>>> str(42)
'42'
>>> int('42')
42
Links to the documentation:
int()str()
str(x) converts any object x to a string by calling x.__str__(), or repr(x) if x doesn't have a __str__() method.
Cannot use str() to convert an int to a string.
How do I get an integer as a string?
python - Short way to convert string to int - Stack Overflow
Python: Convert a string to an integer - Stack Overflow
How to check if a string is an integer in Python?
To check if a string represents an integer, you can use the str.isdigit() method if the string contains only digits and no sign (+/-) or decimals:
string = "42"
if string.isdigit():
print("The string is an integer.")
else:
print("The string is not an integer.")For strings that may include a sign (+/-), you can use a more robust method:
string = "-42"
try:
int(string)
print("The string is an integer.")
except ValueError:
print("The string is not an integer.")What should I do if the string contains a decimal number and I want to convert it to an integer?
First, convert the string to a float using the float() function, then cast it to an integer using int(). For example:
decimal_string = "13.5"
converted_integer = int(float(decimal_string))
print(converted_integer) # Output: 13Okay, so I had a crash course in Python a looooong time ago, and that's all the prior experience I have with it. I'm starting to dabble in it again, playing around with it to make a text-based game.
In this game, you have stats - Speed, Health, etc etc. Each of these is a number (an int).
I am trying to define a function names statdisplay() so that when I call on it, it prints out your stats. So, if you have a Speed of 1, and the max Speed you can increase that stat to is 5, one of the printed lines would be:
Speed: 1 / 5
This was my ORIGINAL code:
print("\nHealth: " + healthstat + " / " + maxhealth)
print("\nHunger: " + hungerstat + " / " + maxhunger)
print("\nStalking Skill: " + stalkingstat + " / 5")
print("\nHunting Skill: " + huntingstat + " / 5")
print("\nSpeed: " + speedstat + " / 5")
print("\nStrength: " + speedstat + " / 5")But then I got the following error:
TypeError: can only concatenate str (not "int") to str
So I mentally facepalmed myself and looked up how to convert an int to a string, and I keep reading that you can use the str() function (I know there are other ways, but I'm taking baby steps here trying to jog my memory on how everything works before I go doing everything by what's deemed "most appropriate").
This is my NEW code with that in mind:
print("\nHealth: " + str(healthstat) + " / " + maxhealth)
print("\nHunger: " + str(hungerstat) + " / " + maxhunger)
print("\nStalking Skill: " + str(stalkingstat) + " / 5")
print("\nHunting Skill: " + str(huntingstat) + " / 5")
print("\nSpeed: " + str(speedstat) + " / 5")
print("\nStrength: " + str(speedstat) + " / 5")...and yet I am still getting the following error:
TypeError: can only concatenate str (not "int") to str
I can't seem to figure out what's wrong. I do not have the str() function defined as anything else. str() also doesn't seem to come from any special libraries that I'd need to import, but maybe I'm wrong there (I tried to look it up)... the only import I currently have is "import random".
My only other thought is that maybe it's a Google Colab thing, as that's where I'm currently running my code since this wasn't anything serious and I tend to go between two different computers.
Any help would be much appreciated!
Edit: accidentally had the new code in both code boxes.
x = 10
y = str(x)
print(y)
Why is 10.0 printed
my_input = int(my_input)
There is no shorter way than using the int function (as you mention)
Maybe you were hoping for something like my_number = my_input.to_int. But it is not currently possible to do it natively. And funny enough, if you want to extract the integer part from a float-like string, you have to convert to float first, and then to int. Or else you get ValueError: invalid literal for int().
The robust way:
my_input = int(float(my_input))
For example:
>>> nb = "88.8"
>>> int(nb)
Traceback (most recent call last):
File "<stdin>", line 1, in <module>
ValueError: invalid literal for int() with base 10: '88.8'
>>> int(float(nb))
88
In this case you do have a way to avoid try/except, although I wouldn't recommend it (assuming your input string is named s, and you're in a function that must return something):
xs = s.strip()
if xs[0:1] in '+-': xs = xs[1:]
if xs.isdigit(): return int(s)
else: ...
the ... part in the else is where you return whatever it is you want if, say, s was 'iamnotanumber', '23skidoo', empty, all-spaces, or the like.
Unless a lot of your input strings are non-numbers, try/except is better:
try: return int(s)
except ValueError: ...
you see the gain in conciseness, and in avoiding the fiddly string manipulation and test!-)
I see many answers do int(s.strip()), but that's supererogatory: the stripping's not needed!
>>> int(' 23 ')
23
int knows enough to ignore leading and trailing whitespace all by itself!-)
import re
int(re.sub(r'[^\d-]+', '', your_string))
This will strip everything except for numbers and the "-" sign. If you can be sure that there won't be ever any excess characters except for whitespace, use gruszczy's method instead.
here is the code:
integer = 170
string = 'sadsad'
print(integer+int(string))
ps thx
Hello Everyone,
I was wondering if it's possible to get the input of a string from the user and convert it into an integer later on. I'm asking this as the code I'm working on requires a string input from the user of what service they'd like. I later had to add up the totals of the services and wondered if once the choice was selected or inputted then if it would become a number that later adds up to the total cost if multiple services are inputted.