scanf("%.2f",&x);
And i think that will solve a problem
Answer from Dmitry Zheshinsky on Stack Overflow Top answer 1 of 3
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scanf("%.2f",&x);
And i think that will solve a problem
2 of 3
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The complete list
Integer display
%d print as decimal integer
%6d print as decimal integer, at least 6 characters wide
%f print as floating point
%6f print as floating point, at least 6 characters wide
%.2f print as floating point, 2 characters after decimal point
With the required modification (scanf("%.2f",&x); in the last entry) will solve your problem
Oxford University
mathcenter.oxford.emory.edu › site › cs170 › printf
The printf Method
we now see that the format specifier "%.2f" tells the printf method to print a floating point value (the double, x, in this case) with 2 decimal places.
Storing a value as two digits after decimal
Doubles don't store their values as decimal numbers with a point, they store them as an exponent and fraction that is computed in a way to convert it to decimal when you display it. What you're asking isn't really a good use of doubles. If you want to get a double into a 100ths precision, you're better off multiplying it by 100 and storing it in an integer type like int and long, then converting back to whole numbers when displaying. For example: double f = 44.444; long f_hundredths = f * 100; // the conversion to long will chop trailing decimal points //display long f_whole = f_hundredths / 100; cout << f_whole << "." << f_hundredths - f_whole; However, because doubles aren't stored as decimal representations, you could end up getting off by a bit when multiplying by 100. It'd be best in your case to only take in the precision you want to work with (hundredths). See this SO post for more information (the base logic applies to C++ as well). More on reddit.com
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June 20, 2014How to set a result to 2 decimal places - C++ Forum
I'm only allowed to use the library, so setprecision can't be used. How can I set 2 decimal places for the average? More on cplusplus.com
floating point - How do I round a number to 2 decimal places in C? - Stack Overflow
You cannot properly round the number ... (and double) aren't decimal floating-point - they are binary floating-point - so rounding to decimal positions is meaningless. You can round the output, however. ... It's not meaningless; it's inexact. There's quite a difference. ... If you just want to round the number for output purposes, then the "%.2f" format string is ... More on stackoverflow.com
Rounding offto 2 decimal points - C++ Forum
If all you want to do is print ... place, use the stream manipulators: However, if you want to actually modify the numeric value, you'll need to multiply, round, and divide. The caveat is that this might not do exactly what you think. The reason is that floating point numbers are not exact. And the reason for that is twofold: (1) numbers in the computer are represented in binary but we view them in decimal, which is ... More on cplusplus.com
Videos
02:45
Setting Decimal Precision in C - YouTube
08:10
Round A Double To A Specific Number Of Decimal Places | C Programming ...
01:45
C++ 3: Print a double to 2 decimal places using setprecision and ...
05:05
Round off decimal number to 2 places in c++ using 2 ways - YouTube
GeeksforGeeks
geeksforgeeks.org › c language › rounding-floating-point-number-two-decimal-places-c-c
Rounding Floating Point Number To two Decimal Places in C and C++ - GeeksforGeeks
May 21, 2024 - #include <iostream> using namespace std; float round(float var) { // we use array of chars to store number // as a string. char str[40]; // Print in string the value of var // with two decimal point sprintf(str, "%.2f", var); // scan string value in var sscanf(str, "%f", &var); return var; } int main() { float var = 37.66666; cout << round(var); return 0; }
Reddit
reddit.com › r/cpp_questions › storing a value as two digits after decimal
r/cpp_questions on Reddit: Storing a value as two digits after decimal
June 20, 2014 -
I can't figure out the code to take a double f = 44.444 and store it into double c as 44.44. I need to make the precision after the decimal place 2.
For cout << setprecision(2) << fixed << f, I know this works, but I don't want to print on the screen.
