Put an l (lowercased letter L) directly before the specifier.
unsigned long n;
long m;
printf("%lu %ld", n, m);
Top answer 1 of 7
811
Put an l (lowercased letter L) directly before the specifier.
unsigned long n;
long m;
printf("%lu %ld", n, m);
2 of 7
208
I think you mean:
unsigned long n;
printf("%lu", n); // unsigned long
or
long n;
printf("%ld", n); // signed long
Microsoft Learn
learn.microsoft.com › en-us › cpp › c-runtime-library › format-specification-syntax-printf-and-wprintf-functions
Format Specification Syntax: `printf` and `wprintf` Functions | Microsoft Learn
Character and string arguments that are specified by using C and S are interpreted as wchar_t and wchar_t* by printf family functions, or as char and char* by wprintf family functions. This behavior is Microsoft-specific. For historical reasons, the wprintf functions use c and s to refer to wchar_t characters, and C and S specify narrow characters. Integer types such as short, int, long, long long, and their unsigned variants, are specified by using d, i, o, u, x, and X.
Printf long long int in C with GCC? - Stack Overflow
How do I printf long long int and also unsigned long long int in C99 using GCC? I have searched the other posts which suggest to use %lld but it gives these warnings: warning#1: unknown convers... More on stackoverflow.com
c - How to printf long long - Stack Overflow
I'm doing a program that aproximate PI and i'm trying to use long long, but it isn't working. Here is the code #include #include typedef long long num; main(){ num... More on stackoverflow.com
Printing long value with sprintf
I have been fighting with this for a long time. The code snipped below is to illustrate my problem. I have a assigned a long value. This is a 4 byte signed value. I assign it a number that is larger then would fit in a 2 byte integer. When I just print the value direct it is correctly displayed. More on forum.arduino.cc
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0
June 2, 2016How to print a 64 bit long in 32 bit mode using printf?
If you're not already, use the types in for specific widths, instead of assuming that int, long, long long, etc. have a given size. int32_t, int64_t or whatever. If you also #include you can use those types with printf like so: int32_t foo = 1; int64_t bar = 2; printf("foo is %" PRId32 "\nbar is %" PRId64 "\n", foo, bar); More on reddit.com
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April 30, 2015Videos
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w3resource
w3resource.com › c-programming-exercises › c-snippets › conversion-specifier-for-formatting-long-with-printf-in-c.php
Conversion Specifier for Printing long in C with printf
For printing a long integer, you use the %ld specifier. This specifier tells printf to format the corresponding argument as a long int.
U-Boot Documentation
docs.u-boot.org › en › v2024.10 › develop › printf.html
Printf() format codes — Das U-Boot unknown version documentation
Printf() format codes · View page source · Each conversion specification consists of: leading ‘%’ character · zero or more flags · an optional minimum field width · an optional precision field preceded by ‘.’ · an optional length modifier · a conversion specifier ·
IncludeHelp
includehelp.com › c › arguments-for-printf-that-formats-a-long-datatype.aspx
Arguments for printf() that formats a long datatype
July 10, 2022 - C language code for understanding ... //declaring an unsigned long long int variable long double ld; //declaring a long double variable printf("Enter long int: "); scanf("%ld", &li); //argument in printf for long int(%ld) printf("Enter unsigned Long Int: "); scanf("%lu", &uli); ...
Texas Instruments E2E
e2e.ti.com › support › processors-group › processors › f › processors-forum › 211691 › printing-unsigned-long-long-using-system_printf
Printing unsigned long long using System_printf() - Processors forum - Processors - TI E2E support forums
September 3, 2012 - To print long long, try "%llu" or "%lld" (I don't know if System_printf() support it).
TheServerSide
theserverside.com › blog › Coffee-Talk-Java-News-Stories-and-Opinions › How-to-format-a-Java-int-with-printf-example
How to format a Java int or long with printf example
There are two key takeaways from this Java int printf example: The %d specifier works for long, int, double and short datatypes.
Top answer 1 of 4
96
If you are on windows and using mingw, gcc uses the win32 runtime, where printf needs %I64d for a 64 bit integer. (and %I64u for an unsinged 64 bit integer)
For most other platforms you'd use %lld for printing a long long. (and %llu if it's unsigned). This is standarized in C99.
gcc doesn't come with a full C runtime, it defers to the platform it's running on - so the general case is that you need to consult the documentation for your particular platform - independent of gcc.
2 of 4
8
For portable code, the macros in inttypes.h may be used. They expand to the correct ones for the platform.
E.g. for 64 bit integer, the macro PRId64 can be used.
int64_t n = 7;
printf("n is %" PRId64 "\n", n);
Wyzant
wyzant.com › resources › ask an expert
How do you format an unsigned long long int using printf? | Wyzant Ask An Expert
May 3, 2019 - #include <stdio.h> int main() { unsigned long long int num = 285212672; //FYI: fits in 29 bits int normalInt = 5; printf("My number is %d bytes wide and its value is %ul. A normal number is %d.\\n", sizeof(num), num, normalInt); return 0; }Output: My number is 8 bytes wide and its value is 285212672l.
Top answer 1 of 4
80
%lld is the standard C99 way, but that doesn't work on the compiler that I'm using (mingw32-gcc v4.6.0). The way to do it on this compiler is: %I64d
So try this:
if(e%n==0)printf("%15I64d -> %1.16I64d\n",e, 4*pi);
and
scanf("%I64d", &n);
The only way I know of for doing this in a completely portable way is to use the defines in <inttypes.h>.
