Django versions 1.8 and later:
You should use get_fields():
[f.name for f in MyModel._meta.get_fields()]
The get_all_field_names() method is deprecated starting from Django
1.8 and will be removed in 1.10.
The documentation page linked above provides a fully backwards-compatible implementation of get_all_field_names(), but for most purposes the previous example should work just fine.
Django versions before 1.8:
model._meta.get_all_field_names()
That should do the trick.
That requires an actual model instance. If all you have is a subclass of django.db.models.Model, then you should call myproject.myapp.models.MyModel._meta.get_all_field_names()
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Django versions 1.8 and later:
You should use get_fields():
[f.name for f in MyModel._meta.get_fields()]
The get_all_field_names() method is deprecated starting from Django
1.8 and will be removed in 1.10.
The documentation page linked above provides a fully backwards-compatible implementation of get_all_field_names(), but for most purposes the previous example should work just fine.
Django versions before 1.8:
model._meta.get_all_field_names()
That should do the trick.
That requires an actual model instance. If all you have is a subclass of django.db.models.Model, then you should call myproject.myapp.models.MyModel._meta.get_all_field_names()
As most of answers are outdated I'll try to update you on Django 2.2 Here posts- your app (posts, blog, shop, etc.)
1) From model link: https://docs.djangoproject.com/en/stable/ref/models/meta/
from posts.model import BlogPost
all_fields = BlogPost._meta.fields
#or
all_fields = BlogPost._meta.get_fields()
Note that:
all_fields=BlogPost._meta.get_fields()
Will also get some relationships, which, for ex: you can not display in a view.
As in my case:
Organisation._meta.fields
(<django.db.models.fields.AutoField: id>, <django.db.models.fields.DateField: created>...
and
Organisation._meta.get_fields()
(<ManyToOneRel: crm.activity>, <django.db.models.fields.AutoField: id>, <django.db.models.fields.DateField: created>...
2) From instance
from posts.model import BlogPost
bp = BlogPost()
all_fields = bp._meta.fields
3) From parent model
Let's suppose that we have Post as the parent model and you want to see all the fields in a list, and have the parent fields to be read-only in Edit mode.
from django.contrib import admin
from posts.model import BlogPost
@admin.register(BlogPost)
class BlogPost(admin.ModelAdmin):
all_fields = [f.name for f in Organisation._meta.fields]
parent_fields = BlogPost.get_deferred_fields(BlogPost)
list_display = all_fields
read_only = parent_fields
You can convert it into string by using JSON and store it as string.
For example,
In [3]: json.dumps([[1, 3, 4], [4, 2, 6], [8, 12, 3], [3, 3, 9]])
Out[3]: '[[1, 3, 4], [4, 2, 6], [8, 12, 3], [3, 3, 9]]'
You can add a method into your class to convert it automatically for you.
import json
class Foobar(models.Model):
foo = models.CharField(max_length=200)
def set_foo(self, x):
self.foo = json.dumps(x)
def get_foo(self):
return json.loads(self.foo)
If you're using Django 1.9 or above, and you use postgresql, there is a new class called JSONField, you should use it instead. Here is a link to it
There is a good talk about PostgreSQL JSONs and Arrays on youtube. Watch it, it has very good information.
If you're on Django 1.10 or newer AND Postgres as your database, you can use ArrayField. It's better to use than django-taggit or other alternatives, as it's native to the Django framework.
https://docs.djangoproject.com/en/3.1/ref/contrib/postgres/fields/#arrayfield
from django.db import models
from django.contrib.postgres.fields import ArrayField
class ChessBoard(models.Model):
board = ArrayField(
ArrayField(
models.CharField(max_length=10, blank=True),
size=8,
),
size=8,
)
If you're on Django 3.1 or newer they've added support for JSONField with most database backends (MariaDB 10.2.7+, MySQL 5.7.8+, Oracle, PostgreSQL, and SQLite 3.9.0+). You can use this to store your Array!
https://docs.djangoproject.com/en/3.1/ref/models/fields/#jsonfield
from django.db import models
class ChessBoard(models.Model):
list_of_pieces = models.JSONField()
I have a model TutorProfile and I wanted it to have an attribute like a list for storing the names of students, so that I will know who are the students that has successfully booked a lesson to a certain tutor. Can someone guide me with this?
this my model
class TutorProfile(models.Model):
user = models.OneToOneField(User, on_delete=models.CASCADE, related_name='tutor_profile')
profile_headline = models.CharField(max_length=200, null=True)
bio = models.TextField(max_length=500, blank=True, null=True)
is_validated = models.BooleanField(default=False)
hourly_rate = models.DecimalField(max_digits=8, decimal_places=2, default=0)
students = models.ListField()