Top answer 1 of 4
3
Doubles don't store their values as decimal numbers with a point, they store them as an exponent and fraction that is computed in a way to convert it to decimal when you display it. What you're asking isn't really a good use of doubles. If you want to get a double into a 100ths precision, you're better off multiplying it by 100 and storing it in an integer type like int and long, then converting back to whole numbers when displaying. For example: double f = 44.444; long f_hundredths = f * 100; // the conversion to long will chop trailing decimal points //display long f_whole = f_hundredths / 100; cout << f_whole << "." << f_hundredths - f_whole; However, because doubles aren't stored as decimal representations, you could end up getting off by a bit when multiplying by 100. It'd be best in your case to only take in the precision you want to work with (hundredths). See this SO post for more information (the base logic applies to C++ as well).
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For that do you need it? The problem is, double cannot exactly represent those numbers. If you need to use double, you can use something like: double to2decimalplaces(double d) { int res = static_cast(d * 100); // This might fail if the numbers get to big return static_cast(res) / 100; } Or better use an integer (maybe in a class so you can overload operators) that stores 1/100 (aka n = 100 would represent 1, n = 42 would be 0.42) .. this is the best way to go if you need it for currency e.g.
Academic Help
academichelp.net › coding › c-coding › how-to-print-a-double.html
How to Print a Double in C With Precision
January 31, 2024 - In this code snippet, we set the precision to two decimal places by using %.2f. The result will be “My double value is: 3.14.” Adjust the value of <n> as needed to control the level of precision in your printed double values.
Quora
quora.com › How-do-I-display-floating-number-with-2-decimal-places-in-c
How to display floating number with 2 decimal places in c - Quora
To print a floating-point number with exactly two decimal places in C, use the printf family with the "%.2f" format specifier. That rounds the value to two decimals and prints trailing zeros.
Northern Michigan University
nmu.edu › Webb › ArchivedHTML › MathComputerScience › c_programming › c_008.htm
More About Float and Double Variables
To change the number of decimal places printed out for float or double variables, modify the %f or %e to include a precision value, eg, ... In this case, the use of %.2f limits the output to two decimal places, and the output now looks like
Smith College
science.smith.edu › ~jfrankli › 231f13 › 231 › format.html
Formatting in printf, in C
You can control the number of digits after the decimal point when printing a floating point value using printf. For example, printf("The value is .6lf",myDoubleNum); causes the double precision value in the variable myDoubleNum to be printed out using 10 characters including the decimal point, with 6 number characters following the decimal point.
Cplusplus
cplusplus.com › forum › beginner › 222271
How to set a result to 2 decimal places - C++ Forum
I started to do a simpler version of that but 100.01 becomes 100 and 1 integer parts and prints 100.1 so you have to handle that aggravation. I think all you need is if ( (int)val - val < 10) cout <<'0' ; //insert extra zero padding.
Top answer 1 of 16
489
If you just want to round the number for output purposes, then the "%.2f" format string is indeed the correct answer. However, if you actually want to round the floating point value for further computation, something like the following works:
#include <math.h>
float val = 37.777779;
float rounded_down = floorf(val * 100) / 100; /* Result: 37.77 */
float nearest = roundf(val * 100) / 100; /* Result: 37.78 */
float rounded_up = ceilf(val * 100) / 100; /* Result: 37.78 */
Notice that there are three different rounding rules you might want to choose: round down (ie, truncate after two decimal places), rounded to nearest, and round up. Usually, you want round to nearest.
As several others have pointed out, due to the quirks of floating point representation, these rounded values may not be exactly the "obvious" decimal values, but they will be very very close.
For much (much!) more information on rounding, and especially on tie-breaking rules for rounding to nearest, see the Wikipedia article on Rounding.
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Using %.2f in printf. It only print 2 decimal points.
Example:
printf("%.2f", 37.777779);
Output:
37.77
Cprogramming
cboard.cprogramming.com › c-programming › 84575-displaying-numbers-two-decimal-places-using-printf.html
Displaying numbers to two decimal places using printf
>does it look like I have used it right? No, isdigit takes an int/char. You're passing it a float (float input). If you want to validate with isdigit, first use fgets to read into a string, then use strtod to convert to a float or double after checking for valid input.
