You should use some HTML parsing library like lxml:

from lxml import etree
s = """<table>
  <tr><th>Event</th><th>Start Date</th><th>End Date</th></tr>
  <tr><td>a</td><td>b</td><td>c</td></tr>
  <tr><td>d</td><td>e</td><td>f</td></tr>
  <tr><td>g</td><td>h</td><td>i</td></tr>
</table>
"""
table = etree.HTML(s).find("body/table")
rows = iter(table)
headers = [col.text for col in next(rows)]
for row in rows:
    values = [col.text for col in row]
    print dict(zip(headers, values))

prints

{'End Date': 'c', 'Start Date': 'b', 'Event': 'a'}
{'End Date': 'f', 'Start Date': 'e', 'Event': 'd'}
{'End Date': 'i', 'Start Date': 'h', 'Event': 'g'}

You can use CSS selector select() and select_one() to get "3text" and "6text" like below:

import requests
from bs4 import BeautifulSoup
html_doc='''
<table callspacing="0" cellpadding="0">
    <tbody><tr>
    <td>1text&nbsp;2text</td>
    <td>3text&nbsp;</td>
    </tr>
    <tr>
    <td>4text&nbsp;5text</td>
    <td>6text&nbsp;</td>
    </tr>
</tbody></table>
'''

soup = BeautifulSoup(html_doc, 'lxml')
soup1 = soup.select('tr')

for i in soup1:
    print(i.select_one('td:nth-child(2)').text)

You can also use find_all method:

trs = soup.find('table').find_all('tr')

for i in trs:
    tds = i.find_all('td')
    print(tds[1].text)

Result:

3text 
6text