text = text.replace("very", "not very", 1)
>>> help(str.replace)
Help on method_descriptor:
replace(...)
S.replace (old, new[, count]) -> string
Return a copy of string S with all occurrences of substring
old replaced by new. If the optional argument count is
given, only the first count occurrences are replaced.
Answer from Fred Nurk on Stack Overflowtext = text.replace("very", "not very", 1)
>>> help(str.replace)
Help on method_descriptor:
replace(...)
S.replace (old, new[, count]) -> string
Return a copy of string S with all occurrences of substring
old replaced by new. If the optional argument count is
given, only the first count occurrences are replaced.
text = text.replace("very", "not very", 1)
The third parameter is the maximum number of occurrences that you want to replace.
From the documentation for Python:
string.replace(s, old, new[, maxreplace])
Return a copy of string s with all occurrences of substring old replaced by new. If the optional argument maxreplace is given, the first maxreplace occurrences are replaced.
regex - Replace first occurrence of string in Python - Stack Overflow
python - How can I replace the first occurrence of a character in every word? - Stack Overflow
Python: How can I replace one specific character on a string while leaving the rest of the string as it was?
Regex: remove first occurrence of specific character
string replace() function perfectly solves this problem:
string.replace(s, old, new[, maxreplace])
Return a copy of string s with all occurrences of substring old replaced by new. If the optional argument maxreplace is given, the first maxreplace occurrences are replaced.
>>> u'longlongTESTstringTEST'.replace('TEST', '?', 1)
u'longlong?stringTEST'
Use re.sub directly, this allows you to specify a count:
regex.sub('', url, 1)
(Note that the order of arguments is replacement, original not the opposite, as might be suspected.)
I would do a regex replacement on the following pattern:
@(@*)
And then just replace with the first capture group, which is all continous @ symbols, minus one.
This should capture every @ occurring at the start of each word, be that word at the beginning, middle, or end of the string.
inp = "hello @jon i am @@here or @@@there and want some@thing in '@here"
out = re.sub(r"@(@*)", '\\1', inp)
print(out)
This prints:
hello jon i am @here or @@there and want something in 'here
How about using replace('@', '', 1) in a generator expression?
string = 'hello @jon i am @@here or @@@there and want some@thing in "@here"'
result = ' '.join(s.replace('@', '', 1) for s in string.split(' '))
# output: hello jon i am @here or @@there and want something in "here"
The int value of 1 is the optional count argument.
str.replace(old, new[, count])
Return a copy of the string with all occurrences of substring old replaced by new. If the optional argument count is given, only the first count occurrences are replaced.