I've recently began learning Python, and I'm trying to write a simple Q&A program. I want the user to be able to insert input and have it be compared to keys in a dictionary, and whichever key that has the most words in common with the question will be activated, and the answer will be printed. Here is my current code: from tkinter import * from tkinter import ttk from tkinter import messagebox

root = Tk()
root.geometry('{}x{}'.format(666, 666))
var = StringVar()
vara = StringVar()

resp = {'What programming language was this written in?': 'This program was written using Python 3.5. Python is a widely used high-level, general-purpose, dynamic programming language. Its syntax enables programmers to write code in fewer lines than more complex languages like Java and C++.', 'Who invented computer programming?': 'Charles Babbage is universally accepted as the father of computer programming due to his creation of the analytical engine. While computers were not created until a century beyond his invention, the analytical engine used an identical concept for input/output commands.', 'What coding language was used to create Windows OS?': 'Windows 7, 8, 8.1 and 10 operate on C++ and C# almost exclusively. Because these are lower-level languages, the programmer has greater control over the computer itself, enabling them to do many amazing things.'}


label = Message( root, textvariable=var,      relief=RAISED)
labelfont = ('times', 20, 'bold')

def callback():

    parabel = Tk()
    parabel.minsize(600, 400)
    parabel.maxsize(600,400)
    parabel.title("BonneyBot")

    pLabel = Label(parabel, text = "Welcome to     BonneyBot.").pack(side = TOP)
    pLabel1 = Label(parabel, text = "Ask a question about programming!").pack()
    pEntry1 = ttk.Entry(parabel, textvariable = vara)
    pEntry1.pack(side='top')

    def response():
        if pEntry1.get() in resp.keys():
                messagebox.showinfo('file',  resp[pEntry1.get()])
        else:
                messagebox.showwarning('error', 'I did not understand the question. Please ask again.')
        
            
    
    ttk.Button(parabel, text = "ASK AWAY!",     command=response).pack()
    
    


widget = Label(root, text="Welcome to my graduation project!\n This is a simple Q&A program created\n by Devin intended to assist individuals\n curious about computer programming.\n Click start to begin!")
widget.config(bg='lightblue', fg='red')
widget.config(font=labelfont)
widget.config(height=3, width=20)
widget.pack(expand=YES, fill=BOTH)
var.set("Let's get started!")


MyButton1 = Button(root, text="START", command=callback)
MyButton1.pack()



label.pack()
root.mainloop()

What could I add to compare the words in common with the user input with the keys in the dictionary? Thanks!

Here is the scenario:

dict1 = { A : 1 , B : 3 , C: 0 }

dict2 = {C : 1, D : 2 , A : 1, B : 3 }

dict3 = {E : 1, B : 3, A : 1, C : 0}

Assuming dict1 is the baseline that subsequent dictionaries (dict2, dict3) need to be compared against, I am thinking about codes that check if dict 2 >= dict1 or dict 3 >= dict1:

1. I understand dictionary is unordered, so does that mean that the dictionary can be compared without sort method?

2. does extra elements in dict2 and dict3 affect the comparison operation, should my code factor extra elements?

3. i think the best way would be something similar to cmp() in Python2, is any function similar to cmp() for dictionary? I don't intend to import any outside library, but okay with builtin modules.

I would like to some pointers to solve the question. Thank you for the help in advance!