You should assign an array of char pointers, and then, for each pointer assign enough memory for the string:
char **orderedIds;
orderedIds = malloc(variableNumberOfElements * sizeof(char*));
for (int i = 0; i < variableNumberOfElements; i++)
orderedIds[i] = malloc((ID_LEN+1) * sizeof(char)); // yeah, I know sizeof(char) is 1, but to make it clear...
Seems like a good way to me. Although you perform many mallocs, you clearly assign memory for a specific string, and you can free one block of memory without freeing the whole "string array"
Answer from MByD on Stack OverflowYou should assign an array of char pointers, and then, for each pointer assign enough memory for the string:
char **orderedIds;
orderedIds = malloc(variableNumberOfElements * sizeof(char*));
for (int i = 0; i < variableNumberOfElements; i++)
orderedIds[i] = malloc((ID_LEN+1) * sizeof(char)); // yeah, I know sizeof(char) is 1, but to make it clear...
Seems like a good way to me. Although you perform many mallocs, you clearly assign memory for a specific string, and you can free one block of memory without freeing the whole "string array"
char **orderIds;
orderIds = malloc(variableNumberOfElements * sizeof(char*));
for(int i = 0; i < variableNumberOfElements; i++) {
orderIds[i] = malloc((ID_LEN + 1) * sizeof(char));
strcpy(orderIds[i], your_string[i]);
}
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Okay so basically I have a function that takes in a string and counts the lowercase tokens in it. I need to make a function that then returns an array of the lowercase tokens. I would need to use malloc to allocate enough memory for such array but I don’t know how to go about doing so.
Once the array is allocated how would I put the token strings into the array?
Any help is appreciated thank you
NOTE: My examples are not checking for NULL returns from malloc()... you really should do that though; you will crash if you try to use a NULL pointer.
First you have to create an array of char pointers, one for each string (char *):
char **array = malloc(totalstrings * sizeof(char *));
Next you need to allocate space for each string:
int i;
for (i = 0; i < totalstrings; ++i) {
array[i] = (char *)malloc(stringsize+1);
}
When you're done using the array, you must remember to free() each of the pointers you've allocated. That is, loop through the array calling free() on each of its elements, and finally free(array) as well.
The common idiom for allocating an N by M array of any type T is
T **a = malloc(N * sizeof *a);
if (a)
for (i = 0; i < N; i++)
a[i] = malloc(M * sizeof *a[i]);
As of the 1989 standard, you don't need to cast the result of malloc, and in fact doing so is considered bad practice (it can suppress a useful diagnostic if you forget to include stdlib.h or otherwise don't have a prototype for malloc in scope). Earlier versions of C had malloc return char *, so the cast was necessary, but the odds of you having to work with a pre-1989 compiler are pretty remote at this point. C++ does require the cast, but if you're writing C++ you should be using the new operator.
Secondly, note that I'm applying the sizeof operator to the object being allocated; the type of the expression *a is T *, and the type of *a[i] is T (where in your case, T == char). This way you don't have to worry about keeping the sizeof expression in sync with the type of the object being allocated. IOW, if you decide to use wchar instead of char, you only need to make that change in one place.
I need a little help with a problem. Just a little guidance in the logic behind solving a problem.
I have to create a program that keeps asking for a string input, and storing it in an array, until a user inputs the string "quit". The only thing I can assume, is that the string will be no longer than 100 chars, but there is no limit on how many strings a user might input.
I think I would have do to this in a while loop to keep asking for an input, and then use strcmp() to see when a person enters "quit" in order to break the loop.
My problem is, I'm not too sure how to dynamically allocate an array.
You can allocate an array of arbitrary length with malloc() (it's like "new" in Java), and make it grow or shrink with realloc().
You have to remember to free the memory with free() as in C there is not garbarage collector.
Check: http://www.gnu.org/software/libc/manual/html_node/Memory-Allocation.html#Memory-Allocation
Edit:
#include <stdlib.h>
#include <string.h>
int main(){
char * string;
// Lets say we have a initial string of 8 chars
string = malloc(sizeof(char) * 9); // Nine because we need 8 chars plus one \0 to terminate the string
strcpy(string, "12345678");
// Now we need to expand the string to 10 chars (plus one for \0)
string = realloc(string, sizeof(char) * 11);
// you can check if string is different of NULL...
// Now we append some chars
strcat(string, "90");
// ...
// at some point you need to free the memory if you don't want a memory leak
free(string);
// ...
return 0;
}
Edit 2: This is the sample for allocate and expand an array of pointers to chars (an array of strings)
#include <stdlib.h>
int main(){
// Array of strings
char ** messages;
char * pointer_to_string_0 = "Hello";
char * pointer_to_string_1 = "World";
unsigned size = 0;
// Initial size one
messages = malloc(sizeof(char *)); // Note I allocate space for 1 pointer to char
size = 1;
// ...
messages[0] = pointer_to_string_0;
// We expand to contain 2 strings (2 pointers really)
size++;
messages = realloc(messages, sizeof(char *) * size);
messages[1] = pointer_to_string_1;
// ...
free(messages);
// ...
return 0;
}
Consider creating apropriate types suitable for you problem. For example, you can create a struct holding a pointer and sn integer length to represent the dynamic arrays.