Assuming you're on at least 3.2, there's a built in for this:

int.from_bytes( bytes, byteorder, *, signed=False )

...

The argument bytes must either be a bytes-like object or an iterable producing bytes.

The byteorder argument determines the byte order used to represent the integer. If byteorder is "big", the most significant byte is at the beginning of the byte array. If byteorder is "little", the most significant byte is at the end of the byte array. To request the native byte order of the host system, use sys.byteorder as the byte order value.

The signed argument indicates whether two’s complement is used to represent the integer.

## Examples:
int.from_bytes(b'\x00\x01', "big")                         # 1
int.from_bytes(b'\x00\x01', "little")                      # 256

int.from_bytes(b'\x00\x10', byteorder='little')            # 4096
int.from_bytes(b'\xfc\x00', byteorder='big', signed=True)  #-1024
Answer from Peter DeGlopper on Stack Overflow
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SCADACore
scadacore.com › home › tools › programming calculators › online hex converter
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geeksforgeeks.org › python › how-to-convert-bytes-to-int-in-python
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tutorialspoint.com › article › how-to-convert-bytes-to-int-in-python
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danielle-honig.com › int-array-converter.html
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September 29, 2021 - def bytes_to_int(bytes): result = 0 for b in bytes: result = result * 256 + int(b) return result def int_to_bytes(value, length): result = [] for i in range(0, length): result.append(value >> (i * 8) & 0xff) result.reverse() return result
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stackoverflow.com › questions › 9581530 › converting-from-byte-to-int-in-java
type conversion - Converting from byte to int in Java - Stack Overflow
I have generated a secure random number, and put its value into a byte. Here is my code. SecureRandom ranGen = new SecureRandom(); byte[] rno = new byte[4]; ranGen.nextBytes(rno); int i = rno[0].
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byte[] bytes = [0, 0, 0, 25]; // ... // Output: int: 25 · In this example, the GetBytes(Int32) method of the BitConverter class is called to convert an int to an array of bytes....
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