If the array is sparse (rare True values); you could use collections.defaultdict:
from collections import defaultdict
a = defaultdict(bool)
a[i,j,k,m] = True
Answer from jfs on Stack OverflowIf the array is sparse (rare True values); you could use collections.defaultdict:
from collections import defaultdict
a = defaultdict(bool)
a[i,j,k,m] = True
If all you want is to store and get from a 4-dimensional object, perhaps use a dict:
In [7]: x = {}
# store
In [8]: x[1,2,3,4] = True
# get
In [9]: x[1,2,3,4]
Out[9]: True
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Hello,
I'm learning to code in Python and I'm stuck on a part of a question. I have googled a lot and tried to do it without success.
The user enters two matrices that are retained in the program as two-dimensional lists. The program checks whether the matrix sizes allow matrix multiplication and in that case performs the matrix multiplication. The result is saved in a new two-dimensional list.
I succeed with the part where users input the lists, but do not know how to proceed after that. Does anyone have any ideas on how to do this? I'm not allowed to use numpy on this assignment.
I would really appreciate some help.
Hey everyone,
Currently I am learning arrays in python for learning machine learning, and I learned 1D array and 2D array now I want to learn 3D array, but I don't get any resource which explaining 3D arrays in python, I searched on google, Gemini, ChatGPT, Bing ai, YouTube. But anyone is not explaining 3D array properly,
Can anyone please Explain me 3D arrays and How 3D arrays look like?
You should use a list comprehension:
>>> import pprint
>>> n = 3
>>> distance = [[[0 for k in xrange(n)] for j in xrange(n)] for i in xrange(n)]
>>> pprint.pprint(distance)
[[[0, 0, 0], [0, 0, 0], [0, 0, 0]],
[[0, 0, 0], [0, 0, 0], [0, 0, 0]],
[[0, 0, 0], [0, 0, 0], [0, 0, 0]]]
>>> distance[0][1]
[0, 0, 0]
>>> distance[0][1][2]
0
You could have produced a data structure with a statement that looked like the one you tried, but it would have had side effects since the inner lists are copy-by-reference:
>>> distance=[[[0]*n]*n]*n
>>> pprint.pprint(distance)
[[[0, 0, 0], [0, 0, 0], [0, 0, 0]],
[[0, 0, 0], [0, 0, 0], [0, 0, 0]],
[[0, 0, 0], [0, 0, 0], [0, 0, 0]]]
>>> distance[0][0][0] = 1
>>> pprint.pprint(distance)
[[[1, 0, 0], [1, 0, 0], [1, 0, 0]],
[[1, 0, 0], [1, 0, 0], [1, 0, 0]],
[[1, 0, 0], [1, 0, 0], [1, 0, 0]]]
numpy.arrays are designed just for this case:
numpy.zeros((i,j,k))
will give you an array of dimensions ijk, filled with zeroes.
depending what you need it for, numpy may be the right library for your needs.
You have a truncated array representation. Let's look at a full example:
>>> a = np.zeros((2, 3, 4))
>>> a
array([[[ 0., 0., 0., 0.],
[ 0., 0., 0., 0.],
[ 0., 0., 0., 0.]],
[[ 0., 0., 0., 0.],
[ 0., 0., 0., 0.],
[ 0., 0., 0., 0.]]])
Arrays in NumPy are printed as the word array followed by structure, similar to embedded Python lists. Let's create a similar list:
>>> l = [[[ 0., 0., 0., 0.],
[ 0., 0., 0., 0.],
[ 0., 0., 0., 0.]],
[[ 0., 0., 0., 0.],
[ 0., 0., 0., 0.],
[ 0., 0., 0., 0.]]]
