You should try using -- instead of surrounding your command with quotes.
scl enable python27 -- ls /tmp
I was able to make a python script that uses the rh-python35 collection with this shebang:
#!/usr/bin/scl enable rh-python35 -- python
import sys
print(sys.version)
Answer from JM0 on Stack OverflowYou should try using -- instead of surrounding your command with quotes.
scl enable python27 -- ls /tmp
I was able to make a python script that uses the rh-python35 collection with this shebang:
#!/usr/bin/scl enable rh-python35 -- python
import sys
print(sys.version)
The parsing of arguments in the she-bang command is not really defined. From man execve:
The semantics of the optional-arg argument of an interpreter script vary across implementations. On Linux, the entire string following the interpreter name is passed as a single argument to the interpreter, and this string can include white space. However, behavior differs on some other systems. Some systems use the first white space to terminate optional-arg. On some systems, an interpreter script can have multiple arguments, and white spaces in optional-arg are used to delimit the arguments.
No matter what, argument splitting based on quote sis not supported. So when you write:
#!/usr/bin/scl enable python27 "ls /tmp"
It's very possible that what gets invoked is (using bash notation):
'/usr/bin/scl' 'enable' 'python27' '"ls' '/tmp"'
This is probably why it tries to open the "ls file at /etc/scl/prefixes/"ls
But it is just as likely that the shebang evaluates to:
'/usr/bin/scl' 'enable python27 "ls /tmp"'
And that would fail since it wont be able to find a command named enable python27 "ls /tmp" for scl to execute.
There's a few workarounds you can use.
You can call your script via scl:
$ cat myscript
#!/bin/bash
echo hello
$ scl enable python27 ./myscript
hello
You can also use the heredoc notation, but it might lead to subtle issues. I personally avoid this:
$ cat ./myscript
#!/bin/bash
scl enable python27 -- <<EOF
echo hi
echo \$X_SCLS
EOF
$ bash -x myscript
+ scl enable python27 --
hi
python27
You can see one of the gotcha's already: I had to write \$X_SCLS to access the environment variable instead of just $X_SCL.
Edit: Another option is two have two scripts. One that has the actual code, and the second that simply does scl enable python27 $FIRST_SCRIPT. Then you wont have to remember to enter scl ... manually.
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From the comments and your further investigations it looks like your devtoolset is modifying the PATH. Unfortunately that includes what appears to be an old or broken sudo command.
It would be worth trying to modify the devtoolset include in your .bashrc like this, and then logging back in again:
if [ "$(gcc -dumpversion)" != "4.7.2" ]; then
scl enable devtoolset-1.1 bash
PATH=/usr/bin:$PATH # We need a working sudo
fi
Rather than work around the SCL's broken sudo wrapper, I just disabled it.
echo >> /opt/rh/devtoolset-2/root/usr/bin/sudo
chmod -x /opt/rh/devtoolset-2/root/usr/bin/sudo
Adding a newline to the end of the file ensures it won't get overwritten by subsequent Yum updates, and then I just make it non-executable.
I installed the dev toolset to get modern versions of gcc and c++ on RHEL 6, and have had no issues compiling code without the fake sudo in the mix.
In your ~/.bashrc or ~/.bash_profile Simply source the "enable" script provided with the devtoolset. For example, with the Devtoolset 2, the command is:
source /opt/rh/devtoolset-2/enable
or
source scl_source enable devtoolset-2
Lot more efficient: no forkbomb, no tricky shell
An alternative of source /opt/rh/devtoolset-4/enable is
source scl_source enable devtoolset-4
The above shell script scl_source is more elegant than using a hard coded path (may be different on another machine). However scl_source does less because /opt/rh/devtoolset-4/enable uses scl_source and other stuff.
To use scl_source you may have to upgrade package scl-utils
yum update scl-utils # old scl-utils versions miss scl_source
Quick copy-paste
echo 'source scl_source enable devtoolset-4' >> ~/.bashrc
# Do not forget to change the version ↑
Source code for curious people
An example of scl_source source code:
https://gist.github.com/bkabrda/6435016
The scl_source installed on my Red Hat 7.1
#!/bin/bash
_scl_source_help="Usage: source scl_source <action> [<collection> ...]
Don't use this script outside of SCL scriptlets!
Options:
-h, --help display this help and exit"
if [ $# -eq 0 -o $1 = "-h" -o $1 = "--help" ]; then
echo "$_scl_source_help"
return 0
fi
if [ -z "$_recursion" ]; then
_recursion="false"
fi
if [ -z "$_scl_scriptlet_name" ]; then
# The only allowed action in the case of recursion is the same
# as was the original
_scl_scriptlet_name=$1
fi
shift 1
if [ -z "$_scl_dir" ]; then
# No need to re-define the directory twice
_scl_dir=/etc/scl/conf
if [ ! -e $_scl_dir ]; then
_scl_dir=/etc/scl/prefixes
fi
fi
for arg in "$@"; do
_scl_prefix_file=$_scl_dir/$arg
_scl_prefix=`cat $_scl_prefix_file 2> /dev/null`
if [ $? -ne 0 ]; then
echo "Can't read $_scl_prefix_file, $arg is probably not installed."
return 1
fi
# First check if the collection is already in the list
# of collections to be enabled
for scl in ${_scls[@]}; do
if [ $arg == $scl ]; then
continue 2
fi
done
# Now check if the collection isn't already enabled
/usr/bin/scl_enabled $arg > /dev/null 2> /dev/null
if [ $? -ne 0 ]; then
_scls+=($arg)
_scl_prefixes+=($_scl_prefix)
fi;
done
if [ $_recursion == "false" ]; then
_i=0
_recursion="true"
while [ $_i -lt ${#_scls[@]} ]; do
_scl_scriptlet_path="${_scl_prefixes[$_i]}/${_scls[$_i]}/${_scl_scriptlet_name}"
source "$_scl_scriptlet_path"
if [ $? -ne 0 ]; then
echo "Can't source $_scl_scriptlet_name, skipping."
else
export X_SCLS="${_scls[$_i]} $X_SCLS"
fi;
_i=$(($_i+1))
done
_scls=()
_scl_prefixes=()
_scl_scriptlet_name=""
_recursion="false"
fi