Hey guys, I tried to implement Doubly Linked List in C programming, I implemented Inserting a node at any given position (using head as a local variable and not making it global), the main issue I'm Facing is , the program is just executing and not printing output, I sat for 2 hrs and tried to figure out the error, but still not able to find, I would be grateful, if you guys could help me out

#include<stdio.h>
#include<stdlib.h>

// Doubly Linked List Implementation
struct Node{
	int data;
	struct Node* next;
	struct Node* prev;
};

int main(){
	struct Node* head = NULL;

	Insert(&head,2,1);
	Insert(&head,3,2);
	Insert(&head,4,1);
	Insert(&head,5,2);
	Insert(&head,6,5);

	Print(head);// it's just getting executed, and not showing any output 
	return 0;
}


//Function for creating a Node
struct Node* GetNewNode(int x){
	struct Node* newNode = (struct Node*)malloc(sizeof(struct Node));
	newNode->data = x;
	newNode->prev = NULL;
	newNode->next = NULL;
	return newNode;
}

//Inserting a node in nth position
void Insert(struct Node** head, int x, int n){
	struct Node* newNode = GetNewNode(x);
	if(n==1){
		if(*head==NULL){
			*head = newNode;
			return;
		}
		else{
			newNode->next = *head;
		    (*head)->prev = newNode;
		    *head = newNode;
		    return;
		}
		
	}
	struct Node* temp1;
	temp1 = *head;
	for(int i=1;i<n-1;i++){
		temp1= temp1->next;
	}
	//temp1 is pointing to (n-1)th node
	struct Node* temp2 = temp1->next;
	//temp2 is pointing to nth node
	if(temp2->next == NULL){
		temp2->next = newNode;
		newNode->prev = temp2;
		return;
	}
	
	temp1->next = newNode;
	newNode->prev = temp1;
	newNode->next = temp2;
	temp2->prev = newNode;
}

// Function for Printing the whole linked list
void Print(struct Node* node){
	while(node!=NULL){
		printf("%d ",node->data);
		node = node->next;
	}
}