All Java objects are dynamically allocated. You're always passing around references to them. This is how the language is designed. When you do:
CopyClassA obj = new ClassA();
Then the object is allocated on the heap and a reference to it is stored on the stack (assuming that's inside a method, of course). What this means is that you can always pass objects about without worrying about where they are stored.
Answer from Donal Fellows on Stack OverflowAll Java objects are dynamically allocated. You're always passing around references to them. This is how the language is designed. When you do:
CopyClassA obj = new ClassA();
Then the object is allocated on the heap and a reference to it is stored on the stack (assuming that's inside a method, of course). What this means is that you can always pass objects about without worrying about where they are stored.
It's dynamic since you don't know when it needs allocating - you allocate upon demand.
Note also that you know how much memory that object requires, but not how much that object's members require. This may only be determinable at run time (e.g. an array of variable size).
Does Java have any limitations on dynamic memory allocation?
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Assume I am working with a large dataset like video files. Would Java be able to allocate something like an array of 1 billion integers, assuming you have enough physical memory? If so, is there anything in particular that I need to do to make sure that it will be successful?
In one line it depends on where the variable is declared.
Local variables (variables declared in method) are stored on the stack while instance and static variables are stored on the heap.*
NOTE: Type of the variable does not matter.
class A{
private int a = 10; ---> Will be allocated in heap
public void method(){
int b = 4; ----> Will be allocated in stack
}
}
primitive variables and function calls are stored in the stack. objects are stored in the heap.