>>> l
[[[0.0, 0.0, 0.0, 0.0], [0.0, 0.0, 0.0, 0.0], [0.0, 0.0, 0.0, 0.0]],
[[0.0, 0.0, 0.0, 0.0], [0.0, 0.0, 0.0, 0.0], [0.0, 0.0, 0.0, 0.0]]]
The first level of this compound list l has exactly 2 elements, just as the first dimension of the array a (# of rows). Each of these elements is itself a list with 3 elements, which is equal to the second dimension of a (# of columns). Finally, the most nested lists have 4 elements each, same as the third dimension of a (depth/# of colors).
So you've got exactly the same structure (in terms of dimensions) as in Matlab, just printed in another way.
Some caveats:
Matlab stores data column by column ("Fortran order"), while NumPy by default stores them row by row ("C order"). This doesn't affect indexing, but may affect performance. For example, in Matlab efficient loop will be over columns (e.g.
for n = 1:10 a(:, n) end), while in NumPy it's preferable to iterate over rows (e.g.for n in range(10): a[n, :]-- notenin the first position, not the last).If you work with colored images in OpenCV, remember that:
2.1. It stores images in BGR format and not RGB, like most Python libraries do.
2.2. Most functions work on image coordinates (
x, y), which are opposite to matrix coordinates (i, j).
No need to go in such deep technicalities, and get yourself blasted. Let me explain it in the most easiest way. We all have studied "Sets" during our school-age in Mathematics. Just consider 3D numpy array as the formation of "sets".
x = np.zeros((2,3,4))
Simply Means:
2 Sets, 3 Rows per Set, 4 Columns
Example:
Input
x = np.zeros((2,3,4))
Output
Set # 1 ---- [[[ 0., 0., 0., 0.], ---- Row 1
[ 0., 0., 0., 0.], ---- Row 2
[ 0., 0., 0., 0.]], ---- Row 3
Set # 2 ---- [[ 0., 0., 0., 0.], ---- Row 1
[ 0., 0., 0., 0.], ---- Row 2
[ 0., 0., 0., 0.]]] ---- Row 3
Explanation: See? we have 2 Sets, 3 Rows per Set, and 4 Columns.
Note: Whenever you see a "Set of numbers" closed in double brackets from both ends. Consider it as a "set". And 3D and 3D+ arrays are always built on these "sets".
Hello friends. I am trying to start to learn Python, but I am having some trouble getting past the early steps. I have a working knowledge of C and have figured out how to transfer most things over to the new syntax, but this one eludes me. I would like to declare a three dimensional array, which I believe may be called a list in Python, similar to this example in C:
int map[2][3][5] = {{
{0,0,0,0,0},
{0,0,0,0,0},
{0,0,0,0,0}},{
{0,0,0,0,0},
{0,0,0,0,0},
{0,0,0,0,0}}}Please note I may have gotten my bracketing slightly wrong here. I always get confused without a compiler to correct me, but you know what I'm going for - an expandable set of 2D arrays I can define when they are initialized.
My issue is finding documentation that allows me to declare and reference a variable in this way. I need the program to be able to hit specific tiles, such as map[1][2][0] vs. map[1][2][1], and all the information I've found regarding declarations for Python seem to lean towards not defining these borders and having these vaguely long lists that I'm not sure how to manage properly. I thought I might be missing something, possibly searching for the wrong words (Is it called a 3D list? Who knows!) or looking in the wrong areas. If this is an easy thing to look up, I'm sorry, I've tried over and over before posting and I just can't get it to come up with what I need. Any help would be greatly appreciated!
As a final note, this is one of the first things I need to figure out to teach myself Python, so it would be best to assume I have little knowledge of the terminology and syntax. All my programming before this was straight C, not even C++ really, so it is very foreign looking to me.
I have a 3d numpy array where the indices of each element represent the coordinates in the cartesian system and the value of each element represents something, let's say temperature. What would be the optimal way to visualize the temperature distribution in this space?
I have been looking at the 3d scatterplot approach in matplotlib, but I can't really make it work. Could someone point me in the right direction? Thanks!