Assuming that a row is one of the entries in a ArrayNode the following simple approach may be useful. It uses the JsonNode abstraction instead of a series of nested Map objects which I personally prefer since JsonNode provides a series of utility methods that are helpful when dealing with this kind of data (data where the structure is possibly unknown or very dynamic so that it can't be easily transformed to a POJO).
The testcase below illustrates how to find the number of rows and how to print the values. To get hold of the values the method JsonNode.elements() is used and the number of rows is simply a call to the size()-method.
public class ArrayNodeTest {
@Test
public void verifySizeAndPrintRows() throws IOException {
final String jsonStr =
"[{\"key11\":\"value11\",\"key12\":\"value12\"},\n" +
"{\"key21\":\"value21\",\"key22\":\"value22\"},\n" +
"{\"keyn1\":\"valuen1\",\"keyn2\":\"valuen2\"}]";
final ObjectMapper mapper = new ObjectMapper();
final JsonNode jsonNode = mapper.readTree(jsonStr);
// Verify size
Assert.assertEquals(3, jsonNode.size());
// And print rows
for (final JsonNode row : jsonNode) {
final Iterable<JsonNode> iterable = () -> row.elements();
iterable.forEach(elem -> System.out.println(elem.asText()));
}
}
}
Assuming that a row is one of the entries in a ArrayNode the following simple approach may be useful. It uses the JsonNode abstraction instead of a series of nested Map objects which I personally prefer since JsonNode provides a series of utility methods that are helpful when dealing with this kind of data (data where the structure is possibly unknown or very dynamic so that it can't be easily transformed to a POJO).
The testcase below illustrates how to find the number of rows and how to print the values. To get hold of the values the method JsonNode.elements() is used and the number of rows is simply a call to the size()-method.
public class ArrayNodeTest {
@Test
public void verifySizeAndPrintRows() throws IOException {
final String jsonStr =
"[{\"key11\":\"value11\",\"key12\":\"value12\"},\n" +
"{\"key21\":\"value21\",\"key22\":\"value22\"},\n" +
"{\"keyn1\":\"valuen1\",\"keyn2\":\"valuen2\"}]";
final ObjectMapper mapper = new ObjectMapper();
final JsonNode jsonNode = mapper.readTree(jsonStr);
// Verify size
Assert.assertEquals(3, jsonNode.size());
// And print rows
for (final JsonNode row : jsonNode) {
final Iterable<JsonNode> iterable = () -> row.elements();
iterable.forEach(elem -> System.out.println(elem.asText()));
}
}
}
to identify the number of rows
What's a "row"? Is a key/value pair a row? Is an element of the JSON array (no matter how many key/value pairs it contains) a row?
print only the values on the screen
Jackson has nothing to do with printing anything on any screens. Jackson can be used to populate a Java data structure from the input JSON, and the populated Java data structure can then be used however you want.
Given the JSON structure in the original question, a simple solution would be to bind to a list (or array) of maps, and then just iterate through the list of maps, accessing all of the values. Following is such an example.
import java.io.File;
import java.util.Map;
import org.codehaus.jackson.map.ObjectMapper;
public class JacksonFoo
{
public static void main(String[] args) throws Exception
{
ObjectMapper mapper = new ObjectMapper();
Map<String, String>[] maps = mapper.readValue(new File("input.json"), Map[].class);
for (Map<String, String> map : maps)
{
for (Map.Entry<String, String> entry : map.entrySet())
{
System.out.println(entry.getValue());
}
}
}
}
Output:
value11
value12
value21
value22
valuen1
valuen2
ObjectMapper mapper = new ObjectMapper();
List<Employee> e = new ArrayList<Employee>();
ArrayNode array = mapper.valueToTree(e);
ObjectNode companyNode = mapper.valueToTree(company);
companyNode.putArray("Employee").addAll(array);
JsonNode result = mapper.createObjectNode().set("company", companyNode);
List<String> yourList = new ArrayList<>();
((ObjectNode) someNode).set("listname", this.objectMapper.valueToTree(yourList));
Yes, the Jackson manual parser design is quite different from other libraries. In particular, you will notice that JsonNode has most of the functions that you would typically associate with array nodes from other APIs. As such, you do not need to cast to an ArrayNode to use. Here's an example:
JSON:
{
"objects" : ["One", "Two", "Three"]
}
Code:
final String json = "{\"objects\" : [\"One\", \"Two\", \"Three\"]}";
final JsonNode arrNode = new ObjectMapper().readTree(json).get("objects");
if (arrNode.isArray()) {
for (final JsonNode objNode : arrNode) {
System.out.println(objNode);
}
}
Output:
"One"
"Two"
"Three"
Note the use of isArray to verify that the node is actually an array before iterating. The check is not necessary if you are absolutely confident in your data structure, but it's available should you need it (and this is no different from most other JSON libraries).
In Java 8 you can do it like this:
import java.util.*;
import java.util.stream.*;
List<JsonNode> datasets = StreamSupport
.stream(obj.get("datasets").spliterator(), false)
.collect(Collectors.toList())
Moving my comment to an answer, as it got upvoted a lot.
This should do what the OP needed:
new ObjectMapper().convertValue(jsonNode, ArrayList.class)
A quick way to do this using the tree-model... convert the JSON string into a tree of JsonNode's:
ObjectMapper mapper = new ObjectMapper();
JsonNode rootNode = mapper.readTree("...<JSON string>...");
Then extract the child nodes and convert them into lists:
List<Double> x = mapper.convertValue(rootNode.get("x"), ArrayList.class);
List<Double> y = mapper.convertValue(rootNode.get("y"), ArrayList.class);
A slight longer, but arguable better way to do this is to define a class representing the JSON structure you expect:
public class Request {
List<Double> x;
List<Double> y;
}
Then deserialized directly as follows:
Request request = mapper.readValue("...<JSON string>...", Request.class);