In your case, it would look like this:
scanf("%"SCNd64"", &n);
//...
if(e%n==0)printf("%15"PRId64" -> %1.16"PRId64"\n",e, 4*pi);
It really is very ugly... but at least it is portable.
2 of 4
3
- Your
scanf()statement needs to use%lldtoo. - Your loop does not have a terminating condition.
There are far too many parentheses and far too few spaces in the expression
pi += pow(-1.0, e) / (2.0*e + 1.0);- You add one on the first iteration of the loop, and thereafter zero to the value of 'pi'; this does not change the value much.
- You should use an explicit return type of
intformain(). - On the whole, it is best to specify
int main(void)when it ignores its arguments, though that is less of a categorical statement than the rest. - I dislike the explicit licence granted in C99 to omit the return from the end of
main()and don't use it myself; I writereturn 0;to be explicit.
I think the whole algorithm is dubious when written using long long; the data type probably should be more like long double (with %Lf for the scanf() format, and maybe %19.16Lf for the printf() formats.
NXP
community.nxp.com › t5 › MCUXpresso-General › printf-double-and-unsigned-long-int-support › td-p › 967954
printf(), double and unsigned long int support - NXP Community
June 28, 2019 - where i is declared as uint64_t cast as an unsigned long int equal to 0x100000001 displays as "i = lu". If instead I select Newlib (nohost) in the Library/Header category, the second printf() call shown above will render the expected value, however when the first printf() shown is encountered the hard fault handler is inevitably invoked.
Cprogramming
cboard.cprogramming.com › c-programming › 60111-displaying-long-long-printf.html
Displaying a 'long long' with printf
December 27, 2004 - ... I decided to post my original response - although it's not the root cause of trinitrotoluene's problems, it is a problem that's popped up here a few times in the past. In short, you can use the MS C-runtime library (MSVCRT.DLL) with MinGW - and the version of printf() in this library uses "%I64" instead of "%ll" when specifying a 64bit integer.
GeeksforGeeks
geeksforgeeks.org › c language › c-long
C Long - GeeksforGeeks
June 15, 2026 - #include <stdio.h> int main() { ... 9223372036854775807 Size of long long: 8 bytes · We can use a long modifier with double datatype to create a long double variable....
Cplusplus
cplusplus.com › reference › cstdio › printf
Printf
printf · function · <cstdio> int printf ( const char * format, ... ); Print formatted data to stdout · Writes the C string pointed by format to the standard output (stdout).
Arduino Forum
forum.arduino.cc › projects › programming
Printing long value with sprintf - Programming - Arduino Forum
June 2, 2016 - I have been fighting with this for a long time. The code snipped below is to illustrate my problem. I have a assigned a long value. This is a 4 byte signed value. I assign it a number that is larger then would fit in a 2 byte integer. When I just print the value direct it is correctly displayed.
Unstop
unstop.com › home › blog › format specifiers in c — complete list with code examples (2026)
Format Specifiers in C — Complete List with Code Examples (2026)
May 19, 2026 - The %lu format specifier is used to print unsigned long integers in C. An unsigned long integer is a non-negative integer that typically occupies more memory than a standard unsigned int, allowing it to represent a larger range of values.
Reddit
reddit.com › r/c_programming › how to print a 64 bit long in 32 bit mode using printf?
r/C_Programming on Reddit: How to print a 64 bit long in 32 bit mode using printf?
April 30, 2015 -
Say i have 2 32 bit registers eax:edx that combined makes a 64 bit signed long. How can i print this using printf in base 10? Basically i need the 32 bit version of printf to interpret the sequence of bits as a 64 bit signed long.
I have tried to print the first half and the second half separately but the signed bit messes everything up. Any ideas? Don't need the exact solution.
Top answer 1 of 2
15
If you're not already, use the types in for specific widths, instead of assuming that int, long, long long, etc. have a given size. int32_t, int64_t or whatever. If you also #include you can use those types with printf like so: int32_t foo = 1; int64_t bar = 2; printf("foo is %" PRId32 "\nbar is %" PRId64 "\n", foo, bar);
2 of 2
8
C implementations targeting 32-bit can still support 64-bit data. long long is required to be at least 64 bits wide in C99. (In fact IA32 apparently specifies the arrangement you describe). You can print such a value using the %lld format specifier: long long x = 10000000000; printf("%lld %zd\n", x, sizeof(void*));
Quora
quora.com › How-can-I-print-an-unsigned-long-int-in-C-language
How to print an unsigned long int in C language - Quora
Answer (1 of 6): %lu is the standard order for unsigned long int. Just ran this snippet and it works for me. #include int main(void) { int unsigned long number = 600851475143LU; printf( "%lu", number ); return 0; } Let me know if you face some issue with this Vineeta Karki.
TutorialsPoint
tutorialspoint.com › cprogramming › c_format_specifiers.htm
Format Specifiers in C
C uses %d for signed integer, %i for unsigned integer, %ld or %li for long integer, %o or %O for octal representation, and %x or %X for hexadecimal representation of an integer. The following example highlights how integer format specifiers ...
University of Surrey
personalpages.surrey.ac.uk › r.bowden › C › printf.html
Format Conversions: printf, fprintf, sprintf
int printf(const char *format, ...) int fprintf(FILE *stream, const char *format, ...) int sprintf(char *string, const char *format, ...) The functions return the number of characters written, or a negative value if an error occurred. The format string is of the form ·