No, you can't cast Integer to Long, even though you can convert from int to long. For an individual value which is known to be a number and you want to get the long value, you could use:

Number tmp = getValueByReflection(inv.var1(), classUnderTest, runtimeInstance);
Long value1 = tmp.longValue();

For arrays, it will be trickier...

Use the following: Long.valueOf(int);.

Here are three ways to do it:

Long l = 123L;
Integer correctButComplicated = Integer.valueOf(l.intValue());
Integer withBoxing = l.intValue();
Integer terrible = (int) (long) l;

All three versions generate almost identical byte code:

 0  ldc2_w <Long 123> [17]
 3  invokestatic java.lang.Long.valueOf(long) : java.lang.Long [19]
 6  astore_1 [l]
 // first
 7  aload_1 [l]
 8  invokevirtual java.lang.Long.intValue() : int [25]
11  invokestatic java.lang.Integer.valueOf(int) : java.lang.Integer [29]
14  astore_2 [correctButComplicated]
// second
15  aload_1 [l]
16  invokevirtual java.lang.Long.intValue() : int [25]
19  invokestatic java.lang.Integer.valueOf(int) : java.lang.Integer [29]
22  astore_3 [withBoxing]
// third
23  aload_1 [l]
// here's the difference:
24  invokevirtual java.lang.Long.longValue() : long [34]
27  l2i
28  invokestatic java.lang.Integer.valueOf(int) : java.lang.Integer [29]
31  astore 4 [terrible]