That depends on what you mean. If you just want to get rid of them, do this:
(Update: Apparently you want to keep digits as well, use the second lines in that case)
String alphaOnly = input.replaceAll("[^a-zA-Z]+","");
String alphaAndDigits = input.replaceAll("[^a-zA-Z0-9]+","");
or the equivalent:
String alphaOnly = input.replaceAll("[^\\p{Alpha}]+","");
String alphaAndDigits = input.replaceAll("[^\\p{Alpha}\\p{Digit}]+","");
(All of these can be significantly improved by precompiling the regex pattern and storing it in a constant)
Or, with Guava:
private static final CharMatcher ALNUM =
CharMatcher.inRange('a', 'z').or(CharMatcher.inRange('A', 'Z'))
.or(CharMatcher.inRange('0', '9')).precomputed();
// ...
String alphaAndDigits = ALNUM.retainFrom(input);
But if you want to turn accented characters into something sensible that's still ascii, look at these questions:
- Converting Java String to ASCII
- Java change áéőűú to aeouu
- ń ǹ ň ñ ṅ ņ ṇ ṋ ṉ ̈ ɲ ƞ ᶇ ɳ ȵ --> n or Remove diacritical marks from unicode chars
regex - Remove / Replace special characters, with exception - Stack Overflow
How do i remove special characters from a string?
RegexReplace for Special Character
RegEx to replace special characters in a string with space ? asp.net c# - Stack Overflow
That depends on what you mean. If you just want to get rid of them, do this:
(Update: Apparently you want to keep digits as well, use the second lines in that case)
String alphaOnly = input.replaceAll("[^a-zA-Z]+","");
String alphaAndDigits = input.replaceAll("[^a-zA-Z0-9]+","");
or the equivalent:
String alphaOnly = input.replaceAll("[^\\p{Alpha}]+","");
String alphaAndDigits = input.replaceAll("[^\\p{Alpha}\\p{Digit}]+","");
(All of these can be significantly improved by precompiling the regex pattern and storing it in a constant)
Or, with Guava:
private static final CharMatcher ALNUM =
CharMatcher.inRange('a', 'z').or(CharMatcher.inRange('A', 'Z'))
.or(CharMatcher.inRange('0', '9')).precomputed();
// ...
String alphaAndDigits = ALNUM.retainFrom(input);
But if you want to turn accented characters into something sensible that's still ascii, look at these questions:
- Converting Java String to ASCII
- Java change áéőűú to aeouu
- ń ǹ ň ñ ṅ ņ ṇ ṋ ṉ ̈ ɲ ƞ ᶇ ɳ ȵ --> n or Remove diacritical marks from unicode chars
I am using this.
s = s.replaceAll("\\W", "");
It replace all special characters from string.
Here
\w : A word character, short for [a-zA-Z_0-9]
\W : A non-word character
Full disclosure regarding the following code:
- It's not tested
- I probably messed up the character escaping in
new Regex(...); I don't actually know C#, but I can Google for
"C# string replace regex"and land on MSDNRegex re = new Regex("[;\\/:*?\"<>|&']"); string outputString = re.Replace(inputString, " ");
Here's the correct code:
string inputString = "1/10 EP Sp'arrowha?wk XT R;TR 2.4GHz R\\ed";
Regex re = new Regex("[;\\\\/:*?\"<>|&']");
string outputString = re.Replace(inputString, " ");
// outputString is "1 10 EP Sp arrowha wk XT R TR 2.4GHz R ed"
Demo: http://ideone.com/hrKdJ
Also: http://www.regular-expressions.info/
string outputString = Regex.Replace(inputString,"[;\/:*?""<>|&']",String.Empty)
var desired = stringToReplace.replace(/[^\w\s]/gi, '')
As was mentioned in the comments it's easier to do this as a whitelist - replace the characters which aren't in your safelist.
The caret (^) character is the negation of the set [...], gi say global and case-insensitive (the latter is a bit redundant but I wanted to mention it) and the safelist in this example is digits, word characters, underscores (\w) and whitespace (\s).
Note that if you still want to exclude a set, including things like slashes and special characters you can do the following:
var outString = sourceString.replace(/[`~!@#$%^&*()_|+\-=?;:'",.<>\{\}\[\]\\\/]/gi, '');
take special note that in order to also include the "minus" character, you need to escape it with a backslash like the latter group. if you don't it will also select 0-9 which is probably undesired.
Hi,
I tried to replace spl characters and new line character( \n) but not the word spacing from a sentence.
I want to build one Single regular expression to achieve this.
I tried to use double negation to target only the newline character, but no success.
Giving below my attempt:
ss = """Nory was a Catholic because her mother was a Catholic,and Nory's mother was a Catholic because her father was a Catholic,and her father was a Catholic because his mother was a Catholic,or had been."""
re.sub('[^a-zA-Z0-9\s\r\n]','',ss)
But the output still contains newline character.
output:
'Nory was a Catholic because her mother was a Catholic \nand Norys mother was a Catholic because her father was a Catholic \nand her father was a Catholic because his mother was a Catholic \nor had been'
Could you please help me to correct this?
Thanks in advance!