compare two json objects and get difference python

How to compare two JSON objects with the same elements in a different order equal?

stackoverflow.com › questions › 25851183 › how-to-compare-two-json-objects-with-the-same-elements-in-a-different-order-equa

If you want two objects with the same elements but in a different order to compare equal, then the obvious thing to do is compare sorted copies of them - for instance, for the dictionaries represented by your JSON strings a and b:

import json

a = json.loads("""
{
    "errors": [
        {"error": "invalid", "field": "email"},
        {"error": "required", "field": "name"}
    ],
    "success": false
}
""")

b = json.loads("""
{
    "success": false,
    "errors": [
        {"error": "required", "field": "name"},
        {"error": "invalid", "field": "email"}
    ]
}
""")

>>> sorted(a.items()) == sorted(b.items())
False

... but that doesn't work, because in each case, the "errors" item of the top-level dict is a list with the same elements in a different order, and sorted() doesn't try to sort anything except the "top" level of an iterable.

To fix that, we can define an ordered function which will recursively sort any lists it finds (and convert dictionaries to lists of (key, value) pairs so that they're orderable):

def ordered(obj):
    if isinstance(obj, dict):
        return sorted((k, ordered(v)) for k, v in obj.items())
    if isinstance(obj, list):
        return sorted(ordered(x) for x in obj)
    else:
        return obj

If we apply this function to a and b, the results compare equal:

>>> ordered(a) == ordered(b)
True

Answer from Zero Piraeus on Stack Overflow

Stack Overflow

stackoverflow.com › questions › 25851183 › how-to-compare-two-json-objects-with-the-same-elements-in-a-different-order-equa

python - How to compare two JSON objects with the same elements in a different order equal? - Stack Overflow

Top answer

1 of 12

225

If you want two objects with the same elements but in a different order to compare equal, then the obvious thing to do is compare sorted copies of them - for instance, for the dictionaries represented by your JSON strings a and b:

import json

a = json.loads("""
{
    "errors": [
        {"error": "invalid", "field": "email"},
        {"error": "required", "field": "name"}
    ],
    "success": false
}
""")

b = json.loads("""
{
    "success": false,
    "errors": [
        {"error": "required", "field": "name"},
        {"error": "invalid", "field": "email"}
    ]
}
""")

>>> sorted(a.items()) == sorted(b.items())
False

... but that doesn't work, because in each case, the "errors" item of the top-level dict is a list with the same elements in a different order, and sorted() doesn't try to sort anything except the "top" level of an iterable.

To fix that, we can define an ordered function which will recursively sort any lists it finds (and convert dictionaries to lists of (key, value) pairs so that they're orderable):

def ordered(obj):
    if isinstance(obj, dict):
        return sorted((k, ordered(v)) for k, v in obj.items())
    if isinstance(obj, list):
        return sorted(ordered(x) for x in obj)
    else:
        return obj

If we apply this function to a and b, the results compare equal:

>>> ordered(a) == ordered(b)
True

2 of 12

94

Another way could be to use json.dumps(X, sort_keys=True) option:

import json
a, b = json.dumps(a, sort_keys=True), json.dumps(b, sort_keys=True)
a == b # a normal string comparison

This works for nested dictionaries and lists.

Stack Overflow

stackoverflow.com › questions › 17607640 › comparing-two-json-objects-irrespective-of-the-sequence-of-elements-in-them

python - Comparing two JSON objects irrespective of the sequence of elements in them - Stack Overflow

Top answer

1 of 4

31

You can use jsondiff

from jsondiff import diff
diff(json1, json2)

... assuming you have json1 and json2 loaded with the json entries from your example (and by the way, you have a missing comma after the 'sex' entry).

2 of 4

23

you can use deepdiff with ignore_order=True

from deepdiff import DeepDiff
t1 = {1:1, 2:2, 3:3, 4:{"a":"hello", "b":[1, 2, 3]}}
t2 = {1:1, 2:2, 3:3, 4:{"a":"hello", "b":[1, 3, 2, 3]}}
ddiff = DeepDiff(t1, t2, ignore_order=True)
print (ddiff)
{}

Discussions

Diff two large JSON array or objects

Yes Firstly you have to load json data in python dictionary using json module/package After that jsondiff module/package help you check different This module/package also compare list,set,etc.👌 If will return empty dictionary {} if there is no different👍 import jsondiff oldJson = {1:"a",2:"b",3:"c"} newJson = {1:1,4:4} r = jsondiff.diff(oldJson,newJson) if r : print(r) else: print("404,No Different Found!") Output: {1: 1, 4: 4, delete: [2, 3]} 😀 json.diff take 1st arg oldJson means from which we are checking different & 2nd newJson. There are 3 syntax 🎲 : compact ( default ) Any Change in Value of key & new insrted key will display normaly symmetric Inserted & delete show differently change show normally explicit 👀 It is detailed Inserted Deleted Changed Show differently import jsondiff oldJson = {1:"a",2:"b",3:"c"} newJson = {1:1,4:4} r = jsondiff.diff(oldJson,newJson,syntax="explicit") if r: print(r) else: print("404,No Different Found!") Output : {insert: {4: 4}, update: {1: 1}, delete: [2, 3]} 😃 Finally 🔥,Now you doubt about how to access them You can access them using symbols eg. r[jsondiff.symbols.insert] OR from jsondiff import symbols r[symbols.insert] There are some other symbols which use in different compare like list,set, etc Note : if you try using insert in compact & update in compact & symmetric then you will get KeyError 😔 because those not exist there import jsondiff from jsondiff import symbols oldJson = {1:"a",2:"b",3:"c"} newJson = {1:1,4:4} r = jsondiff.diff(oldJson,newJson,syntax="explicit") if r: print("Deleted keys are ",r[symbols.delete]) else: print("404,No Different Found!") Output : Deleted keys are [2, 3] 🥳 Thanks for reading 😂 More on reddit.com

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