Assuming this array may or may not be redundantly nested and you're unsure of how deep it goes, this should flatten it for you:

function array_flatten($array) { 
  if (!is_array($array)) { 
    return FALSE; 
  } 
  $result = array(); 
  foreach ($array as value) { 
    if (is_array($value)) { 
      $result = array_merge($result, array_flatten($value)); 
    } 
    else { 
      $result[value; 
    } 
  } 
  return $result; 
} 

The best way would be to manage your data structure as an object from the start if you have the ability:

$a = (object) array( ... ); $a->prop = $value; //and so on

But the quickest way would be the approach supplied by @CharlieS, using json_decode(json_encode($a)).

You could also run the array through a recursive function to accomplish the same. I have not benchmarked this against the json approach but:

function convert_array_to_obj_recursive($a) {
    if (is_array($a) ) {
        foreach(k => $v) {
            if (is_integer($k)) {
                // only need this if you want to keep the array indexes separate
                // from the object notation: eg. a['index'][$k] = convert_array_to_obj_recursive($v);
            }
            else {
                k] = convert_array_to_obj_recursive($v);
            }
        }

        return (object) $a;
    }

    // else maintain the type of $a
    return $a; 
}

Hope that helps.

EDIT: json_encode + json_decode will create an object as desired. But, if the array was numerical or mixed indexes (eg. array('a', 'b', 'foo'=>'bar') ), you will not be able to reference the numerical indexes with object notation (eg. o[1]). the above function places all the numerical indexes into the 'index' property, which is itself a numerical array. so, you would then be able to do $o->index[1]. This keeps the distinction of a converted array from a created object and leaves the option to merge objects that may have numerical properties.

Use array_map() or array_column()

// (PHP 4 >= 4.0.6, PHP 5, PHP 7)
print_r(array_map(function($a){return $a['sku'];}, $array));

// (PHP 5 >= 5.5.0, PHP 7)
print_r(array_column($array,'sku'));  

you new array will be

$new_array = array_map(function($a){return $a['sku'];}, $array);

$new_array = array_column($array,'sku');

This is a blanket statement on how to get your desired array :

$desired_array = array(array("0"=>"A"), array("0"=>"B"), array("0"=>"C"));

However, dynamically, you could do the following :

//Assume $original_array = array("0"=>"A", "1"=>"B", "2"=>"C");

$desired_array = array(); // New Array
for($i = 0; $i < count($original_array); $i++){ // Loop over all elements in original array
array_push($desired_array, array("0"=>$original_array[$i])); // Place each valueable as an array in new desired array
}

i don't know what you realy want to do .... maybe this could you help

<?php
   $new = array();
   foreach($oldArr as $arr) {
        $new[$arr['created']] = $arr;

   }
   print_r($new);
?>

You can use as follows :

$newArray = array();
foreach($arrayData as $key => $value) {
    foreach($value as $key2 => $value2) {
        $newArray[$key2] = $value2;
    }
}

Where $arrayData is your DB data array and $newArray will be the result.