class consecutiveOnes
{

public int findMaxConsecutiveOnes(int[] nums) { //constructor that accepts as an argument an int array called nums.

        int maxHere = 0, max = 0; //int variable declarations initialized with zero.
        for (int n : nums) //for each loop. for int n in nums array:
            max = Math.max(max, maxHere = n == 0 ? 0 : maxHere +1); //ternary operator. max is assigned the math.max function (different use of max). max is the total max values consecutively. maxHere is the max value per n in the array.
                                                                    // This says if the larger of the two values (max, maxHere)

                                                                    // is zero, return zero and overwrite max with zero(this ensures the consecutive counter for 1 is reset), else increment maxHere by 1.
        return max;     //returns max
    }

    public static void main (String[] args)
    {
        consecutiveOnes co = new consecutiveOnes();

        int nums[] = {1, 0, 1, 1, 1, 1};

        //int n = nums.length;

        System.out.println("number of consecutive ones are: " +co.findMaxConsecutiveOnes(nums));

    }
}

I understand that the Math.max function returns the highest of two values (in this case, the highest of max and maxHere). Included are comments of what I believe is happening. What I don't understand is why the Math.max function is not returning 2 for max when for example, n in the array is 1. Would it not be the case since maxHere is incrementing by 1?

My rationalization is if n = 1, and maxhere +1 or increments by 1, then maxHere = 2 and new max value is 2, but that would not make sense, especially because consecutive count would be 2 at the first run of the loop...

EDIT: I apologize for the confusion. The code runs fine, but I have a limited understanding of why the Math.max function is choosing maxHere = 1 for max and not maxHere = 2 when maxHere = n =1 since maxHere + 1 would execute.

I need to compare 4 values and determine which one is biggest.