Using Math.round() will round the float to the nearest integer.

Answer from tw39124 on Stack Overflow
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Using Math.round() will round the float to the nearest integer.

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Actually, there are different ways to downcast float to int, depending on the result you want to achieve: (for int i, float f)

  • round (the closest integer to given float)

    i = Math.round(f);
      f =  2.0 -> i =  2 ; f =  2.22 -> i =  2 ; f =  2.68 -> i =  3
      f = -2.0 -> i = -2 ; f = -2.22 -> i = -2 ; f = -2.68 -> i = -3
    

    note: this is, by contract, equal to (int) Math.floor(f + 0.5f)

  • truncate (i.e. drop everything after the decimal dot)

    i = (int) f;
      f =  2.0 -> i =  2 ; f =  2.22 -> i =  2 ; f =  2.68 -> i =  2
      f = -2.0 -> i = -2 ; f = -2.22 -> i = -2 ; f = -2.68 -> i = -2
    
  • ceil/floor (an integer always bigger/smaller than a given value if it has any fractional part)

    i = (int) Math.ceil(f);
      f =  2.0 -> i =  2 ; f =  2.22 -> i =  3 ; f =  2.68 -> i =  3
      f = -2.0 -> i = -2 ; f = -2.22 -> i = -2 ; f = -2.68 -> i = -2
    
    i = (int) Math.floor(f);
      f =  2.0 -> i =  2 ; f =  2.22 -> i =  2 ; f =  2.68 -> i =  2
      f = -2.0 -> i = -2 ; f = -2.22 -> i = -3 ; f = -2.68 -> i = -3
    

For rounding positive values, you can also just use (int)(f + 0.5), which works exactly as Math.Round in those cases (as per doc).

You can also use Math.rint(f) to do the rounding to the nearest even integer; it's arguably useful if you expect to deal with a lot of floats with fractional part strictly equal to .5 (note the possible IEEE rounding issues), and want to keep the average of the set in place; you'll introduce another bias, where even numbers will be more common than odd, though.

See

http://mindprod.com/jgloss/round.html

http://docs.oracle.com/javase/6/docs/api/java/lang/Math.html

for more information and some examples.

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Baeldung
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October 17, 2024 - In this article, weโ€™ll look at various methods for converting a float to an int in Java, along with practical examples that demonstrate when each approach is appropriate.
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(Java) Need to convert from float to integer to floats for displaying a percentage. I have tried googling, yet can't seem to wrap my head around it
[1] initial value as a float, and then [2] convert it to an integer, [3] multiply by 1000 If you follow these steps exactly, you will lose information. Converting a float to an int drops the fraction component, so you have to do step 3 before step 2. More on reddit.com
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The first and second one will cause ... both integers. 2014-07-26T01:00:06.473Z+00:00 ... @user3002853 read about boxed types vs primitives. docs.oracle.com/javase/tutorial/java/data/autoboxing.html 2014-10-06T12:28:40.567Z+00:00 ... Adam R. Turner ยท Adam R. Turner Over a year ago ยท in Android Studio at least, the compiler will complain about incompatible types trying to do this. 2019-01-07T00:10:04.823Z+00:00 ... You shouldn't use float unless you ... More on stackoverflow.com
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September 20, 2016 - So... 1.2345 * 10 = 12.345 convert to int = 12 convert to float = 12 (float) divide by 10 = 1.2 ... You're right I did mess up my multiplying numbers. He wants it so that when it is in the final float form there is still one decimal. And I need it to be able to round up.
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