You can use always:
'C:/mydir'
This works both in Linux and Windows.
Another possibility is:
'C:\\mydir'
If you have problems with some names you can also try raw string literals:
r'C:\mydir'
However, the best practice is to use the os.path module functions that always joins with the correct path separator (os.path.sep) for your OS:
os.path.join(mydir, myfile)
From python 3.4 you can also use the pathlib module. This is equivalent to the above:
pathlib.Path(mydir, myfile)
or:
pathlib.Path(mydir) / myfile
You can use always:
'C:/mydir'
This works both in Linux and Windows.
Another possibility is:
'C:\\mydir'
If you have problems with some names you can also try raw string literals:
r'C:\mydir'
However, the best practice is to use the os.path module functions that always joins with the correct path separator (os.path.sep) for your OS:
os.path.join(mydir, myfile)
From python 3.4 you can also use the pathlib module. This is equivalent to the above:
pathlib.Path(mydir, myfile)
or:
pathlib.Path(mydir) / myfile
Use the os.path module.
os.path.join( "C:", "meshes", "as" )
Or use raw strings
r"C:\meshes\as"
I would also recommend no spaces in the path or file names. And you could use double backslashes in your strings.
"C:\\meshes\\as.jpg"
I have been searching the web for a solution without a result.
I made this small script that can be used. Feel free to use it.
I wonder is there a better solution on the issue to convert windows path to python path?
"""
A path, in Windows "C:\Folder" . in Python it is "C:/Folder".
In Python the "\" character can get interpreted as the ESCAPE character.
When an 'r' or 'R' prefix is present, a character following a backslash is
included in the string without change, and all backslashes are left in the string.
"""
def main():
# - YOUR INPUT - IMPORTANT: keep the r in front of path string here.
win_path = r"<TYPE YOUR PATH HERE>"
# Call function to convert from windows to Python path.
path_py = py_path(win_path)
print("Your Python Path: ", path_py)
def py_path(win_path):
python_path = "" # The result of this script.
# Convert to ASCII list
ascii_values_list = []
for character in win_path:
ascii_values_list.append(ord(character))
# Replace all ASCII values for "\" (=92) with value for "/" (=47).
for i in range(0, len(ascii_values_list)):
if ascii_values_list[i] == 92:
ascii_values_list[i] = 47
path_py = "" # Convert ASCII list to string
for val in ascii_values_list:
path_py = path_py + chr(val)
if path_py[-1] != "/": # Add "/" at end of path if needed.
path_py = path_py + "/"
return path_py
if __name__ == "__main__":
main() # Script goes there.
# EOF
python - Convert WindowsPath to String - Stack Overflow
Python - handling windows path with '\' characters
Implement Path property that returns the full path as a string - Ideas - Discussions on Python.org
How to Convert string variable to Raw literal path in Windows
Videos
As most other Python classes do, the WindowsPath class, from pathlib, implements a non-defaulted "dunder string" method (__str__). It turns out that the string representation returned by that method for that class is exactly the string representing the filesystem path you are looking for. Here an example:
from pathlib import Path
p = Path('E:\\x\\y\\z')
>>> WindowsPath('E:/x/y/z')
p.__str__()
>>> 'E:\\x\\y\\z'
str(p)
>>> 'E:\\x\\y\\z'
The str builtin function actually calls the "dunder string" method under the hood, so the results are exaclty the same. By the way, as you can easily guess calling directly the "dunder string" method avoids a level of indirection by resulting in faster execution time.
Here the results of the tests I've done on my laptop:
from timeit import timeit
timeit(lambda:str(p),number=10000000)
>>> 2.3293891000000713
timeit(lambda:p.__str__(),number=10000000)
>>> 1.3876856000000544
Even if calling the __str__ method may appear a bit uglier in the source code, as you saw above, it leads to faster runtimes.
You are right, you need a string when you call glob.glob. In the last line of your code, parent_dir is a pathlib.Path object, which you cannot concatenate with the string '/*fits'. You need to explicitly convert parent_dir to a string by passing it to the built-in str function.
The last line of your code should thus read:
fspec = glob.glob(str(parent_dir)+'/*fits')
To illustrate further, consider this example:
>>> from pathlib import Path
>>> path = Path('C:\\')
>>> path
WindowsPath('C:/')
>>> str(path)
'C:\\'
>>>
I have been searching the web for a solution without a result.
I made this small script that can be used. Feel free to use it.
I wonder is there a better solution on the issue to convert windows path to python path?
"""
A path, in Windows "C:\Folder" . in Python it is "C:/Folder".
In Python the "\" character can get interpreted as the ESCAPE character.
When an 'r' or 'R' prefix is present, a character following a backslash is
included in the string without change, and all backslashes are left in the string.
"""
def main():
# - YOUR INPUT - IMPORTANT: keep the r in front of path string here.
win_path = r"<TYPE YOUR PATH HERE>"
# Call function to convert from windows to Python path.
path_py = py_path(win_path)
print("Your Python Path: ", path_py)
def py_path(win_path):
python_path = "" # The result of this script.
# Convert to ASCII list
ascii_values_list = []
for character in win_path:
ascii_values_list.append(ord(character))
# Replace all ASCII values for "\" (=92) with value for "/" (=47).
for i in range(0, len(ascii_values_list)):
if ascii_values_list[i] == 92:
ascii_values_list[i] = 47
path_py = "" # Convert ASCII list to string
for val in ascii_values_list:
path_py = path_py + chr(val)
if path_py[-1] != "/": # Add "/" at end of path if needed.
path_py = path_py + "/"
return path_py
if __name__ == "__main__":
main() # Script goes there.
# EOF
You can use os.path.abspath() to convert it:
print(os.path.abspath("P:\python\t\temp.txt"))
>>> P:/python/t/temp.txt
See the documentation of os.path here.
I've solved it.
The issues lies with the python interpreter. \t and all the others don't exist as such data, but are interpretations of nonprint characters.
So I got a bit lucky and someone else already faced the same problem and solved it with a hard brute-force method:
http://code.activestate.com/recipes/65211/
I just had to find it.
After that I have a raw string without escaped characters, and just need to run the simple replace() on it to get a workable path.