So what I am trying to do is to input String and then assign each letter to a Char array. The problem I have is that I need to implement it in a way that no matter how long the String Java knows to assign each component of the array to the corresponding letter in the String.

My code in Java:

Scanner scan = new Scanner(System.in);
System.out.println("Enter a first number ");
int x = scan.nextInt();
IntegerToString(x);
}
public static void IntegerToString(int x){
int numberOne = x;
System.out.println("This is the number: " + numberOne);
System.out.println("Now Backend needs to convert this number into a String");
String numberWord = Integer.toString(numberOne);
int lengthOf = numberWord.length();
char[] array = new char[lengthOf];
array[0] = numberWord.charAt(0);
array[1] = numberWord.charAt(1);
array[2] = numberWord.charAt(2);

I hope this makes sense. Thanks.

I'm trying to turn a string into a char array by using .toCharArray() and I thought that if I had escaped characters ("\t", or "\n", etc) in the string it would automatically get converted to one char in the char array but instead the slash and the character after it become their own characters.

Example:

StringBuilder sb = new StringBuilder();
sb.append("\t\tStuff");
char[] stuff = sb.toString().toCharArray();

If I do this, the first char in the array is \ instead of \t. Am I doing something wrong? I've tried this in an online compiler to test it out and it works there so I'm not sure what could be going on.

Here is what I'm seeing