-6
Math.floor(value) // -5 -6 -6
Math.ceil(value) // -5 -5 -5
Math.round(value) // -5 -5 -6
Math.trunc(value) // -5 -5 -5
parseInt(value) // -5 -5 -5
value | 0 // -5 -5 -5
~~value // -5 -5 -5
value >> 0 // -5 -5 -5
value >>> 0 // 4294967291 4294967291 4294967291
value - value % 1 // -5 -5 -5
Positive - Larger numbers
// x = Number.MAX_SAFE_INTEGER/10 // =900719925474099.1
// value=x x=900719925474099 x=900719925474099.4 x=900719925474099.5
Math.floor(value) // 900719925474099 900719925474099 900719925474099
Math.ceil(value) // 900719925474099 900719925474100 900719925474100
Math.round(value) // 900719925474099 900719925474099 900719925474100
Math.trunc(value) // 900719925474099 900719925474099 900719925474099
parseInt(value) // 900719925474099 900719925474099 900719925474099
value | 0 // 858993459 858993459 858993459
~~value // 858993459 858993459 858993459
value >> 0 // 858993459 858993459 858993459
value >>> 0 // 858993459 858993459 858993459
value - value % 1 // 900719925474099 900719925474099 900719925474099
Negative - Larger numbers
// x = Number.MAX_SAFE_INTEGER/10 * -1 // -900719925474099.1
// value = x // x=-900719925474099 x=-900719925474099.5 x=-900719925474099.6
Math.floor(value) // -900719925474099 -900719925474100 -900719925474100
Math.ceil(value) // -900719925474099 -900719925474099 -900719925474099
Math.round(value) // -900719925474099 -900719925474099 -900719925474100
Math.trunc(value) // -900719925474099 -900719925474099 -900719925474099
parseInt(value) // -900719925474099 -900719925474099 -900719925474099
value | 0 // -858993459 -858993459 -858993459
~~value // -858993459 -858993459 -858993459
value >> 0 // -858993459 -858993459 -858993459
value >>> 0 // 3435973837 3435973837 3435973837
value - value % 1 // -900719925474099 -900719925474099 -900719925474099
Bitwise OR operator
A bitwise or operator can be used to truncate floating point figures and it works for positives as well as negatives:
function float2int (value) {
return value | 0;
}
Results
float2int(3.1) == 3
float2int(-3.1) == -3
float2int(3.9) == 3
float2int(-3.9) == -3
Performance comparison?
I've created a JSPerf test that compares performance between:
Math.floor(val)val | 0bitwise OR~~valbitwise NOTparseInt(val)
that only works with positive numbers. In this case you're safe to use bitwise operations well as Math.floor function.
But if you need your code to work with positives as well as negatives, then a bitwise operation is the fastest (OR being the preferred one). This other JSPerf test compares the same where it's pretty obvious that because of the additional sign checking Math is now the slowest of the four.
Note
As stated in comments, BITWISE operators operate on signed 32bit integers, therefore large numbers will be converted, example:
1234567890 | 0 => 1234567890
12345678901 | 0 => -539222987
Great Question! I actually had to deal with this the other day! It may seem like a goto to just write parseInt but wait! we can be fancier.
So we can use bit operators for quite a few things and this seems like a great situation! Let's say I have the number from your question, 12.345, I can use the bit operator '~' which inverts all the bits in your number and in the process converts the number to an int! Gotta love JS.
So now we have the inverted bit representation of our number then if we '~' it again we get ........drum roll......... our number without the decimals! Unfortunately, it doesn't do rounding.
var a = 12.345;
var b = ~~a; //boom!
We can use Math.round() for that. But there you go! You can try it on JSperf to see the slight speed up you get! Hope that helps!
this is a good example i think
var intvalue = Math.floor( floatvalue );
var intvalue = Math.ceil( floatvalue );
var intvalue = Math.round( floatvalue );
You can do it directly from the ArrayBuffer
var dataAsInt16Array = new Int16Array(data.buffer);
var f32 = new Float32Array(4);
f32[0] = 0.1, f32[1] = 0.2, f32[2] = 0.3, f32[3] = 0.4;
// [0.10000000149011612, 0.20000000298023224, 0.30000001192092896, 0.4000000059604645]
var i16 = new Int16Array(f32.buffer);
// [-13107, 15820, -13107, 15948, -26214, 16025, -13107, 16076]
// and back again
new Float32Array(i16.buffer);
// [0.10000000149011612, 0.20000000298023224, 0.30000001192092896, 0.4000000059604645]
If you're after converting the raw underlying data you can use the approach Paul S. is describing in his answer.
But be aware of that you will not get the same numbers as you are dealing with 32-bit IEEE 754 representation of the number in the case of Float32. When a new view such as Int16 is used you are looking at the binary representation of that, not the original number.
If you are after the number you will have to convert manually, just modify your code to:
var data = ...; /*new Float32Array();*/
var len = data.length, i = 0;
var dataAsInt16Array = new Int16Array(len);
while(i < len)
dataAsInt16Array[i] = convert(data[i++]);
function convert(n) {
var v = n < 0 ? n * 32768 : n * 32767; // convert in range [-32768, 32767]
return Math.max(-32768, Math.min(32768, v)); // clamp
}
JavaScript only has a Number type that stores floating point values.
There is no int.
Edit:
If you want to format the number as a string with two digits after the decimal point use:
(4).toFixed(2)
toFixed() method formats a number using fixed-point notation. Read MDN Web Docs for full reference.
var fval = 4;
console.log(fval.toFixed(2)); // prints 4.00
After all the improvements/features and fixes which were made to javascript (or precisely ECMAScript) since ES6 (ES2015) till now (ES2022), isn't it about time to fix the ultimate pending weakness i.e. having an Integer and a Float type as well (just like "var" keyword was/is there but they added "let" and "const" as a better semantics and good practice) and not just mashup everything in Number.
Heck, we even got a big int to represent big integers (no floats allowed) but we still don't have Integer's and Floats which are SUPER useful in almost every scenario.
So, why is it still not added and not planned as well? Those are VERY important data types and MOST languages HAVE those data types as they are NEEDED, why is it not planned for ECMAScript? Is it planned? Do you want to see this added?