Cplusplus
cplusplus.com › forum › beginner › 222475
Rounding offto 2 decimal points - C++ Forum
For rounding methods, check out http://www.cplusplus.com/forum/articles/3638/ (and its follow-up http://www.cplusplus.com/articles/213hAqkS/). Whew. Hope this helps! ... Round to nearest integer, rounding halfway cases away from zero: std::round std::lround std::llround http://en.cppreference.com/w/cpp/numeric/math/round Also see: std::nearbyint http://en.cppreference.com/w/cpp/numeric/math/nearbyint std::rint std::lrint std::llrint http://en.cppreference.com/w/cpp/numeric/math/rint
GeeksforGeeks
geeksforgeeks.org › c language › g-fact-41-setting-decimal-precision-in-c
Setting decimal precision in C - GeeksforGeeks
January 10, 2025 - // C program to set precision in floating point numbers // using format specifier #include<stdio.h> int main() { float num = 5.48958123; // 4 digits after the decimal point printf("%0.4f", num); return 0; }
Reddit
reddit.com › r/cpp_questions › how to convert a double to a string, truncating it to only two decimals? [c++]
r/cpp_questions on Reddit: How to convert a double to a string, truncating it to only two decimals? [C++]
March 17, 2020 -
The result of the following function: calculateFinalCost() is a double
Currently, I'm using this code:
std::string toStringConsult()
{
return "\nFinal Cost: " + "$" + std::to_string(calculateFinalCost());
}However I need toStringConsult() to show the value of calculateFinalCost() truncated from, for example, 45.123321 to 45.12
What would be the simplest way to achieve this?
Thanks
Top answer 1 of 5
5
If your compiler supports C++20's std::format , you can use that. I think the result would look like this: std::string toStringConsult() { return std::format("\nFinal cost: ${.2f}", calculateFinalCost()); } or maybe it should be {:.2f}. Alternatively you can use std::ostringstream like in this guy's comment . I think the result would look like this: std::string toStringConsult() { std::ostringstream result; result << "\nFinal cost: $" << std::setprecision(2) << calculateFinalCost(); return result.str(); }
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std::snprintf() is still a reasonable option in some cases, such as not having C++20 available. std::array buffer; std::snprintf(&buffer\[0\], buffer.size(), "\\nFinal Cost: $%.2f", calculateFinalCost()); Note that though the printf family of functions work well, they can easily lead to run time errors if you are not careful. So take care to correctly match the format with the arguments, and make sure the buffer is large enough for the formatted string. This is why std::format is finally a thing. Offered for completeness. In general: avoid.
Augustana University
lovelace.augustana.edu › q2a › index.php › 1208 › how-do-round-up-double-to-decimal-places-in-printf-statement
How do I round up a double to 2 decimal places in a printf statement? - Augustana CSC Q&A
February 10, 2019 - System.out.printf ("Here is a double: %.2f" , double value or variable); · You can try something like this: double example = 0.24556; System.out.printf("Example: %.2f", example);
W3Schools
w3schools.com › c › c_data_types_dec.php
C Data Types Decimal Precision
float myFloatNum = 3.5; printf("%f\n", myFloatNum); // Default will show 6 digits after the decimal point printf("%.1f\n", myFloatNum); // Only show 1 digit printf("%.2f\n", myFloatNum); // Only show 2 digits printf("%.4f", myFloatNum); // Only ...
Facebook
facebook.com › groups › cppdev › posts › 2039166226823297
Setting output to two decimal places in C?
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Reddit
reddit.com › r/learnprogramming › [c] truncating to 2 decimal places.
r/learnprogramming on Reddit: [C] Truncating to 2 decimal places.
September 26, 2014 -
Hey there, really quick question...
How can I get my program to truncate a double to 2 decimal places NOT rounding it.
my printf statement looks like this right now:
printf("The amount entered is: %.2lf", input);Thanks.
SitePoint
sitepoint.com › .net
Forcing a number to 2 decimal places in C# - .NET - SitePoint Forums | Web Development & Design Community
July 20, 2005 - Hey guys On my website i have numbers that get calculated according to what the use types in. I need the number 2 be forced to 2 decimal places. At the moment im using Math.Round(decOne,2); that changes this: 65.231 into 65.23 but if the user types in 65 it stays 65 and doesn’t give me 65.00.